mysql练习

暗之星瞳2025-12-18 15:42
数据表介绍

  • 1.学⽣表 Student(SId,Sname,Sage,Ssex)

    • SId 学⽣编号

    • Sname 学⽣姓名

    • Sage 出⽣年⽉

    • Ssex 学⽣性别

  • 2.课程表 Course(CId,Cname,TId)

    • CId 课程编号

    • Cname 课程名称

    • TId 教师编号

  • 3.教师表 Teacher(TId,Tname)

    • TId 教师编号

    • Tname 教师姓名

  • 4.成绩表 SC(SId,CId,score)

    • SId 学⽣编号

    • CId 课程编号

    • score 分数

建表语句

  • 学⽣表 Student

    复制代码 
    create table Student(
    SId varchar(10),
    Sname varchar(10),
    Sage datetime,
    Ssex varchar(10)
);

  • 课程表 Course

    复制代码 
    create table Course(
    CId varchar(10),
    Cname nvarchar(10),
    TId varchar(10)
);

  • 教师表 Teacher

    复制代码 
    create table Teacher(
    TId varchar(10),
    Tname varchar(10)
);

  • 成绩表 SC

    复制代码 
    create table SC(
    SId varchar(10),
    CId varchar(10),
    score decimal(18,1)
);
插入数据

  • 学⽣表 Student

    复制代码 
    -- 学生表 Student
insert into Student values('01' , '赵雷' , '1990-01-01' , '男'); 
insert into Student values('02' , '钱电' , '1990-12-21' , '男'); 
insert into Student values('03' , '孙⻛' , '1990-12-20' , '男'); 
insert into Student values('04' , '李云' , '1990-12-06' , '男'); 
insert into Student values('05' , '周梅' , '1991-12-01' , '⼥'); 
insert into Student values('06' , '吴兰' , '1992-01-01' , '⼥'); 
insert into Student values('07' , '郑⽵' , '1989-01-01' , '⼥'); 
insert into Student values('09' , '张三' , '2017-12-20' , '⼥'); 
insert into Student values('10' , '李四' , '2017-12-25' , '⼥'); 
insert into Student values('11' , '李四' , '2012-06-06' , '⼥'); 
insert into Student values('12' , '赵六' , '2013-06-13' , '⼥'); 
insert into Student values('13' , '孙七' , '2014-06-01' , '⼥');

  • 课程表 Course

    复制代码 
    -- 科⽬表 Course 
insert into Course values('01' , '语⽂' , '02'); 
insert into Course values('02' , '数学' , '01'); 
insert into Course values('03' , '英语' , '03');

  • 教师表 Teacher

    复制代码 
    -- 教师表 Teacher 
insert into Teacher values('01' , '张三'); 
insert into Teacher values('02' , '李四'); 
insert into Teacher values('03' , '王五');

  • 成绩表 SC

    复制代码 
    -- 成绩表 SC 
insert into SC values('01' , '01' , 80); 
insert into SC values('01' , '02' , 90); 
insert into SC values('01' , '03' , 99); 
insert into SC values('02' , '01' , 70); 
insert into SC values('02' , '02' , 60); 
insert into SC values('02' , '03' , 80); 
insert into SC values('03' , '01' , 80); 
insert into SC values('03' , '02' , 80); 
insert into SC values('03' , '03' , 80); 
insert into SC values('04' , '01' , 50); 
insert into SC values('04' , '02' , 30); 
insert into SC values('04' , '03' , 20); 
insert into SC values('05' , '01' , 76); 
insert into SC values('05' , '02' , 87); 
insert into SC values('06' , '01' , 31); 
insert into SC values('06' , '03' , 34); 
insert into SC values('07' , '02' , 89); 
insert into SC values('07' , '03' , 98);
1. 查询 "01" 课程比 "02" 课程成绩高的学生的信息及课程分数

sql

复制代码 
-- 步骤：先分别查询01和02课程成绩，再关联比较
SELECT s.*, sc1.score AS '01课程分数', sc2.score AS '02课程分数'
FROM Student s
JOIN SC sc1 ON s.SId = sc1.SId AND sc1.CId = '01'
JOIN SC sc2 ON s.SId = sc2.SId AND sc2.CId = '02'
WHERE sc1.score > sc2.score;
2. 查询同时存在 "01" 课程和 "02" 课程的情况

sql

复制代码 
-- 方法1：关联查询
SELECT s.SId, s.Sname, sc1.score AS '01课程', sc2.score AS '02课程'
FROM Student s
JOIN SC sc1 ON s.SId = sc1.SId AND sc1.CId = '01'
JOIN SC sc2 ON s.SId = sc2.SId AND sc2.CId = '02';

