KY18 今年的第几天？

KY18 今年的第几天？

⭐️难度：中等

⭐️知识点：模拟

📖题目：

📚题解1：自己做

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<string.h>

using namespace std;

void count(int year, int month, int day) {
    int dayOfMonth[] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };
    int isLeap;  // 是否是闰年
    if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0)) {  // 闰年二月29天
        dayOfMonth[2] = 29;
    }
    int sum = 0; // 记录第几天
    for (int i = 1;i < month;i++) {
        sum = sum + dayOfMonth[i];
    }
    sum = sum + day;
    printf("%d\n", sum);
}

int main() {
    int year = 0 ;
    int month = 0;
    int day = 0;
    while (scanf("%d%d%d",&year,&month,&day) != EOF) {
        count(year, month, day);
    }
    

    return 0;
}

📚题解2：利用NextDay函数

#include <stdio.h>
    using namespace std;
    void NextDay(int &year, int &month, int &day) {
        // & 出现在定义or形参当中 表示引用的意思 出现在其他位置，表示取地址
        // 存储一下 月份和天数的对应关系
        int dayOfMonth[] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };
        int isLeap; // 是否是闰年 
        isLeap = year % 400 == 0 || year % 4 == 0 && year % 100 != 0;
        if (isLeap) {
            dayOfMonth[2] = 29;
        }
        else {
            dayOfMonth[2] = 28;
        }
    
        ++day;
        if (day > dayOfMonth[month]) {
            day = 1;
            ++month;
        }
        if (month > 12) {
            month = 1;
            ++year;
        }
        //printf("NextDay year = %d, month = %d, day = %d\n", year, month, day);
    }
    //int main() {
    //	int year = 1900;
    //	int month = 2;
    //	int day = 28;
    //	NextDay(year, month, day);
    //	printf("main year = %d, month = %d, day = %d\n", year, month, day);
    //	return 0;
    //}
    int main() {
        int year, month, day;
        while (scanf("%d%d%d", &year, &month, &day) != EOF) {
            int next = 1; // NextDay执行的次数
            int curmonth = 1;
            int curday = 1;
            while (1) {
                if (month == curmonth && day == curday) {
                    break;
                }
                NextDay(year, curmonth, curday);
                ++next;
            }
            printf("%d\n", next);
        }
        return 0;
    }