面试经典150题——Day15

文章目录

一、题目

135. Candy

There are n children standing in a line. Each child is assigned a rating value given in the integer array ratings.

You are giving candies to these children subjected to the following requirements:

Each child must have at least one candy.

Children with a higher rating get more candies than their neighbors.

Return the minimum number of candies you need to have to distribute the candies to the children.

Example 1:

Input: ratings = 1,0,2

Output: 5

Explanation: You can allocate to the first, second and third child with 2, 1, 2 candies respectively.

Example 2:

Input: ratings = 1,2,2

Output: 4

Explanation: You can allocate to the first, second and third child with 1, 2, 1 candies respectively.

The third child gets 1 candy because it satisfies the above two conditions.

Constraints:

n == ratings.length

1 <= n <= 2 * 104

0 <= ratingsi <= 2 * 104

题目来源:leetcode

二、题解

每次处理一边的情况

cpp 复制代码
class Solution {
public:
    int candy(vector<int>& ratings) {
        int n = ratings.size();
        vector<int> candies(n,1);
        //右边比左边大的情况
        for(int i = 1;i < n;i++){
            if(ratings[i] > ratings[i-1]) candies[i] = candies[i-1] + 1;
        }
        //左边比右边大的情况
        for(int i = n - 2;i >= 0;i--){
            if(ratings[i] > ratings[i+1]) candies[i] = max(candies[i],candies[i+1] + 1);
        }
        int res = 0;
        for(int i = 0;i < n;i++){
            res += candies[i];
        }
        return res;
    }
};
相关推荐
QiLinkOS8 小时前
第三视觉理解徐玉生与他的商业活动(30)
大数据·c++·人工智能·算法·开源协议
mit6.8248 小时前
阅读的核心,是再读
c++
疯狂打码的少年8 小时前
【操作系统】页面置换算法(OPT/FIFO/LRU)
算法
小O的算法实验室8 小时前
2026年CIE,优化客货协同运输:综合地铁系统的列车容量动态分配
算法
Coder_Shenshen9 小时前
西门子S7CommPlus协议鉴权算法原理与流程详解
网络·后端·算法
硕风和炜10 小时前
【LeetCode: 2492. 两个城市间路径的最小分数 + DFS】
java·算法·leetcode·深度优先·dfs·bfs·并查集
upgrador10 小时前
基础知识:C++ STL构造函数的左闭右开惯例及其实现原理
开发语言·c++
我是一颗柠檬11 小时前
【Java项目技术亮点】加权轮询负载均衡算法
java·算法·负载均衡
灯厂码农11 小时前
C语言动态内存分配完全指南(malloc、calloc、realloc、free)
java·c语言·算法
凯瑟琳.奥古斯特12 小时前
K次取反最大化数组和解法(力扣1005)
开发语言·c++·算法·leetcode·职场和发展