代码中m4a可以换成mp3,图片和音频放同一目录，图片名image.jpg，多线程max_workers可以根据CPU核心数量修改。

import os

import subprocess

import sys

import concurrent.futures

import ffmpeg

def get_media_duration(media_path):

probe = ffmpeg.probe(media_path)

format = probe $'format'$

duration = format $'duration'$

print('duration: {}'.format(duration))

return duration

def convert_m4a_to_mp4(input_file_path,imput_image_path, output_file_path):

#ffmpeg -r 10 -f image2 -loop 1 -i image.jpg -i 01.mp3 -s 1920x1080 -pix_fmt yuvj420p -t 281 -vcodec libx264 output.mp4

print(input_file_path)

duration = get_media_duration(input_file_path)

cmd = f"ffmpeg -r 10 -f image2 -loop 1 -i \"{imput_image_path}\" -i \"{input_file_path}\" -s 640*480 -pix_fmt yuvj420p -t {duration} -vcodec libx264 \"{output_file_path}\""

os.system(cmd)

def convert_files(input_folder, output_folder):

检查输出文件夹是否存在，如果不存在则创建

if not os.path.exists(output_folder):

os.makedirs(output_folder)

创建 ThreadPoolExecutor，并限制最大线程数为 16

with concurrent.futures.ThreadPoolExecutor(max_workers=2) as executor:

遍历输入文件夹中的所有 WAV 文件

for root, dirs, files in os.walk(input_folder):

for filename in files:

if filename.endswith(".m4a"):

input_image_path = os.path.join(root, "image.jpg")

input_file_path = os.path.join(root, filename)

output_file_path = os.path.join(output_folder, os.path.splitext(filename) $0$ + ".mp4")

提交任务给线程池

executor.submit(convert_m4a_to_mp4, input_file_path,input_image_path, output_file_path)

等待所有任务完成后退出

executor.shutdown()

if name == "main":

从命令行获取输入和输出文件夹的路径

if len(sys.argv) != 2:

print("Usage: python script.py input_folder")

sys.exit(1)

input_folder = sys.argv $1$

output_folder = sys.argv $1$

convert_files(input_folder, output_folder)