LeetCode //C - 219. Contains Duplicate II

219. Contains Duplicate II

Given an integer array nums and an integer k , return true if there are two distinct indices i and j in the array such that nums[i] == nums[j] and abs(i - j) <= k .

Example 1:

Input: nums = [1,2,3,1], k = 3
Output: true

Example 2:

Input: nums = [1,0,1,1], k = 1
Output: true

Example 3:

Input: nums = [1,2,3,1,2,3], k = 2
Output: false

Constraints:

  • 1 < = n u m s . l e n g t h < = 1 0 5 1 <= nums.length <= 10^5 1<=nums.length<=105
  • − 1 0 9 < = n u m s [ i ] < = 1 0 9 -10^9 <= nums[i] <= 10^9 −109<=nums[i]<=109
  • 0 < = k < = 1 0 5 0 <= k <= 10^5 0<=k<=105

From: LeetCode

Link: 219. Contains Duplicate II


Solution:

Ideas:
  1. Structure Definition: A structure Number is defined to store two integers: the value of an element from the nums array and its original index in the array.

  2. Array Initialization: An array numbers of type Number is created and initialized with the values and corresponding indices from the input array nums.

  3. Sorting: The numbers array is sorted by the values using the qsort function. The compare function is used to define the sorting order, which is based on the value field of the structure. After sorting, elements with the same value will be adjacent to each other, and their original indices can still be accessed.

  4. Scanning for Duplicates: The sorted numbers array is then scanned to find adjacent pairs with the same value. If such a pair is found, the original indices are checked to see if the absolute difference between them is less than or equal to k. If this condition is met, the function returns true.

  5. Memory Cleanup: The dynamically allocated memory for the numbers array is freed before exiting the function.

  6. Result: If no such pair is found that meets the condition, the function returns false.

By sorting the numbers and keeping track of the original indices, this approach efficiently checks for duplicates within the specified range k. The sorting ensures that the same values are grouped together, making it easy to check the condition without needing a hash table.

Code:
c 复制代码
typedef struct {
    int value;
    int index;
} Number;

int compare(const void *a, const void *b) {
    return ((Number*)a)->value - ((Number*)b)->value;
}

bool containsNearbyDuplicate(int* nums, int numsSize, int k) {
    if (k == 0 || numsSize <= 1) return false;
    
    Number* numbers = (Number*)malloc(numsSize * sizeof(Number));
    for (int i = 0; i < numsSize; i++) {
        numbers[i].value = nums[i];
        numbers[i].index = i;
    }
    
    qsort(numbers, numsSize, sizeof(Number), compare);
    
    for (int i = 0; i < numsSize - 1; i++) {
        if (numbers[i].value == numbers[i + 1].value && 
            abs(numbers[i].index - numbers[i + 1].index) <= k) {
            free(numbers);
            return true;
        }
    }
    
    free(numbers);
    return false;
}
相关推荐
橙几9 分钟前
击败了90%的解法?Two Sum 从 O(n²) 到 O(n) 的优化之路
算法
叶子爱分享23 分钟前
经典排序算法之归并排序(Merge Sort)
算法·排序算法
珹洺29 分钟前
C++算法竞赛篇:DevC++ 如何进行debug调试
java·c++·算法
Norvyn_738 分钟前
LeetCode|Day18|20. 有效的括号|Python刷题笔记
笔记·python·leetcode
呆呆的小鳄鱼1 小时前
leetcode:冗余连接 II[并查集检查环][节点入度]
算法·leetcode·职场和发展
墨染点香1 小时前
LeetCode Hot100【6. Z 字形变换】
java·算法·leetcode
沧澜sincerely1 小时前
排序【各种题型+对应LeetCode习题练习】
算法·leetcode·排序算法
CQ_07121 小时前
自学力扣:最长连续序列
数据结构·算法·leetcode
弥彦_1 小时前
cf1925B&C
数据结构·算法
Y4090012 小时前
C语言转Java语言,相同与相异之处
java·c语言·开发语言·笔记