【CodinGame】趣味算法（教学用） CLASH OF CODE -20240725

文章目录

• 简单图形绘制
• 判断
• 数字的个数
• 中间字符
• END

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简单图形绘制

import math
import sys

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

# length = 4
# c = "R"
length = int(input())
c = input()


for i in range(length):
    n_k = length - 1 - i
    print(" " * n_k + c)
    # 对称下半面 0 3
for i in range(length - 1):
    n_k = i + 1
    print(" " * n_k + c)

或者分三种(作者：SupercraftD)

import math
import sys

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

# length = int(input())
# c = input()
length = 4
c = "R"

rows = []

# 这里row构建出来['   R', '  R', ' R']
for i in range(1, length):
    rows.append(" " * (length - i) + c)
# 然后解包为参数，设置参数之间以\n分隔，构成
#    R
#   R
#  R
print(*rows, sep="\n")
# 单独输出一个
# R
print(c)
# 倒序输出
#  R
#   R
#    R
print(*rows[::-1], sep="\n")

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判断

不推荐第一种写法

import math
import sys

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

n = int(input())

for i in range(1, n + 1):
    if i % 3 == 0 and i % 5 == 0 and i % 4 == 0:
        print("FizzBuzzBar")

    if i % 3 == 0 and i % 4 == 0 and i % 5 != 0:
        print("FizzBar")
    if i % 5 == 0 and i % 4 == 0 and i % 3 != 0:
        print("BuzzBar")
    if i % 5 == 0 and i % 3 == 0 and i % 4 != 0:
        print("FizzBuzz")

    if i % 3 == 0 and i % 4 != 0 and i % 5 != 0:
        print("Fizz")
    if i % 5 == 0 and i % 3 != 0 and i % 4 != 0:
        print("Buzz")
    if i % 4 == 0 and i % 3 != 0 and i % 5 != 0:
        print("Bar")

    if i % 3 != 0 and i % 4 != 0 and i % 5 != 0:
        print(i)

没必要这样写，观察结果

n = int(input())

for i in range(1, n + 1):
    output = ""
    if i % 3 == 0:
        output += "Fizz"
    if i % 5 == 0:
        output += "Buzz"
    if i % 4 == 0:
        output += "Bar"
    if output == "":
        output = str(i)
    
    print(output)

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数字的个数

import sys
import math

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

n = int(input())
for i in range(n):
    row = input()
    # 检测里面的字符是数字的个数
    print(sum(c.isdigit() for c in row))

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中间字符

import sys
import math

# Auto-generated code below aims at helping you parse
# the standard input according to the problem statement.

s = input().split()
if len(s) %2 != 0:
    print(s[len(s)//2])
else:
    # 012 345  6//2=3
    print( s[len(s)//2-1]+ s[len(s)//2]   )

END