mysql作业

数据表介绍

--1.学生表

Student(SId,Sname,Sage,Ssex)

--SId 学生编号,Sname 学生姓名,Sage 出生年月,Ssex 学生性别

--2.课程表

Course(CId,Cname,TId)

--CId 课程编号,Cname 课程名称,TId 教师编号

--3.教师表

Teacher(TId,Tname)

--TId 教师编号,Tname 教师姓名

--4.成绩表

SC(SId,CId,score)

--SId 学生编号,CId 课程编号,score 分数

学生表 Student

create table Student(SId varchar(10),Sname varchar(10),Sage datetime,Ssex varchar(10));

insert into Student values('01' , '赵雷' , '1990-01-01' , '男');

insert into Student values('02' , '钱电' , '1990-12-21' , '男');

insert into Student values('03' , '孙风' , '1990-12-20' , '男');

insert into Student values('04' , '李云' , '1990-12-06' , '男');

insert into Student values('05' , '周梅' , '1991-12-01' , '女');

insert into Student values('06' , '吴兰' , '1992-01-01' , '女');

insert into Student values('07' , '郑竹' , '1989-01-01' , '女');

insert into Student values('09' , '张三' , '2017-12-20' , '女');

insert into Student values('10' , '李四' , '2017-12-25' , '女');

insert into Student values('11' , '李四' , '2012-06-06' , '女');

insert into Student values('12' , '赵六' , '2013-06-13' , '女');

insert into Student values('13' , '孙七' , '2014-06-01' , '女');

科目表 Course

create table Course(CId varchar(10),Cname nvarchar(10),TId varchar(10));

insert into Course values('01' , '语文' , '02');

insert into Course values('02' , '数学' , '01');

insert into Course values('03' , '英语' , '03');

教师表 Teacher

create table Teacher(TId varchar(10),Tname varchar(10));

insert into Teacher values('01' , '张三');

insert into Teacher values('02' , '李四');

insert into Teacher values('03' , '王五');

成绩表 SC

create table SC(SId varchar(10),CId varchar(10),score decimal(18,1));

insert into SC values('01' , '01' , 80);

insert into SC values('01' , '02' , 90);

insert into SC values('01' , '03' , 99);

insert into SC values('02' , '01' , 70);

insert into SC values('02' , '02' , 60);

insert into SC values('02' , '03' , 80);

insert into SC values('03' , '01' , 80);

insert into SC values('03' , '02' , 80);

insert into SC values('03' , '03' , 80);

insert into SC values('04' , '01' , 50);

insert into SC values('04' , '02' , 30);

insert into SC values('04' , '03' , 20);

insert into SC values('05' , '01' , 76);

insert into SC values('05' , '02' , 87);

insert into SC values('06' , '01' , 31);

insert into SC values('06' , '03' , 34);

insert into SC values('07' , '02' , 89);

insert into SC values('07' , '03' , 98);


练习题目

  1. 查询" 01 "课程比" 02 "课程成绩高的学生的信息及课程分数 select *

    from student as a

    right join sc as b

    on a.sid=b.sid

    inner join sc as c

    on a.sid=c.sid and b.cid=01 and c.cid=02

    where b.score>c.score;

1.1查询同时存在" 01 "课程和" 02 "课程的情况

select *

from sc as a

inner join sc as b

on a.sid=b.sid and a.cid='01' and b.cid='02';

1.2查询存在" 01 "课程但可能不存在" 02 "课程的情况(不存在时显示为 null )

select *

from sc as a

left join sc as b

on a.sid=b.sid and b.cid='02'

where a.cid = '01';

1.3查询不存在" 01 "课程但存在" 02 "课程的情况

select *

from sc

where sid not in (select sid from sc where cid='01')

and cid ='02';

2.查询平均成绩大于等于 60 分的同学的学生编号和学生姓名和平均成绩

select a.sid,a.sname,avg(b.score) as s_avg

from student as a

right join sc as b

on a.sid=b.sid

group by b.sid

having s_avg>60;

3.查询在 SC 表存在成绩的学生信息

select a.*

from student as a

right join sc as b

on a.sid=b.sid

group by b.sid;

