进阶2.回文数
问题描述
1221是一个非常特殊的数，它从左边读和从右边读是一样的，编程求大于等于n的所有这样的四位十进制数。
个人总结
本题可以枚举所有可能的千位 a（1 到 9），十位和百位 b（0 到 9），构造数num = a*1000 + b*100 + b*10 + a，然后判断num>=n就输出。
cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
for (int a = 1; a <= 9; a++) {
for (int b = 0; b <= 9; b++) {
int num = a * 1000 + b * 100 + b * 10 + a;
if (num >= n) {
cout << num << endl;
}
}
}
return 0;
}计算机英语翻译
原文：
In recent years, pre-trained models have played an important role in artificial intelligence research. Researchers typically first train a general model using large-scale datasets and then fine-tune it on specific tasks. In this way, the model can utilize the knowledge learned during the pre-training stage to improve the performance of downstream tasks. For example, in the field of natural language processing, many language models are pre-trained on massive text corpora and achieve excellent results in tasks such as text classification, machine translation, and question answering. The pre-training and fine-tuning framework not only reduces training costs but also improves the generalization ability of models. Therefore, this approach has become an important paradigm in modern artificial intelligence research.
翻译：
近年来，预训练模型在人工智能研究中扮演了重要角色。研究者们通常首先使用大规模的数据集来训练一个总体的模型，然后在特定任务中进行微调。以这种方式，这个模型可以xx预训练阶段学到的知识来提升xx任务的表现。例如，在自然语言处理领域，许多语言模型在大量文本xx上进行预训练，并且在文本分类、机器翻译和问题回答等任务中取得优异的成功。预训练和微调架构不仅减少了训练开销而且提升了模型的总体能力。因此，这种方式已经成为现代人工智能研究的重要方式。
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