-- 方法2：分组筛选
SELECT SId
FROM SC
WHERE CId IN ('01', '02')
GROUP BY SId
HAVING COUNT(DISTINCT CId) = 2;
3. 查询存在 "01" 课程但可能不存在 "02" 课程的情况（不存在时显示为 null）

sql

复制代码 
SELECT s.SId, s.Sname, sc1.score AS '01课程', sc2.score AS '02课程'
FROM Student s
JOIN SC sc1 ON s.SId = sc1.SId AND sc1.CId = '01'
LEFT JOIN SC sc2 ON s.SId = sc2.SId AND sc2.CId = '02';
4. 查询不存在 "01" 课程但存在 "02" 课程的情况

sql

复制代码 
SELECT s.*, sc2.score AS '02课程分数'
FROM Student s
JOIN SC sc2 ON s.SId = sc2.SId AND sc2.CId = '02'
WHERE s.SId NOT IN (SELECT SId FROM SC WHERE CId = '01');
5. 查询平均成绩大于等于 60 分的同学的学生编号、姓名和平均成绩

sql

复制代码 
SELECT s.SId, s.Sname, ROUND(AVG(sc.score), 1) AS 平均成绩
FROM Student s
JOIN SC sc ON s.SId = sc.SId
GROUP BY s.SId, s.Sname
HAVING AVG(sc.score) >= 60;
6. 查询在 SC 表存在成绩的学生信息

sql

复制代码 
-- 方法1：DISTINCT去重
SELECT DISTINCT s.*
FROM Student s
JOIN SC sc ON s.SId = sc.SId;

-- 方法2：IN子查询
SELECT *
FROM Student
WHERE SId IN (SELECT DISTINCT SId FROM SC);
7. 查询所有同学的学生编号、姓名、选课总数、所有课程的总成绩（没成绩显示为 null）

sql

复制代码 
SELECT s.SId, s.Sname, 
       COUNT(sc.CId) AS 选课总数, 
       SUM(sc.score) AS 总成绩
FROM Student s
LEFT JOIN SC sc ON s.SId = sc.SId
GROUP BY s.SId, s.Sname;
8. 查询「李」姓老师的数量

sql

复制代码 
SELECT COUNT(*) AS 李姓老师数量
FROM Teacher
WHERE Tname LIKE '李%';
9. 查询学过「张三」老师授课的同学的信息

sql

复制代码 
-- 步骤：先找到张三老师的课程，再关联成绩表和学生表
SELECT DISTINCT s.*
FROM Student s
JOIN SC sc ON s.SId = sc.SId
JOIN Course c ON sc.CId = c.CId
JOIN Teacher t ON c.TId = t.TId
WHERE t.Tname = '张三';
10. 查询没有学全所有课程的同学的信息

sql

复制代码 
-- 步骤：先统计总课程数，再筛选选课数不足的学生
SELECT s.*
FROM Student s
LEFT JOIN SC sc ON s.SId = sc.SId
GROUP BY s.SId, s.Sname
HAVING COUNT(DISTINCT sc.CId) < (SELECT COUNT(*) FROM Course);
11. 查询至少有一门课与学号为 "01" 的同学所学相同的同学的信息

sql

复制代码 
SELECT DISTINCT s.*
FROM Student s
JOIN SC sc ON s.SId = sc.SId
WHERE sc.CId IN (SELECT CId FROM SC WHERE SId = '01')
  AND s.SId != '01'; -- 排除01号学生自身
12. 查询和 "01" 号同学学习的课程完全相同的其他同学的信息

