1.针对隐式转换的情况,可能会出现误用的情况
- 示例代码
cpp
#include <iostream>
class Rational
{
public:
Rational(float iNum1 = 1, float iNum2 = 2) { fNum = iNum1 / iNum2; }
~Rational() {}
//自定义逻辑
const Rational operator * (const Rational& rhs) const{ return Rational(this->fNum, rhs.fNum);}
public:
float fNum;
};
int main()
{
Rational R1(1.0);
Rational R2 = R1 * 2.0;
Rational R3 = 3.0 * R2;
}
不符合类的设计逻辑
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书中解释
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2.解决:使用非成员函数来解决以上的问题
- 示例代码
cpp
#include <iostream>
class Rational
{
public:
Rational(float iNum1 = 1, float iNum2 = 2) { fNum = iNum1 / iNum2; }
~Rational() {}
public:
float fNum;
};
const Rational operator * (const Rational& r1, const Rational& r2)
{
return Rational(r1.fNum, r2.fNum);
}
int main()
{
Rational R1(1.0);
Rational R2 = R1 * 2.0;
Rational R3 = 3.0 * R2;
std::cout << "end...................." << std::endl;
}
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