6.4.1 控制器父类用哪个
6.2小节和6.3小节所演示的ASP.NET Core Web API 的控制器类都继承自ControllerBase,而6.1中MVC的控制器继承自Controller,Controller又继承自ControllerBase。
所以,一般情况下,编写的WebAPI控制器类继承自ControllerBase即可,当然也可以不继承任何类,例如:
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6.4.2 操作方法的异步、返回值、状态码
1. 异步及返回值
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IActionResult返回值:
添加一个Hello控制器并编写操作方法,并且在返回404异常码时添加异常原因
cs
using Microsoft.AspNetCore.Http;
using Microsoft.AspNetCore.Mvc;
using System.ComponentModel.Design.Serialization;
namespace WebApplicationTest.Controllers
{
[Route("api/[controller]")]
[ApiController]
public class HelloController : ControllerBase
{
[HttpGet]
public IActionResult GetOrder(int id)
{
if (id==1)
{
return Ok(100);
}
else if (id==2)
{
return Ok(200);
}
else
{
return NotFound("id错误");
}
}
}
}
启动调试
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异常:
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由于IActionResult不包含返回值的类型信息,Swagger无法从操作方法中获取返回数据的类型信息,所以ASP.Net Core中提供了一个泛型ActionResult<T>
ActionResult<T>作为返回值,新增操作方法:
cs
[HttpGet("{id}")]
public ActionResult<Person> GetOrderFX(int id)
{
if (id == 1)
{
return new Person("枸杞泡茶", 18);
}
else if (id == 2)
{
return new Person("牧羊人", 27);
}
else
{
return NotFound("id错误");
}
}
启动调试:
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2. 异常响应码及统一响应体
一般在项目开发中,需要统一响应报文体的格式,以便客户端进行错误处理。例如此处声明一个ErrorInfo类表示错误详情:
cs
namespace WebApplicationTest
{
public record ErrorInfo(int ErrorCode ,string ?Message);
}
改造【GetOrderFX】方法:
cs
[HttpGet("{id}")]
public ActionResult<Person> GetOrderFX(int id)
{
if (id<=0)
{
return BadRequest(new ErrorInfo(100, "id需为正数!"));
}
else if (id == 1)
{
return new Person("枸杞泡茶", 18);
}
else if (id == 2)
{
return new Person("牧羊人", 27);
}
else
{
return NotFound(new ErrorInfo(100,"人员不存在!"));
}
}
启动调试
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6.4.3 操作方法的参数从哪里来
给服务端WebAPI传参时,有URL、QueryString,请求报文体,三种
1. 从URL获取
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例如新增一个控制器
cs
[HttpGet("N1/{number1}/N2/{number2}")]
public int Add(int number1,int number2)
{
return number1+number2;
}
启动调试
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2. QueryString
对于通过QueryString传递的参数,使用 [FromQuery]获取值
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编写一个控制方法:
cs
[HttpPost]
public int AddQueryString([FromQuery]int number1, [FromQuery] int number2)
{
return number1 + number2;
}
启动调试:
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调试结果查看,默认的方式其实就是QueryString方式,如果需要显式设置:
cs
[HttpPost]
public int AddQueryString([FromQuery]int number1, [FromQuery] int number2)
{
return number1 + number2;
}
3. 请求报文体
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新增一个操作
cs
[HttpPost]
public string AddUser(Person ppp1)
{
return "保存成功!"+ppp1.Name +",Age:"+ppp1 .Age;
}
启动调试
Json请求报文体
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响应:
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当然,这几种方式也可以混用:
cs
[HttpPut("{Name}")]
public string AddUser1(string Name, Person ppp1)
{
return "保存成功!" + ppp1.Name + ",Age:" + ppp1.Age+","+Name;
}
启动调试
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响应
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