4.查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩(没成绩的显示为 null )

select a.sid,a.sname,count(b.cid) as c_sum,sum(b.score) as s_sum

from student as a

left join sc as b

on a.sid=b.sid

group by a.sid;

4.1 查有成绩的学生信息

select * from student

where sid in(select distinct sid from sc);

5.查询「李」姓老师的数量

select count(*)

from teacher

where tname like '李%';

6.查询学过「张三」老师授课的同学的信息

select student.*

from teacher,course,sc,student

where teacher.tname = '张三'

and teacher.tid=course.tid

and course.cid=sc.cid

and sc.sid=student.sid;

7.查询没有学全所有课程的同学的信息

select a.*,count(cid) as c_count

from student as a

inner join sc as b

on a.sid=b.sid

group by a.sid

having c_count<(select count(cid) from course);

8.查询至少有一门课与学号为" 01 "的同学所学相同的同学的信

select cid from sc where sid = '01';

select * from student where sid in(

select distinct sid from sc

where cid in(select cid from sc where sid = '01'));

9.查询和" 01 "号的同学学习的课程 完全相同的其他同学的信息

select * from student where sid in(

select a.sid from (select sid,group_concat(cid order by cid) as courses

from sc group by sid) as a

inner join (select sid,group_concat(cid order by cid) as courses

from sc group by sid having sid='01') as b

on a.sid != 1 and a.courses = b.courses);

10.查询没学过"张三"老师讲授的任一门课程的学生姓名

select distinct sname from student where sid not in(

select sid from sc where cid in(

select a.cid from course as a

inner join teacher as b

on a.tid=b.tid

where b.tname = '张三' ));

11.查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩

select student.SId, student.Sname,b.avg

from student RIGHT JOIN

(select sid, AVG(score) as avg from sc

where sid in (

select sid from sc

where score<60

GROUP BY sid

HAVING count(score)>1)

GROUP BY sid) b on student.sid=b.sid;

12.检索" 01 "课程分数小于 60,按分数降序排列的学生信息

select student.*, sc.score from student, sc

where student.sid = sc.sid

and sc.score < 60

and cid = "01"

ORDER BY sc.score DESC;

13.按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩

select * from sc

left join (

select sid,avg(score) as avscore from sc

group by sid

)r

on sc.sid = r.sid

order by avscore desc;

14.查询各科成绩最高分、最低分和平均分:

以如下形式显示:课程 ID,课程 name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率

及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90

要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列

15.按各科成绩进行排序,并显示排名, Score 重复时保留名次空缺

select a.cid, a.sid, a.score, count(b.score)+1 as rank

from sc as a

left join sc as b

on a.score<b.score and a.cid = b.cid

group by a.cid, a.sid,a.score

order by a.cid, rank ASC;

15.1 按各科成绩进行排序,并显示排名, Score 重复时合并名次

16.查询学生的总成绩,并进行排名,总分重复时保留名次空缺

set @crank=0;

select q.sid, total, @crank := @crank +1 as rank from(

select sc.sid, sum(sc.score) as total from sc

group by sc.sid

order by total desc)q;

16.1 查询学生的总成绩,并进行排名,总分重复时不保留名次空缺

17.统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[60-0] 及所占百分比

select course.cname, course.cid,

sum(case when sc.score<=100 and sc.score>85 then 1 else 0 end) as "[100-85]",

sum(case when sc.score<=85 and sc.score>70 then 1 else 0 end) as "[85-70]",

sum(case when sc.score<=70 and sc.score>60 then 1 else 0 end) as "[70-60]",

sum(case when sc.score<=60 and sc.score>0 then 1 else 0 end) as "[60-0]"

from sc left join course

on sc.cid = course.cid

group by sc.cid;

18.查询各科成绩前三名的记录

select * from sc

where (

select count(*) from sc as a

where sc.cid = a.cid and sc.score<a.score

)< 3

order by cid asc, sc.score desc;

19.查询每门课程被选修的学生数

select cid, count(sid) from sc group by cid;

20.查询出只选修两门课程的学生学号和姓名

select student.sid,student.sname from student,sc where student.sid=sc.sid group by sid having count(cid)=2;

21.查询男生、女生人数

select ssex,count(*) from student group by ssex;

22.查询名字中含有「风」字的学生信息

select * from student where sname like '%风%';

