任意大小的整数和任意精度的小数的API方法

import java.math.BigInteger;

public class BigEnoughInteger {
    public static void main(String[] args) {
        /*
        * Long num = 8988774156023154060879859845612358874056123877989564132564894L 是存储不了的，会报异常
        * 使用BigInteger
        * BigInteger element = new BigInteger("number");
        * element方法:
        * 1. add(BigInteger val)  //加
        * 2. subtract(BigInteger val)  //减
        * 3. multiply(BigInteger val)  //乘
        * 4. divide(BigInteger val)  //除
        * 5. remainder(BigInteger val)  //求余数
        * */

        BigInteger element = new BigInteger("8988774156023154060879859845612358874056123877989564132564894");
        BigInteger element2 = new BigInteger("8568498465321564898765321648994");
        System.out.println(element.add(element2));
        System.out.println(element2.subtract(element));
        System.out.println(element.multiply(element2));
        System.out.println(element.divide(element2));
        System.out.println(element.remainder(element2));

        /*
        * BigDecimal bd = new BigDecimal("number");
        *
        * BigDecimal方法:
        * 1. add(BigDecimal val)  //加
        * 2. subtract(BigDecimal val)  //减
        * 3. multiply(BigDecimal val)  //乘
        * 4. divide(BigDecimal val)  //除
        *   4.1除不尽时，会报异常
        *      .divide(BigDecimal val, int scale, int roundingMode)
        *   4.2 roungdingMode的类型
        *       1.CEILING  //向上取整
        *       2.FLOOR  //向下取整
        *       3.HALF_UP  //四舍五入
        *       4.HALF_EVEN  //偶数就进位，一半概率
        * 5. remainder(BigDecimal val)  //求余数
        * */

    }
}