[Prob] (Coupon collector)

Suppose there are n types of toys, which you are collecting one by one, with the goal of getting a complete set. When collecting toys, the toy types are random (as is sometimes the case, for example, with toys included in cereal boxes or included with kids' meals from a fast food restaurant).

Assume that each time you collect a toy, it is equally likely to be any of the n types. What is the expected number of toys needed until you have a complete set?

Solution: Let N be the number of toys needed; we want to find E(N). Our strategy will be to break up N into a sum of simpler r.v.s so that we can apply linearity. So write

N = N1 + N2 + · · · + Nn,

where N1 is the number of toys until the first toy type you haven't seen before (which is always 1, as the first toy is always a new type), N2 is the additional number of toys until the second toy type you haven't seen before, and so forth.

with

相关推荐
初心未改HD2 天前
机器学习之朴素贝叶斯分类器详解
人工智能·机器学习·概率论
the sun344 天前
概率论:二维随机变量、随机变量组合函数的分布求解
概率论
初心未改HD6 天前
AI应用开发之概率论与贝叶斯定理
人工智能·概率论
做cv的小昊9 天前
【TJU】研究生应用统计学课程笔记(8)——第四章 线性模型(4.1 一元线性回归分析)
笔记·线性代数·算法·数学建模·回归·线性回归·概率论
做cv的小昊13 天前
【TJU】研究生应用统计学课程笔记(6)——第二章 参数估计(2.4 区间估计)
人工智能·笔记·线性代数·算法·机器学习·数学建模·概率论
-cywen-13 天前
扩散模型相关的概率论基础
概率论
风落无尘14 天前
第二章《概率与生存》完整学习资料
人工智能·矩阵·概率论
风筝在晴天搁浅14 天前
用rand7()函数构造函数rand10()
概率论
上课不要睡觉了16 天前
day13统计师考试(初级)统计量与抽样分布
统计·概率论·统计师考试
the sun3417 天前
概率论:随机变量的定义、常见离散型、连续型随机变量
概率论