sql

复制代码 
-- 步骤：1. 获取01号课程列表 2. 筛选选课数相同且课程完全匹配的学生
SELECT s.*
FROM Student s
JOIN SC sc ON s.SId = sc.SId
WHERE s.SId != '01'
GROUP BY s.SId, s.Sname
HAVING COUNT(DISTINCT sc.CId) = (SELECT COUNT(*) FROM SC WHERE SId = '01')
   AND GROUP_CONCAT(sc.CId ORDER BY sc.CId) = (SELECT GROUP_CONCAT(CId ORDER BY CId) FROM SC WHERE SId = '01');
13. 查询没学过 "张三" 老师讲授的任一课程的学生姓名

sql

复制代码 
-- 步骤：先找到张三老师的课程，再筛选未选这些课程的学生
SELECT s.Sname
FROM Student s
WHERE s.SId NOT IN (
    SELECT DISTINCT sc.SId
    FROM SC sc
    JOIN Course c ON sc.CId = c.CId
    JOIN Teacher t ON c.TId = t.TId
    WHERE t.Tname = '张三'
);
14. 查询两门及其以上不及格课程的同学的学号、姓名及其平均成绩

sql

复制代码 
SELECT s.SId, s.Sname, ROUND(AVG(sc_all.score), 1) AS 平均成绩
FROM Student s
JOIN SC sc_fail ON s.SId = sc_fail.SId AND sc_fail.score < 60
JOIN SC sc_all ON s.SId = sc_all.SId
GROUP BY s.SId, s.Sname
HAVING COUNT(DISTINCT sc_fail.CId) >= 2;
15. 检索 "01" 课程分数小于 60，按分数降序排列的学生信息

sql

复制代码 
SELECT s.*, sc.score
FROM Student s
JOIN SC sc ON s.SId = sc.SId
WHERE sc.CId = '01' AND sc.score < 60
ORDER BY sc.score DESC;
16. 按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩

sql

复制代码 
-- 步骤：先计算每个学生的平均成绩，再关联所有课程成绩
SELECT 
    s.SId, s.Sname,
    MAX(CASE WHEN sc.CId = '01' THEN sc.score ELSE NULL END) AS 语文,
    MAX(CASE WHEN sc.CId = '02' THEN sc.score ELSE NULL END) AS 数学,
    MAX(CASE WHEN sc.CId = '03' THEN sc.score ELSE NULL END) AS 英语,
    ROUND(AVG(sc.score), 1) AS 平均成绩
FROM Student s
LEFT JOIN SC sc ON s.SId = sc.SId
GROUP BY s.SId, s.Sname
ORDER BY 平均成绩 DESC;
17. 查询各科成绩最高分、最低分和平均分（含及格率 / 中等率 / 优良率 / 优秀率）

sql

复制代码 
SELECT 
    c.CId, c.Cname,
    COUNT(sc.SId) AS 选修人数,
    MAX(sc.score) AS 最高分,
    MIN(sc.score) AS 最低分,
    ROUND(AVG(sc.score), 1) AS 平均分,
    -- 及格率（>=60）
    ROUND(SUM(CASE WHEN sc.score >= 60 THEN 1 ELSE 0 END)/COUNT(sc.SId)*100, 1) AS 及格率,
    -- 中等率（70-80）
    ROUND(SUM(CASE WHEN sc.score BETWEEN 70 AND 80 THEN 1 ELSE 0 END)/COUNT(sc.SId)*100, 1) AS 中等率,
    -- 优良率（80-90）
    ROUND(SUM(CASE WHEN sc.score BETWEEN 80 AND 90 THEN 1 ELSE 0 END)/COUNT(sc.SId)*100, 1) AS 优良率,
    -- 优秀率（>=90）
    ROUND(SUM(CASE WHEN sc.score >= 90 THEN 1 ELSE 0 END)/COUNT(sc.SId)*100, 1) AS 优秀率
FROM Course c
JOIN SC sc ON c.CId = sc.CId
GROUP BY c.CId, c.Cname
ORDER BY 选修人数 DESC, c.CId ASC;
18. 按各科平均成绩排序并显示排名（Score 重复时保留名次空缺）

