scala 实现表达式解析

表达式解析

scala 复制代码
import org.junit.Test

import scala.collection.mutable

class ExprTestCase {


  private val orderSource = "source_1"
  private val saleChannel = "saleChannel"
  val datas = new mutable.HashMap[String, String]();
  //  p1, source1, sale1, source_1 & ( sale_channel_1 | sq )"
  datas.put("source_1", "source_1");
  datas.put("saleChannel", "saleChannel");
  datas.put("orderSource", "orderSource");

  val expr = s"orderSource:source_1 & ( saleChannel:saleChannel | orderSource:orderSource )"

  private val tokens: Array[String] = expr.split("\\s+")

  private val optStack = new mutable.ArrayStack[String]()
  private val memberStatck = new mutable.ArrayStack[String]()
  private var flag = false;

  def matchFiled(fieldName: String): String = {
    fieldName match {
      case "orderSource" => orderSource
      case "saleChannel" => saleChannel
      case _ => throw new IllegalArgumentException(s"unknown filed name: ${fieldName}, it's  can only be 'orderSource' or 'saleChannel'")
    }
  }

  @Test
  def expParseTestCase() = {

    var opt = ""

    def exprProcess = {
      if (opt == "" || opt == "(") opt = optStack.pop()
      while (opt != null && opt != "(" && memberStatck.nonEmpty) {
        opt match {
          case "|" => {
            if(memberStatck.size > 1) {
              val m1 = memberStatck.pop().split(":")
              val m2 = memberStatck.pop().split(":")
              flag = datas.getOrElse(m2(1), "N").eq(matchFiled(m2(0))) || datas.getOrElse(m1(1), "N").eq(matchFiled(m1(0)))
              println(
                s"""
                [&]: ${datas.getOrElse(m2(1), "N")}.eq("${matchFiled(m2(0))}") || ${datas.getOrElse(m1(1), "N")}.eq("${matchFiled(m1(0))}")
                """)
            } else {
              val m1 = memberStatck.pop().split(":")
              flag = flag || datas.getOrElse(m1(1), "N").eq(matchFiled(m1(0)))
              println(
                s"""
                [&]: ${flag} || ${datas.getOrElse(m1(1), "N")}.eq("${matchFiled(m1(0))}
                """)
            }
          }
          case "&" => {
            if (memberStatck.size > 1) {
              val m1 = memberStatck.pop().split(":")
              val m2 = memberStatck.pop().split(":")
              flag = datas.getOrElse(m1(1), "N").equals(matchFiled(m1(0))) && datas.getOrElse(m2(1), "N").equals(matchFiled(m2(0)))
              println(
                s"""
                [&]: ${datas.getOrElse(m1(1), "N")}.eq("${matchFiled(m1(0))}") && ${datas.getOrElse(m2(1), "N")}.eq("${matchFiled(m2(0))}")
                """)
            } else {
              val m1 = memberStatck.pop().split(":")
              flag = flag && datas.getOrElse(m1(1), "N").equals(matchFiled(m1(0)))
              println(
                s"""
                [&]: ${false} && ${datas.get(m1(1))}.eq("$saleChannel")}.eq("${matchFiled(m1(0))}")
                """)
            }
          }
        }
        if (optStack.nonEmpty) opt = optStack.pop()
      }
    }

    tokens.foreach {
      case ")" => {
        exprProcess
      }
      case token@("|" | "&" | "(") => {
        optStack.push(token)
      }
      case token => {
        memberStatck.push(token)
      }
    }

    println("expr match complete :) ")
    if(memberStatck.nonEmpty) {
      exprProcess
    }

    println(flag)
    println(optStack)
    println(memberStatck)

  }

}

输出

log 复制代码
                [&]: saleChannel.eq("saleChannel") || orderSource.eq("source_1")
                
expr match complete :) 

                [&]: false && Some(source_1).eq("saleChannel")}.eq("source_1")
                
true
ArrayStack()
ArrayStack()
相关推荐
近津薪荼1 分钟前
优选算法——分治(2):快速选择
算法
Z...........1 分钟前
(优选算法)斐波那契数列模型
数据结构·算法
于先生吖18 分钟前
国际版JAVA婚恋交友系统源码:多语言适配,可商用的跨境婚恋解决方案
java·大数据·交友
zyjyyds11319 分钟前
和为0的四元组-双指针法(C语言实现)
c语言·数据结构·算法
fengci.29 分钟前
ctfshow(web入门)279-286
java·开发语言·学习
fy1216330 分钟前
navicat15安装破解
java
炽烈小老头34 分钟前
【每天学习一点算法 2026/03/16】电话号码的字母组合
学习·算法
ok_hahaha35 分钟前
java从头开始-苍穹外卖day05-Redis及店铺营业状态设置
java·开发语言·redis
Lee川1 小时前
时空迷宫探险记:从O(1)到O(2^n)的算法进化论
算法·面试