C语言实现 input事件模拟
            
            
              c
              
              
            
          
          #include <stdio.h>
#include <fcntl.h>
#include <unistd.h>
#include <linux/input.h>
int main() {
    int fd = open("/dev/input/event0", O_RDWR);
    if (fd < 0) {
        perror("Failed to open device");
        return -1;
    }
    // 定义 8 个输入事件(按顺序模拟按键按下和释放)
    struct input_event events[] = {
        // KEY_314 按下
        {.type = EV_KEY, .code = 314, .value = 1},
        {.type = EV_SYN, .code = SYN_REPORT, .value = 0},
        // KEY_212 按下
        {.type = EV_KEY, .code = 212, .value = 1},
        {.type = EV_SYN, .code = SYN_REPORT, .value = 0},
        // KEY_212 释放
        {.type = EV_KEY, .code = 212, .value = 0},
        {.type = EV_SYN, .code = SYN_REPORT, .value = 0},
        // KEY_314 释放
        {.type = EV_KEY, .code = 314, .value = 0},
        {.type = EV_SYN, .code = SYN_REPORT, .value = 0}
    };
    // 批量发送事件
    for (int i = 0; i < sizeof(events)/sizeof(events[0]); i++) {
        if (write(fd, &events[i], sizeof(struct input_event)) < 0) {
            perror("Failed to send event");
            close(fd);
            return -1;
        }
    }
    close(fd);
    return 0;
}静态交叉编译
            
            
              c
              
              
            
          
          aarch64-linux-gnu-gcc-10   123.c -o startup_camera_common --static可以模拟 简单按键事件
为什么不用 shell命令
比如
adb shell "sendevent /dev/input/event0 0001 314 00000001"
adb shell "sendevent /dev/input/event0 0000 0000 00000000"
adb shell "sendevent /dev/input/event0 0001 212 00000001"
adb shell "sendevent /dev/input/event0 0000 0000 00000000"
adb shell "sendevent /dev/input/event0 0001 212 00000000"
adb shell "sendevent /dev/input/event0 0000 0000 00000000"
adb shell "sendevent /dev/input/event0 0001 314 00000000"
adb shell "sendevent /dev/input/event0 0000 0000 00000000"
sendevent 是 busybox命令, 每次执行八条命令 耗时过长, 在抓 perfetto的时候 会看到耗时特别久, 对于分析按键触发的性能事件有很大的干扰!