文章目录
一、发现问题
在一次准备处理历史数据sql时,出现这么一个问题:You can't specify target table '表名' for update in FROM clause
,大致的意思就是:不能在同一张表中先select再update。
在此进行一下复盘沉淀,使用测试sql复现当时的场景(mysql是8版本),准备测试数据:
sql
CREATE TABLE `student` (
`id` int NOT NULL,
`name` varchar(255) DEFAULT NULL,
`address` varchar(255) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_0900_ai_ci;
INSERT INTO `athena_opencourse`.`student`(`id`, `name`, `address`) VALUES (1, '张三', '北京');
INSERT INTO `athena_opencourse`.`student`(`id`, `name`, `address`) VALUES (2, '李四', '上海');
二、场景1:在where条件中查询了修改表的数据
sql
update student set address = '杭州'
where id in (select id from student where name = '张三');
delete from student
where id in (select id from student where name = '张三');
此时会提示:1093 - You can't specify target table 'student' for update in FROM clause
解决方式:在where子句中再加一层,使其成为临时表:
sql
update student set address = '杭州'
where id in (select tmp.id from (select id from student where name = '张三') tmp);
三、场景2:在set语句中查询了修改表的数据
sql
update student set address = (select address from student where name = '李四')
where name = '张三';
此时,一样的报错:> 1093 - You can't specify target table 'student' for update in FROM clause
解决方式同上,查询时再加一层,使其成为临时表:
sql
update student set address = (select tmp.address from (select address from student where name = '李四') tmp)
where name = '张三';
或者使用update join的方案:
sql
update student s1 ,student s2
set s1.address = s2.address
where s1.name = '张三' and s2.name = '李四';
惊呆了有木有!使用update join语法,可以很轻松的实现跨表的数据修改。
当然,上面的例子中,两个表之间的数据并没有关联关系,如果有关联关系的话,比如说同一个id更新相同的数据,可以使用left join on的语法:
sql
update student s1
left join student s2 on s1.id = s2.id
set s1.address = s2.name;