Leetcode 3767. Maximize Points After Choosing K Tasks

  • [Leetcode 3767. Maximize Points After Choosing K Tasks](#Leetcode 3767. Maximize Points After Choosing K Tasks)
    • [1. 解题思路](#1. 解题思路)
    • [2. 代码实现](#2. 代码实现)

1. 解题思路

这一题是leetcode双周赛171的第三题,同样是一个medium的题目。

这一题乍一眼看过去像是一个动态规划的题目,实际其实我们只需要考察tech1与tech2的差值,然后取最大的 k k k个强制分配给tech1,其余的谁大取谁即可。

2. 代码实现

给出python代码实现如下:

python 复制代码
class Solution:
    def maxPoints(self, technique1: List[int], technique2: List[int], k: int) -> int:
        s = [(x-y, x, y) for x, y in zip(technique1, technique2)]
        s = sorted(s, reverse=True)
        n, ans = len(s), 0
        for i in range(n):
            if i < k:
                ans += s[i][1]
            elif s[i][0] >= 0:
                ans += s[i][1]
            else:
                ans += s[i][2]
        return ans

提交代码评测得到:耗时275ms,占用内存40.16MB。

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