1、求出1 / 1 + 1 / 3 + 1 / 5......+1 / 99的和 (1分之一+1分之三+1分支5....)

2、用循环语句，计算2 - 10之间整数的循环相乘的值（2*3*4*5....10)

3、用for循环打印九九乘法表

4、求每个字符串中字符出现的个数如：helloworld

5、实现把字符串str = "duoceshi"中任意字母变为大写(通过输入语句来实现)

6、分别打印100以内的所有偶数和奇数并存入不同的列表当中

7、请写一段Python代码实现删除一个list = [1, 3, 6, 9, 1, 8]#

8、将字符串类似："k:1|k3:2|k2:9" 处理成key:value或json格式,比如{"k": "1", "k3": "2"}

9、把字符串user_controller转换为驼峰命名UserController大驼峰在java用作变量命名

（前英文为大写后英文为小写）小驼峰：作为变量命名

10、给一组无规律的数据从大到小或从小到大进行排序如：list = [2, 6, 9, 10, 18, 15, 1]

11、分析以下数字的规律， 1 1 2 3 5 8 13 21 34用Python语言编程实现输出

#分析题目：根据规律 1+1=2 2+1=3 2+3=5 3+5=8....

#此为斐波那契数列（考试题非常多次题目）

12、如有两个list:a =['a','b','c','d','e']

b =[1,2,3,4,5] 将a中的元素作为key b中的元素作为value，将a,b合并为字典

13、有如下列表，统计列表中的字符串出现的次数

a = ['apple','banana','apple','tomao','orange','apple','banana','watermeton']

14、、列表推导式求出列表所有奇数并构造新列表 a =[1,2,3,4,5,6,7,8,9,10]

15、有如下url地址, 要求实现截取出"?"号后面的参数, 并将参数以"key value"的键值形式保存起来, 并最终通过#get(key)的方式取出对应的value值。

#url地址如下：http://ip:port/extername/get_account_trade_record.json?page_size=20&page_index=1&user_id=203317&trade_type=0"

================================================================================================

练习讲解：

1、求出1 / 1 + 1 / 3 + 1 / 5......+1 / 99的和 (1分之一+1分之三+1分支5....)

方法1:

2、用循环语句，计算2 - 10之间整数的循环相乘的值（2*3*4*5....10)

3、用for循环打印九九乘法表

\n 表示换行，相当于一个回车键

\t 表示4个空字符，类似文旦中的缩进功能，按tab

end=" " 不换行

f 是format的函数的缩写，用于格式化输出

|-------------|-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------|
| 1 2 3 4 5 6 | 方法``1``： for i ``in range``(``1``,``10``): ``for j ``in range``(``1``,``10``): ``if j<``=``i: ``print``(``'%d*%d=%d'``%``(i,j,i``*``j),end``=``' '``) ``print``(``'\n'``) 方法``2``：``for i ``in range``(``1``,``10``): ``for j ``in range``(``1``,i``+``1``): ``print``(f``"{i}*{j} ={i*j}"``,end``=``" "``) ``print``() 方法``3``：``for i ``in range``(``1``,``10``): ``for j ``in range``(``1``,i``+``1``): ``print``(``'%d*%d=%d'``%``(i,j,i``*``j),end``=``' ' ) ``print``() 方法``4``：i``=``1`` ``while i<``10``: j``=``1`` ``while j<``=``i: ``print``(j,``'x'``,i,``'='``,i``*``j,end``=``' '``) j``+``=``1`` ``print``() i``+``=``1 |

4、求每个字符串中字符出现的个数如：helloworld

|---------------|------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------|
| 1 2 3 4 5 6 7 | 方法``1``： str1``=``'helloworld' str2``=``'' for i ``in str1: ``if i ``not in str2: ``print``(``'str1中有%d个%s'``%``(str1.count(i),i)) ``str2``=``str2``+``i 方法``2``：a``=``'helloworld'`` count``=``{} ``for i ``in a: ``if i ``in count: count[i]``+``=``1`` ``else``: count[i]``=``1`` ``print``(count) 方法``3``：``sum``=``0`` ``for i ``in s2: ``for j ``in s1: ``if j``=``=``i: ``sum``=``sum``+``1`` ``print``(f``"{i}出现的次数为：{sum}"``) ``sum``=``0`` 方法``4``：str1``=``'helloworld'`` ``for i ``in set``(str1): c``=``str1.count(i) ``print``(``'{}出现的次数：{}次'``.``format``(i, c)) 方法``5``：str1``=``'hello world'`` d``=``{} ``for i ``in str1: d[i]``=``str1.count(i) ``print``(d) 方法``6``：str1``=``'hello world'`` ``print``({i:str1.count(i) ``for i ``in str1})  |

