[保研/考研机试] KY109 Zero-complexity Transposition 上海交通大学复试上机题 C++实现

描述：

You are given a sequence of integer numbers. Zero-complexity transposition of the sequence is the reverse of this sequence. Your task is to write a program that prints zero-complexity transposition of the given sequence.

输入描述：

For each case, the first line of the input file contains one integer n-length of the sequence (0 ＜ n ≤ 10 000). The second line contains n integers numbers-a1, a2, ..., an (-1 000 000 000 000 000 ≤ ai ≤ 1 000 000 000 000 000).

输出描述：

For each case, on the first line of the output file print the sequence in the reverse order.

示例1：

输入：
5
-3 4 6 -8 9

输出：
9 -8 6 4 -3

源代码：

#include<iostream>
#include<stack>
using namespace std;

//例题5.4 Zero-complexity Transposition
int main()
{
	int n;
	cin >> n;
	stack<int> myStack;
	for (int i = 0; i < n; i++) {
		int temp = 0;
		cin >> temp;
		myStack.push(temp);
	}
	cout << myStack.top();
	myStack.pop();
	while (!myStack.empty()) {
		cout << " " << myStack.top();
		myStack.pop();
	}
	cout << endl;

	return 0;
}
// 64 位输出请用 printf("%lld")

提交结果：