代码随想录day3

203:移除链表元素:注意虚拟头节点的使用

cpp 复制代码
ListNode* removeElements(ListNode* head, int val) {
        ListNode* result = new ListNode();
        result->next = head;
        ListNode* current = result;
        while(current != nullptr && current->next != nullptr){
            if(current->next->val == val){
                ListNode* tmp = current->next;
                current->next = tmp->next;
                delete tmp;
            }else{
                current = current->next;
            }
        }
        return result->next;
    }

707.设计链表:依然采用虚拟头节点方式

todo:学习双指针写法

cpp 复制代码
class MyLinkedList {
    
public:
    struct LinkedNode {
        int val;
        LinkedNode* next;
        LinkedNode(int val):val(val),next(nullptr){}

    };
    MyLinkedList() {
        prev = new LinkedNode(0);
        _size = 0;
    }
    
    int get(int index) {
        if(index < 0 || index >= _size){
            return -1;
        }
        LinkedNode* current = prev->next;//注意此处起始位置
        while(index--){
            current = current->next;
        }
        return current->val;
    }
    
    void addAtHead(int val) {
        LinkedNode* current = new LinkedNode(val);
        LinkedNode* tmp = prev->next;
        current->next = tmp;
        prev->next = current;
        _size++;
    }
    
    void addAtTail(int val) {
        LinkedNode* current = prev;
        while(current->next != nullptr){
            current = current->next;
        }
        LinkedNode* tail = new LinkedNode(val);
        current->next = tail;
        _size++;
    }
    
    void addAtIndex(int index, int val) {
        if(index > _size){
            return;
        }
        if(index < 0) index = 0;
        
        LinkedNode* current = prev;
        while(index--){
            current = current->next;
        }
        LinkedNode* node = new LinkedNode(val);
        node->next = current->next;
        current->next = node;
        _size++;
    }
    
    void deleteAtIndex(int index) {
        if(index < 0 || index > _size-1){
            return;
        }
        LinkedNode* current = prev;
        while(index--){
            current = current->next;
        }
        LinkedNode* tmp = current->next;
        current->next = tmp->next;
        delete tmp;
        _size--;
    }
private:
    int _size;
    LinkedNode* prev;
};

双链表写法:注意用过程变量来缓存节点,保持逻辑清晰

cpp 复制代码
class MyLinkedList {
    
public:
    struct DoubleLinkedNode {
        int val;
        DoubleLinkedNode* next;
        DoubleLinkedNode* prev;
        DoubleLinkedNode(int val):val(val),next(nullptr),prev(nullptr){}

    };
    MyLinkedList() {
       sentinel = new DoubleLinkedNode(0);
       sentinel->next = sentinel;
       sentinel->prev = sentinel;
       _size = 0;
    }
    
    int get(int index) {
        if (index > (_size - 1) || index < 0) { // 检查索引是否超出范围
            return -1; // 如果超出范围,返回-1
        }
        int num;
        int mid = _size >> 1; // 计算链表中部位置
        DoubleLinkedNode *curNode = sentinel; // 从哨兵节点开始
        if (index < mid) { // 如果索引小于中部位置,从前往后遍历
            for (int i = 0; i < index + 1; i++) {
                curNode = curNode->next; // 移动到目标节点
            }
        } else { // 如果索引大于等于中部位置,从后往前遍历
            for (int i = 0; i < _size - index; i++) {
                curNode = curNode->prev; // 移动到目标节点
            }
        }
        num = curNode->val; // 获取目标节点的值
        return num; // 返回节点的值
    }
    
    void addAtHead(int val) {
        DoubleLinkedNode* current = new DoubleLinkedNode(val);
        DoubleLinkedNode* next = sentinel->next;
        next->prev = current;
        current->prev = sentinel;
        current->next = next;
        sentinel->next = current;
        _size++;
    }
    
    void addAtTail(int val) {
        DoubleLinkedNode* current = new DoubleLinkedNode(val);
        DoubleLinkedNode* prev = sentinel->prev;
        prev->next = current;
        current->prev = prev;
        current->next = sentinel;
        sentinel->prev = current;
        _size++;
    }
    
    void addAtIndex(int index, int val) {
        if(index > _size){
            return;
        }
        DoubleLinkedNode* current = sentinel;
        while(index--){
            current = current->next;
        }
        DoubleLinkedNode* tmp = new DoubleLinkedNode(val);
        DoubleLinkedNode* next = current->next;
        tmp->next = next;
        tmp->prev = current;
        next->prev = tmp;
        current->next = tmp;
        _size++;
    }
    
    void deleteAtIndex(int index) {
        if(index < 0 || index >= _size){
            return;
        }
        DoubleLinkedNode* current = sentinel;
        while(index--){
            current = current->next;
        }
        DoubleLinkedNode* tmp = current->next;
        tmp->next->prev = current;
        current->next = tmp->next;
        delete(tmp);
        _size--;
    }
private:
    int _size;
    DoubleLinkedNode* sentinel;
};

206.反转链表:学习使用双链表法

cpp 复制代码
ListNode* reverseList(ListNode* head) {
        ListNode* cur = head;
        ListNode* pre = nullptr;
        ListNode* tmp = head;
        while(cur){
            tmp = cur->next;
            cur->next = pre;
            pre = cur;
            cur = tmp;
        }
        return pre;
    }
相关推荐
ytttr8736 小时前
隐马尔可夫模型(HMM)MATLAB实现范例
开发语言·算法·matlab
AlenTech7 小时前
160. 相交链表 - 力扣(LeetCode)
数据结构·leetcode·链表
点云SLAM7 小时前
凸优化(Convex Optimization)理论(1)
人工智能·算法·slam·数学原理·凸优化·数值优化理论·机器人应用
会周易的程序员7 小时前
多模态AI 基于工业级编译技术的PLC数据结构解析与映射工具
数据结构·c++·人工智能·单例模式·信息可视化·架构
jz_ddk8 小时前
[学习] 卫星导航的码相位与载波相位计算
学习·算法·gps·gnss·北斗
放荡不羁的野指针8 小时前
leetcode150题-动态规划
算法·动态规划
sin_hielo8 小时前
leetcode 1161(BFS)
数据结构·算法·leetcode
一起努力啊~8 小时前
算法刷题-二分查找
java·数据结构·算法
水月wwww8 小时前
【算法设计】动态规划
算法·动态规划
码农水水9 小时前
小红书Java面试被问:Online DDL的INSTANT、INPLACE、COPY算法差异
算法