sql

复制代码 
-- 使用RANK()函数（保留空缺）
SELECT 
    CId, 
    平均成绩,
    RANK() OVER (ORDER BY 平均成绩 DESC) AS 排名
FROM (
    SELECT CId, ROUND(AVG(score), 1) AS 平均成绩
    FROM SC
    GROUP BY CId
) AS t;
19. 按各科平均成绩排序并显示排名（Score 重复时不保留名次空缺）

sql

复制代码 
-- 使用DENSE_RANK()函数（不保留空缺）
SELECT 
    CId, 
    平均成绩,
    DENSE_RANK() OVER (ORDER BY 平均成绩 DESC) AS 排名
FROM (
    SELECT CId, ROUND(AVG(score), 1) AS 平均成绩
    FROM SC
    GROUP BY CId
) AS t;
20. 查询学生的总成绩并排名（总分重复保留名次空缺）

sql

复制代码 
SELECT 
    s.SId, s.Sname,
    IFNULL(SUM(sc.score), 0) AS 总成绩,
    RANK() OVER (ORDER BY IFNULL(SUM(sc.score), 0) DESC) AS 排名
FROM Student s
LEFT JOIN SC sc ON s.SId = sc.SId
GROUP BY s.SId, s.Sname;
21. 查询学生的总成绩并排名（总分重复不保留名次空缺）

sql

复制代码 
SELECT 
    s.SId, s.Sname,
    IFNULL(SUM(sc.score), 0) AS 总成绩,
    DENSE_RANK() OVER (ORDER BY IFNULL(SUM(sc.score), 0) DESC) AS 排名
FROM Student s
LEFT JOIN SC sc ON s.SId = sc.SId
GROUP BY s.SId, s.Sname;
22. 统计各科成绩各分数段人数及百分比

sql

复制代码 
SELECT 
    c.CId, c.Cname,
    -- [100-85]
    SUM(CASE WHEN sc.score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS '100-85人数',
    ROUND(SUM(CASE WHEN sc.score BETWEEN 85 AND 100 THEN 1 ELSE 0 END)/COUNT(sc.SId)*100, 1) AS '100-85百分比',
    -- [85-70]
    SUM(CASE WHEN sc.score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS '85-70人数',
    ROUND(SUM(CASE WHEN sc.score BETWEEN 70 AND 85 THEN 1 ELSE 0 END)/COUNT(sc.SId)*100, 1) AS '85-70百分比',
    -- [70-60]
    SUM(CASE WHEN sc.score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS '70-60人数',
    ROUND(SUM(CASE WHEN sc.score BETWEEN 60 AND 70 THEN 1 ELSE 0 END)/COUNT(sc.SId)*100, 1) AS '70-60百分比',
    -- [60-0]
    SUM(CASE WHEN sc.score < 60 THEN 1 ELSE 0 END) AS '60-0人数',
    ROUND(SUM(CASE WHEN sc.score < 60 THEN 1 ELSE 0 END)/COUNT(sc.SId)*100, 1) AS '60-0百分比'
FROM Course c
JOIN SC sc ON c.CId = sc.CId
GROUP BY c.CId, c.Cname;
23. 查询各科成绩前三名的记录

sql

复制代码 
-- 方法：使用窗口函数ROW_NUMBER()
SELECT *
FROM (
    SELECT 
        sc.SId, sc.CId, sc.score,
        ROW_NUMBER() OVER (PARTITION BY sc.CId ORDER BY sc.score DESC) AS 排名
    FROM SC sc
) AS t
WHERE 排名 <= 3;
24. 查询每门课程被选修的学生数

sql

复制代码 
SELECT c.CId, c.Cname, COUNT(DISTINCT sc.SId) AS 选修人数
FROM Course c
LEFT JOIN SC sc ON c.CId = sc.CId
GROUP BY c.CId, c.Cname;
25. 查询出只选修两门课程的学生学号和姓名

sql

复制代码 
SELECT s.SId, s.Sname
FROM Student s
JOIN SC sc ON s.SId = sc.SId
GROUP BY s.SId, s.Sname
HAVING COUNT(DISTINCT sc.CId) = 2;
26. 查询男生、女生人数