5、实现把字符串str = "duoceshi"中任意字母变为大写(通过输入语句来实现)

6、分别打印100以内的所有偶数和奇数并存入不同的列表当中

7、请写一段Python代码实现删除一个list = [1, 3, 6, 9, 1, 8]#去重（重点

|---------|-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------|
| 1 2 3 4 | 方法``1``： list1 ``= [``1``, ``3``, ``6``, ``9``, ``1``, ``8``] c``=``set``(list1) print``(c) 方法``2``：list1 ``= [``1``, ``3``, ``6``, ``9``, ``1``, ``8``] dict1``=``{} ``for i ``in list1: ``if i ``in dict1: dict1[i]``=``dict1[i]``+``1`` ``else``: dict1[i]``=``1`` ``print``(``list``(dict1.keys())) 方法``3``：通过``not in 不存在list1 ``= [``1``, ``3``, ``6``, ``9``, ``1``, ``8``] list2``=``[] ``for i ``in list1: ``if i ``not in list2: list2.append(i) ``print``(list2) 方法``4``：通过字典中键的唯一性list1 ``= [``1``, ``3``, ``6``, ``9``, ``1``, ``8``] ``dict``=``{} c``=``dict``.fromkeys(list1) ``print``(``list``(c)) 方法``5``：通过统计的方法list1 ``= [``1``, ``3``, ``6``, ``9``, ``1``, ``8``] ``for i ``in list1: ``if list1.count(i)>``1``: list1.remove(i) ``print``(list1) |

8、将字符串类似："k:1|k3:2|k2:9" 处理成key:value或json格式,比如{"k": "1", "k3": "2"}

|---------------|-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------|
| 1 2 3 4 5 6 7 | 方法``1``： str1``=``"k:1|k3:2|k2:9" str2``=``str1.split(``"|"``) dict1``=``{} for i ``in str2: ``dict1[i.split(``":"``)[``0``]] ``= i.split(``":"``)[``1``] print``(dict1) 方法``2``：``def parse_string_to_dict(input_string): ``# 使用'|'分割字符串 pairs = input_string.split('|') # 创建一个空字典来存储结果 result_dict = {} # 遍历每对键值 for pair in pairs: # 使用':'分割键和值 key, value = pair.split(':') # 将键和值添加到字典中 result_dict[key] = value return result_dict # 使用函数 input_str = "k:1|k3:2|k2:9" output_dict = parse_string_to_dict(input_str) print(output_dict) # 输出: {'k': '1', 'k3': '2', 'k2': '9'} 方法3：str1="k:1|k3:2|k2:9" str2=str1.split("|") dict1={} for i in str2: k,v=i.split(":") dict1[k]=v print(dict1) |

9、把字符串user_controller转换为驼峰命名UserController大驼峰在java用作变量命名

（前英文为大写后英文为小写）小驼峰：作为变量命名

|---------------|------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------|
| 1 2 3 4 5 6 7 | 方法``1``： str_old``=``"user_controller" list1``=``str_old.split(``"_"``) str_new``=``"" for i ``in list1: ``str_new``=``str_new``+``str``(i).capitalize() print``(str_new) 方法``2``： ``def to_camel_case(s): components ``= s.split(``'_'``) ``# 将字符串按下划线分割成组件 return ''.join(x.capitalize() for x in components) # 将每个组件的首字母大写，并拼接起来 # 示例字符串 s = "user_controller" # 转换为驼峰命名法 camel_case_str = to_camel_case(s) # 输出结果 print(camel_case_str) # 输出: UserController 方法3：str_old="user_controller" list1=str_old.split("_") print(list1[0].title()+list1[1].title()) 方法4：str_old="user_controller" list1=str_old.split("_") print(list1[0].capitalize()+list1[1].capitalize())  |

10、给一组无规律的数据从大到小或从小到大进行排序如：list = [2, 6, 9, 10, 18, 15, 1]

11、分析以下数字的规律， 1 1 2 3 5 8 13 21 34用Python语言编程实现输出

#分析题目：根据规律 1+1=2 2+1=3 2+3=5 3+5=8....

#此为斐波那契数列（考试题非常多次题目）

如:兔子的繁殖问题：如果一开始有一对兔子，它们每月生育一对兔子，小兔在出生后一个月又开始生育且繁殖情况与最初的那对兔子一样，那么一年后有多少对兔子？

答案是，每月兔子的总数可以用以下数列表示：1，1，2，3，5，8，13，21，34，55，89，144，233...

