eg1：解决方法：添加作用域标识符，消除成员限定的二义性
#include <iostream>
#include<iostream>
#include<vector>
using namespace std;
class A {
public:
void f()
{
cout << "A::f()" << endl;
}
};
class B {
public:
void f()
{
cout << "B::f()" << endl;
}
void g();
};
class C : public A, public B
{
public:
void g();
void h();
void f() {
A::f();
}
};
int main()
{
C C1;
C1.f();
return 0;
}
eg2：解决方法： C++中虚继承 ：使派生类只保留一份间接基类成员
class A //间接基类,第一层的类
{
protected:
int m_a;
};
class B :virtual public A //直接基类B
{
protected:
int m_b;
//继承m_a;
};
class C :virtual public A //直接基类C
{
protected:
int m_c;
};
class D :public C, public B
{
public:
void set(int a)
{
//继承m_a;
//error: m_a=a;
//不知道赋值给B 类的还是C类的m_a；
m_a = a;
//B::m_a = a;
//C::m_a = a;
}
};
int main()
{
return 0;
}
egg：解决方法： C++中虚继承 ：使派生类只保留一份间接基类成员
//多重继承 虚继承
#include <iostream>
#include <string>
using namespace std;
class A
{
public:
int m_a;
};
class B :virtual public A
{
public:
int m_b;
//虚继承 m_a
};
class C :virtual public A
{
public:
int m_c;
//虚继承 m_a
};
class D :virtual public A
{
public:
int m_d;
//虚继承 m_a
};
class E :public C, public B
{
public:
int m_e;
//虚继承 m_a
//继承 m_b
//继承 m_c
void seta(int a) { m_a = a; }//正确
void setb(int b) { m_b = b; }//正确
void setc(int c) { m_c = c; }//正确
void sete(int e) { m_e = e; }//正确
};
int main()
{
E e;
return 0;
}