sql

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SELECT Ssex AS 性别, COUNT(*) AS 人数
FROM Student
GROUP BY Ssex;
27. 查询名字中含有「风」字的学生信息

sql

复制代码 
SELECT *
FROM Student
WHERE Sname LIKE '%风%';
28. 查询同名同性学生名单，并统计同名人数

sql

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SELECT Sname, Ssex, COUNT(*) AS 同名人数
FROM Student
GROUP BY Sname, Ssex
HAVING COUNT(*) > 1;
29. 查询 1990 年出生的学生名单

sql

复制代码 
-- 方法1：YEAR函数
SELECT *
FROM Student
WHERE YEAR(Sage) = 1990;

-- 方法2：LIKE匹配
SELECT *
FROM Student
WHERE Sage LIKE '1990%';
30. 查询每门课程的平均成绩（降序，平均成绩相同按课程号升序）

sql

复制代码 
SELECT c.CId, c.Cname, ROUND(AVG(sc.score), 1) AS 平均成绩
FROM Course c
JOIN SC sc ON c.CId = sc.CId
GROUP BY c.CId, c.Cname
ORDER BY 平均成绩 DESC, c.CId ASC;
31. 查询平均成绩大于等于 85 的所有学生的学号、姓名和平均成绩

sql

复制代码 
SELECT s.SId, s.Sname, ROUND(AVG(sc.score), 1) AS 平均成绩
FROM Student s
JOIN SC sc ON s.SId = sc.SId
GROUP BY s.SId, s.Sname
HAVING AVG(sc.score) >= 85;
32. 查询课程名称为「数学」且分数低于 60 的学生姓名和分数

sql

复制代码 
SELECT s.Sname, sc.score
FROM Student s
JOIN SC sc ON s.SId = sc.SId
JOIN Course c ON sc.CId = c.CId
WHERE c.Cname = '数学' AND sc.score < 60;
33. 查询所有学生的课程及分数情况（含没成绩 / 没选课的情况）

sql

复制代码 
-- 笛卡尔积生成所有学生-课程组合，再左连接成绩
SELECT s.SId, s.Sname, c.Cname, sc.score
FROM Student s
CROSS JOIN Course c
LEFT JOIN SC sc ON s.SId = sc.SId AND c.CId = sc.CId
ORDER BY s.SId, c.CId;
34. 查询任何一门课程成绩在 70 分以上的姓名、课程名称和分数

sql

复制代码 
SELECT DISTINCT s.Sname, c.Cname, sc.score
FROM Student s
JOIN SC sc ON s.SId = sc.SId AND sc.score > 70
JOIN Course c ON sc.CId = c.CId;
35. 查询不及格的课程

sql

复制代码 
SELECT s.SId, s.Sname, c.Cname, sc.score
FROM Student s
JOIN SC sc ON s.SId = sc.SId AND sc.score < 60
JOIN Course c ON sc.CId = c.CId;
36. 查询课程编号为 01 且课程成绩在 80 分以上的学生的学号和姓名

sql

复制代码 
SELECT s.SId, s.Sname
FROM Student s
JOIN SC sc ON s.SId = sc.SId
WHERE sc.CId = '01' AND sc.score > 80;
37. 求每门课程的学生人数

sql

复制代码 
-- 同24题，重复题目
SELECT c.CId, c.Cname, COUNT(DISTINCT sc.SId) AS 学生人数
FROM Course c
LEFT JOIN SC sc ON c.CId = sc.CId
GROUP BY c.CId, c.Cname;
38. 成绩不重复，查询选修「张三」老师所授课程的学生中成绩最高的学生信息及其成绩

sql

复制代码 
-- 步骤：先找到张三老师的课程，再筛选最高分（无重复）
SELECT s.*, sc.score, c.Cname
FROM Student s
JOIN SC sc ON s.SId = sc.SId
JOIN Course c ON sc.CId = c.CId
JOIN Teacher t ON c.TId = t.TId
WHERE t.Tname = '张三'
  AND sc.score = (
      SELECT MAX(score)
      FROM SC sc2
      JOIN Course c2 ON sc2.CId = c2.CId
      JOIN Teacher t2 ON c2.TId = t2.TId
      WHERE t2.Tname = '张三'
  );
39. 成绩有重复的情况下，查询选修「张三」老师所授课程的学生中成绩最高的学生信息及其成绩