23.查询同名同性学生名单,并统计同名人数

24.查询 1990 年出生的学生名单

select * from student where year(sage)='1990';

25.查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列

select cid,avg(score) from sc group by cid order by avg(score) desc,cid asc;

26.查询平均成绩大于等于 85 的所有学生的学号、姓名和平均成绩

select student.sname,student.sid,avg(score) from student,sc where student.sid=sc.sid having avg(score)>=85 group by student.sid;

27.查询课程名称为「数学」,且分数低于 60 的学生姓名和分数

select score,sname from student,sc,course where student.sid=sc.sid and sc.cid=course.cid and cname='数学' and score<60;

28.查询所有学生的课程及分数情况(存在学生没成绩,没选课的情况)

select student.sname, cid, score from studentleft join sc on student.sid = sc.sid;

29.查询任何一门课程成绩在 70 分以上的姓名、课程名称和分数

select sname,cname,score from student,sc,course where student.sid=sc.sid and sc.cid=course.cid and score>70;

30.查询不及格的课程

select cname from sc,course where sc.cid=course.cid and score<60;

31.查询课程编号为 01 且课程成绩在 80 分以上的学生的学号和姓名

select student.sid,student.sname from student,sc,course where student.sid=sc.sid and sc.cid=course.cid and course.cid='01' and score>=80;

32.求每门课程的学生人数

select count(student.sid),cname from course,student,sc where student.sid=sc.sid and sc.cid=course.cid group by cname;

33.成绩不重复,查询选修「张三」老师所授课程的学生中,成绩最高的学生信息及其成绩

select distinct * from student,sc,teacher,course where student.sid=sc.sid and teacher.tid=course.tid and sc.cid=course.cid and teacher.tname='张三' having max(score);

34.成绩有重复的情况下,查询选修「张三」老师所授课程的学生中,成绩最高的学生信息及其成绩

select * from student,sc,teacher,course where student.sid=sc.sid and teacher.tid=course.tid and sc.cid=course.cid and teacher.tname='张三' having max(score);

35.查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩

36.查询每门功成绩最好的前两名

37.统计每门课程的学生选修人数(超过 5 人的课程才统计)。

select count(sid) from sc group by cid having count(sid)>=5;

38.检索至少选修两门课程的学生学号

select student.sid from student,sc where student.sid=sc.sid group by sid having count(cid)>=2;

39.查询选修了全部课程的学生信息

select student.* from student,sc where student.sid=sc.sid group by sid having count(cid)=3 ;

40.查询各学生的年龄,只按年份来算

select 2023-year(sage),sname from student;

41.按照出生日期来算,当前月日 < 出生年月的月日则,年龄减一

42.查询本周过生日的学生

select * from student where weekofyear(sage)=weekofyear(curdate());

43.查询下周过生日的学生

select * from student where weekofyear(sage)=weekofyear(curdate())+1;

44.查询本月过生日的学生

select * from student where month(sage)=month(curdate());

45.查询下月过生日的学生

select * from student where month(sage)=month(curdate())+1;

相关推荐
SomeB1oody3 分钟前
【Rust自学】5.3. struct的方法(Method)
开发语言·后端·rust
Amarantine、沐风倩✨33 分钟前
设计一个监控摄像头物联网IOT(webRTC、音视频、文件存储)
java·物联网·音视频·webrtc·html5·视频编解码·七牛云存储
dazhong20121 小时前
PLSQL 客户端连接 Oracle 数据库配置
数据库·oracle
Kisorge1 小时前
【C语言】指针数组、数组指针、函数指针、指针函数、函数指针数组、回调函数
c语言·开发语言
路在脚下@2 小时前
spring boot的配置文件属性注入到类的静态属性
java·spring boot·sql
森屿Serien2 小时前
Spring Boot常用注解
java·spring boot·后端
轻口味2 小时前
命名空间与模块化概述
开发语言·前端·javascript
苹果醋33 小时前
React源码02 - 基础知识 React API 一览
java·运维·spring boot·mysql·nginx
晓纪同学3 小时前
QT-简单视觉框架代码
开发语言·qt
威桑3 小时前
Qt SizePolicy详解:minimum 与 minimumExpanding 的区别
开发语言·qt·扩张策略