方法1:

|-----------|---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------|
| 1 2 3 4 5 | ``list``=``[``1``,``1``] for i ``in range``(``10``): ``list``.append(``list``[``-``1``]``+``list``[``-``2``]) print``(``list``) 方法``2``： <``/``em>a``=``0`` b``=``1`` ``for i ``in range``(``11``): ``sum``=``a``+``b a``=``b b``=``sum`` ``print``(a,end``=``" "``) 方法``3``：a,b``=``1``,``1`` ``print``(a,end``=``" "``) ``print``(b,end``=``" "``) ``for i ``in range``(``10``): a,b``=``b,a``+``b ``print``(b,end``=``" "``) 方法``4``：list2``=``[] ``for i ``in range``(``10``): ``if i``=``=``0 or i``=``=``1 : list2.append(``1``) ``else``: list2.append(list2[i``-``1``]``+``list2[i``-``2``]) ``print``(list2) <``/``em> |

12、如有两个list:a =['a','b','c','d','e']

b =[1,2,3,4,5] 将a中的元素作为key b中的元素作为value，将a,b合并为字典

|-----------|-------------------------------------------------------------------------------------------------------------------------------------------------------------|
| 1 2 3 4 5 | 方法``1``： a ``=``[``'a'``, ``'b'``, ``'c' , ``'d'``, ``'e'``] b ``=``[``1``, ``2``, ``3``, ``4``, ``5``] c ``= dict``(``zip``(a,b)) print``(c) |

13、有如下列表，统计列表中的字符串出现的次数

a = ['apple','banana','apple','tomao','orange','apple','banana','watermeton']

|-------------------|-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------|
| 1 2 3 4 5 6 7 8 9 | 方法``1``： a ``= [``'apple'``, ``'banana'``, ``'apple'``, ``'tomao'``, ``'orange'``, ``'apple'``, ``'banana'``, 'waterm b ``=``set``(a) for i ``in b: ``total``=``0 ``for j ``in a: ``if i ``=``=``j: ``total``=``total``+``1 ``print``(f``"{i}出现的次数为：{total}次"``) 方法``2``： ``#：使用字典 # python # 复制代码 a = ['apple', 'banana', 'apple', 'tomao', 'orange', 'apple', 'banana', 'watermelon'] # 初始化一个空字典来存储字符串及其出现的次数 count_dict = {} # 遍历列表中的每个字符串 for item in a: # 如果字符串已经在字典中，增加其计数 if item in count_dict: count_dict[item] += 1 # 如果字符串不在字典中，添加到字典并设置计数为1 else: count_dict[item] = 1 # 打印结果 print(count_dict) #{'apple': 3, 'banana': 2, 'tomao': 1, 'orange': 1, 'watermelon': 1} 方法3：a = ['apple', 'banana', 'apple', 'tomao', 'orange', 'apple', 'banana', 'watermelon'] count_dict = {} for i in a: count_dict[i] = a.count(i) print(count_dict)  方法4：a = ['apple','banana','apple','tomao','orange','apple','banana','watermeton'] for i in set(a): b=a.count(i) print('{}出现的次数：{}次'.format(i,b)) |

14、列表推导式求出列表所有奇数并构造新列表 a =[1,2,3,4,5,6,7,8,9,10]

|---------------|--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------|
| 1 2 3 4 5 6 7 | 方法``1``： list4``=``[``1``,``2``,``3``,``4``,``5``,``6``,``7``,``8``,``9``,``10``] list5``=``[] for i ``in list4: ``if i``%``2``=``=``1``: ``list5.append(i) print``(list5) |

15、有如下url地址, 要求实现截取出"?"号后面的参数, 并将参数以"key value"的键值形式保存起来, 并最终通过#get(key)的方式取出对应的value值。

#url地址如下：http://ip:port/extername/get_account_trade_record.json?page_size=20&page_index=1&user_id=203317&trade_type=0"

|----------------------------|-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------|
| 1 2 3 4 5 6 7 8 9 10 11 12 | 方法``1``： url``=``r"http:``/``/``ip:port``/``extername``/``get_account_trade_record.json?page_size``=``20``&page_index``=``1``&user_i str1``=``url.split(``"?"``) [``1``] print``(str1) str2``=``str1.split(``"&"``) print``(str2) d``=``{} for i ``in str2: ``k,v``=``i.split(``"="``) ``d[k]``=``v print``(d) print``(d.get(``"user_id"``)) 方法``2``：url1 ``=``"http://ip:port/extername/get_account_trade_record.json?page_size=20&page_index=1&user str1="``" dict1={} for i in range(url1.index("``?``")+1,len(url1)): str1=str1+url1[i] #print(str1) str2=str1.split("``&``") #print(str2) for i in str2: str3=i.split("``=``") dict1[str3[``0``]]``=``str3[``1``] ``print``(dict1) |

1.7.2 python练习题15道

a = ['apple','banana','apple','tomao','orange','apple','banana','watermeton']

a = ['apple','banana','apple','tomao','orange','apple','banana','watermeton']