D - Zero Array

You are given an array a_1, a_2, \ldots, a_na1​,a2​,...,an​.

In one operation you can choose two elements a_iai​ and a_jaj​ (i \ne ji=j) and decrease each of them by one.

You need to check whether it is possible to make all the elements equal to zero or not.

Input

The first line contains a single integer nn (2 \le n \le 10^52≤n≤105) --- the size of the array.

The second line contains nn integers a_1, a_2, \ldots, a_na1​,a2​,...,an​ (1 \le a_i \le 10^91≤ai​≤109) --- the elements of the array.

Output

Print "YES" if it is possible to make all elements zero, otherwise print "NO".

Sample 1

Inputcopy Outputcopy
4 1 1 2 2 YES

Sample 2

Inputcopy Outputcopy
6 1 2 3 4 5 6 NO

Note

In the first example, you can make all elements equal to zero in 33 operations:

  • Decrease a_1a1 and a_2a2,
  • Decrease a_3a3 and a_4a4,
  • Decrease a_3a3 and a_4a4

In the second example, one can show that it is impossible to make all elements equal to zero.

复制代码
#include<iostream>
#include<algorithm>
using namespace std;
typedef long long ll;
ll n;
ll sum = 0;
int main()
{
	ll maxnum = 0;
	cin >> n;
	for (ll i = 0; i < n; i++)
	{
		ll num;
		cin >> num;
		sum += num;
		maxnum = max(maxnum, num);
	}
	//因为是成对成对的减少,所以总数首先是偶数。其次还要满足最大的数小于等于总数的一半,这样才能保证最大的数消去
	if (sum % 2 == 0&&maxnum <= sum / 2) cout << "YES" << endl;
	else cout << "NO" << endl;
}
相关推荐
Dream it possible!12 小时前
LeetCode 面试经典 150_多维动态规划_交错字符串(97_C++_中等)
算法·leetcode·面试·动态规划
心抵鹊12 小时前
算法之双指针系列(一)
算法·leetcode
十二12 小时前
【洛谷题解】P1083 [NOIP 2012 提高组] 借教室(二分答案 + 差分)
数据结构·c++·算法·蓝桥杯
小此方13 小时前
[算法实战论:动态规划]回文串问题的dp解法,回文串问题的母题,以及以此为基础的派生题
算法·动态规划
Pniubi14 小时前
力扣560.和为k的子数组
算法·leetcode·职场和发展
D e re k ZH14 小时前
C++ 从零入门(一):基础语法与程序结构
数据结构·c++·算法
Pniubi15 小时前
力扣438.找到字符串中所有字母异位词
算法·leetcode·职场和发展
東隅已逝,桑榆非晚17 小时前
算法6. 双指针法-查找总价格为目标的两个商品
c++·学习·算法
Eyfcom18 小时前
〖物联网终端实战 01〗UWB 室内高精度定位:仓储 AGV 与人员的厘米级轨迹追踪
物联网·算法·物流系统·快递系统·跨境物流快递系统·物联网终端实战
bro_Java66618 小时前
《排序的底层逻辑:比较、交换与分治》
java·算法·排序算法