定义
特点
操作函数
元素查找、移除或安插
forward_list::emplace_after
**arg...**指的是元素构造函数的参数(0~N个)
cpp
#include <iostream>
#include <memory>
#include <list>
#include <forward_list>
using namespace std;
class aaa
{
public:
aaa() {
c = 666;
};
aaa(int a, int b) {
c = a + b;
};
friend std::ostream& operator << (std::ostream& o, const aaa& s) {
o << s.c;
return o;
}
private:
int c;
};
int main()
{
forward_list<aaa> t1{ {1,1},{},{2,2} };
std::copy(t1.cbegin(), t1.cend(), std::ostream_iterator<aaa>(cout, " "));
cout << endl;
t1.emplace_after(t1.before_begin(), 6, 8);
std::copy(t1.cbegin(), t1.cend(), std::ostream_iterator<aaa>(cout, " "));
cout << endl;
t1.emplace_after(t1.before_begin());
std::copy(t1.cbegin(), t1.cend(), std::ostream_iterator<aaa>(cout, " "));
cout << endl;
forward_list<int> t{ 1,2,3 };
t.emplace_after(t.before_begin(), 55);
std::copy(t.cbegin(), t.cend(), std::ostream_iterator<int>(cout, "-"));
for (;;);
}
forward_list::splice_after
<C++标准库第二版>书中介绍了c.splice_after(pos,c2,c2pos)的定义【将c2pos所指的下一个转移到pos所指的下一个】,但是示例代码却写成了
这个调用的参数顺序与函数定义的参数顺序并不一致,于是我专门验证了一下,发现这个写法的运行结果与按照函数定义的参数顺序t2.splice_after(pos2, t1, pos1);运行结果居然相同,甚至我改成了下面这样的调用,结果仍然相同
cpp
forward_list<int> t3; //定义一个空的forward_list
t3.splice_after(pos2, forward_list<int>(), pos1); //形参传入一个空的forward_list
细看了一下 splice_after函数实现发现,在没有开启DEBUG宏的情况下,其内部并没有操作形参传入的forward_list参数,而只是对迭代器pos2、pos1之右(后)所指内容进行了拼接。即常规的单向链表拼接的指针操作。
示例代码:
cpp
#include <iostream>
#include <forward_list>
using namespace std;
int main()
{
forward_list<int> t1{1,2,3,4,5};
forward_list<int> t2{ 97,98,99};
auto pos1 = t1.before_begin();
for (auto pb1 = t1.begin(); pb1 != t1.end(); ++pb1,++pos1)
{
if (*pb1 == 3)
{
break;
}
}
auto pos2 = t2.before_begin();
for (auto pb2 = t2.begin(); pb2 != t2.end(); ++pb2, ++pos2)
{
if (*pb2 == 99)
{
break;
}
}
t1.splice_after(pos2, t2, pos1);
//t2.splice_after(pos2, t1, pos1);
//forward_list<int> t3;
//t3.splice_after(pos2, forward_list<int>(), pos1);
//t2.splice_after(pos2, t1, t1.before_begin());
//t2.splice_after(pos2, t1, t1.begin());
for (;;);
}