sql

复制代码 
-- 方法：使用窗口函数
SELECT *
FROM (
    SELECT 
        s.*, sc.score, c.Cname,
        RANK() OVER (ORDER BY sc.score DESC) AS 排名
    FROM Student s
    JOIN SC sc ON s.SId = sc.SId
    JOIN Course c ON sc.CId = c.CId
    JOIN Teacher t ON c.TId = t.TId
    WHERE t.Tname = '张三'
) AS t
WHERE 排名 = 1;
40. 查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩

sql

复制代码 
SELECT DISTINCT sc1.SId, sc1.CId, sc1.score
FROM SC sc1
JOIN SC sc2 ON sc1.SId = sc2.SId 
           AND sc1.CId != sc2.CId 
           AND sc1.score = sc2.score
ORDER BY sc1.score;
41. 查询每门课程成绩最好的前两名

sql

复制代码 
-- 同23题（前三名），调整为前两名
SELECT *
FROM (
    SELECT 
        sc.SId, sc.CId, sc.score,
        ROW_NUMBER() OVER (PARTITION BY sc.CId ORDER BY sc.score DESC) AS 排名
    FROM SC sc
) AS t
WHERE 排名 <= 2;
42. 统计每门课程的学生选修人数（超过 5 人的课程才统计）

sql

复制代码 
SELECT c.CId, c.Cname, COUNT(DISTINCT sc.SId) AS 选修人数
FROM Course c
JOIN SC sc ON c.CId = sc.CId
GROUP BY c.CId, c.Cname
HAVING COUNT(DISTINCT sc.SId) > 5;
43. 检索至少选修两门课程的学生学号

sql

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SELECT SId
FROM SC
GROUP BY SId
HAVING COUNT(DISTINCT CId) >= 2;
44. 查询选修了全部课程的学生信息

sql

复制代码 
SELECT s.*
FROM Student s
JOIN SC sc ON s.SId = sc.SId
GROUP BY s.SId, s.Sname
HAVING COUNT(DISTINCT sc.CId) = (SELECT COUNT(*) FROM Course);
45. 查询各学生的年龄（只按年份来算）

sql

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SELECT SId, Sname, YEAR(NOW()) - YEAR(Sage) AS 年龄
FROM Student;
46. 按出生日期算年龄（当前月日 < 出生年月的月日则年龄减一）

sql

复制代码 
SELECT 
    SId, Sname,
    YEAR(NOW()) - YEAR(Sage) - 
    CASE WHEN DATE_FORMAT(NOW(), '%m%d') < DATE_FORMAT(Sage, '%m%d') 
         THEN 1 
         ELSE 0 
    END AS 实际年龄
FROM Student;
47. 查询本周过生日的学生

sql

复制代码 
-- MySQL中WEEKOFYEAR函数：本周（1-53）
SELECT *
FROM Student
WHERE WEEKOFYEAR(Sage) = WEEKOFYEAR(NOW());
48. 查询下周过生日的学生

sql

复制代码 
SELECT *
FROM Student
WHERE WEEKOFYEAR(Sage) = WEEKOFYEAR(NOW()) + 1;
49. 查询本月过生日的学生

sql

复制代码 
SELECT *
FROM Student
WHERE MONTH(Sage) = MONTH(NOW());
50. 查询下月过生日的学生

sql

复制代码 
SELECT *
FROM Student
WHERE MONTH(Sage) = MONTH(NOW()) + 1;

补充说明

  1. 所有 SQL 基于 MySQL 8.0 + 语法（支持窗口函数：RANK ()/DENSE_RANK ()/ROW_NUMBER ()）；
  2. 涉及日期计算的函数（YEAR/MONTH/WEEKOFYEAR）为 MySQL 特有，其他数据库（如 Oracle/SQL Server）需调整；
  3. 百分比计算中使用ROUND(...,1)保留 1 位小数，可根据需求调整；
  4. 左连接（LEFT JOIN）确保无成绩 / 无选课的学生也能显示，符合题目要求。
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