每日练题（py,c,cpp）

Hobert.h2024-06-20 9:16

检验素数

python 复制代码

from math import sqrt
a = int(input("请输入一个数："))
for i in range(2,int(sqrt(a))):
    if a%i == 0:
        print("该数不是素数")
        break
    else:    
       print("该数是素数")

# # 1既不是素数也不是合数
# #可以用flag做标志位
# b = int(input("请输入一个数："))
# Flag = False
# for i in range(2,b):
#     if b%i == 0:
#         Flag = True

# if Flag:
#     print("是合数")

# else:
#     print("是素数")

cpp 复制代码

#include <iostream>

/* run this program using the console pauser or add your own getch, system("pause") or input loop */

int main(int argc, char** argv) {
 	int a = 0;
    printf("请输入一个大于1的自然数：");
    scanf("%d", &a);
    int flag = 0;
    for (int i = 2; i < a; i++)
    {
        if (a % i == 0)
        {
            flag = 1;
            break;
        }
    }
    if (flag == 0)
    {

        printf("输入的数是一个素数");
    }
    else
    {
        printf("输入的数不是一个素数");
    }
	return 0;
}

逐字检查法

自解

python 复制代码

解法1
a = "python"
b = "typhon"
list1 = list(b)
print(list1)
def judge(a,b):
    for i in range(len(a)):
       for j in range(len(a)):
            if a[i] == b[j]:
                list1[j] = None
                break
    for i in range(len(a)):
        list1[i] == None
        if list1[i] != None:
            return False
    return True
if judge(a,b) == True:
    print("是变位词")
elif judge(a,b) == False:
    print("不是变位词")

python 复制代码

解法2
a = "python"
b = "typhon"
def judge(a,b):
    list1 = list(a)
    list2 = list(b)
    j = len(list2)
    list1.sort()
    list2.sort()
    for i in range(len(list1)):
        if list1[i] == list2[i]:
            pass
        else:
            return False
    return True
if judge(a,b) == True:
    print("是变位词")
elif judge(a,b) == False:
    print("不是变位词")

他解

鹏哥C语言

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