图像处理-形态学操作


C++代码提取骨架的实现:(代码来自opencv的扩展模块ximgproc.hpp)

cpp 复制代码
void thinningIteration(Mat &img, int iter, int thinningType)
{
	Mat marker = Mat::zeros(img.size(), CV_8UC1);
	if (thinningType == 0)
	{
		for (int i = 1; i < img.rows - 1; i++)
		{
			for (int j = 1; j < img.cols - 1; j++)
			{
				if (img.at<uchar>(i, j) == 0)
				{
					continue;
				}
				uchar p2 = img.at<uchar>(i - 1, j);
				uchar p3 = img.at<uchar>(i - 1, j + 1);
				uchar p4 = img.at<uchar>(i, j + 1);
				uchar p5 = img.at<uchar>(i + 1, j + 1);
				uchar p6 = img.at<uchar>(i + 1, j);
				uchar p7 = img.at<uchar>(i + 1, j - 1);
				uchar p8 = img.at<uchar>(i, j - 1);
				uchar p9 = img.at<uchar>(i - 1, j - 1);

				int A = (p2 == 0 && p3 == 1) + (p3 == 0 && p4 == 1) +
					(p4 == 0 && p5 == 1) + (p5 == 0 && p6 == 1) +
					(p6 == 0 && p7 == 1) + (p7 == 0 && p8 == 1) +
					(p8 == 0 && p9 == 1) + (p9 == 0 && p2 == 1);
				int B = p2 + p3 + p4 + p5 + p6 + p7 + p8 + p9;
				int m1 = iter == 0 ? (p2 * p4 * p6) : (p2 * p4 * p8);
				int m2 = iter == 0 ? (p4 * p6 * p8) : (p2 * p6 * p8);

				if (A == 1 && (B >= 2 && B <= 6) && m1 == 0 && m2 == 0)
					marker.at<uchar>(i, j) = 1;
			}
		}
	}
	if (thinningType == 1) //THINNING_GUOHALL
	{
		for (int i = 1; i < img.rows - 1; i++)
		{
			for (int j = 1; j < img.cols - 1; j++)
			{
				if (img.at<uchar>(i, j) == 0)
				{
					continue;
				}
				uchar p2 = img.at<uchar>(i - 1, j);
				uchar p3 = img.at<uchar>(i - 1, j + 1);
				uchar p4 = img.at<uchar>(i, j + 1);
				uchar p5 = img.at<uchar>(i + 1, j + 1);
				uchar p6 = img.at<uchar>(i + 1, j);
				uchar p7 = img.at<uchar>(i + 1, j - 1);
				uchar p8 = img.at<uchar>(i, j - 1);
				uchar p9 = img.at<uchar>(i - 1, j - 1);

				int C = ((!p2) & (p3 | p4)) + ((!p4) & (p5 | p6)) +
					((!p6) & (p7 | p8)) + ((!p8) & (p9 | p2));
				int N1 = (p9 | p2) + (p3 | p4) + (p5 | p6) + (p7 | p8);
				int N2 = (p2 | p3) + (p4 | p5) + (p6 | p7) + (p8 | p9);
				int N = N1 < N2 ? N1 : N2;
				int m = iter == 0 ? ((p6 | p7 | (!p9)) & p8) : ((p2 | p3 | (!p5)) & p4);

				if ((C == 1) && ((N >= 2) && ((N <= 3)) & (m == 0)))
					marker.at<uchar>(i, j) = 1;
			}
		}
	}
	img &= ~marker;
}

Mat thinning(Mat input, int thinningType)
{
	Mat output = input.clone();
	// Enforce the range of the input image to be in between 0 - 255
	output /= 255;

	Mat prev = Mat::zeros(output.size(), CV_8UC1);
	Mat diff;

	do {
		thinningIteration(output, 0, thinningType);
		thinningIteration(output, 1, thinningType);
		absdiff(output, prev, diff);
		output.copyTo(prev);
	} while (countNonZero(diff) > 0);

	output *= 255;
	return output;
}
相关推荐
日晨难再7 小时前
DSO.ai:基于AI的搜索优化型EDA工具介绍
人工智能·数字ic
机器学习之心HML7 小时前
多光伏电站功率预测新思路:当GCN遇见LSTM,解锁时空预测密码,python代码
人工智能·python·lstm
JarryStudy7 小时前
HCCL与PyTorch集成 hccl_comm.cpp DDP后端注册全流程
人工智能·pytorch·python·cann
大闲在人7 小时前
10. 配送中心卡车卸货流程分析:产能利用率与利特尔法则的实践应用
人工智能·供应链管理·智能制造·工业工程
woshikejiaih7 小时前
**播客听书与有声书区别解析2026指南,适配不同场景的音频
大数据·人工智能·python·音视频
qq7422349847 小时前
APS系统与OR-Tools完全指南:智能排产与优化算法实战解析
人工智能·算法·工业·aps·排程
兜兜转转了多少年7 小时前
从脚本到系统:2026 年 AI 代理驱动的 Shell 自动化
运维·人工智能·自动化
LLWZAI7 小时前
十分钟解决朱雀ai检测,AI率为0%
人工智能
无忧智库7 小时前
某市“十五五“智慧气象防灾减灾精准预报系统建设方案深度解读 | 从“看天吃饭“到“知天而作“的数字化转型之路(WORD)
大数据·人工智能
方见华Richard7 小时前
方见华个人履历|中英双语版
人工智能·经验分享·交互·原型模式·空间计算