LeetCode475. Heaters

文章目录

一、题目

Winter is coming! During the contest, your first job is to design a standard heater with a fixed warm radius to warm all the houses.

Every house can be warmed, as long as the house is within the heater's warm radius range.

Given the positions of houses and heaters on a horizontal line, return the minimum radius standard of heaters so that those heaters could cover all houses.

Notice that all the heaters follow your radius standard, and the warm radius will the same.

Example 1:

Input: houses = 1,2,3, heaters = 2

Output: 1

Explanation: The only heater was placed in the position 2, and if we use the radius 1 standard, then all the houses can be warmed.

Example 2:

Input: houses = 1,2,3,4, heaters = 1,4

Output: 1

Explanation: The two heaters were placed at positions 1 and 4. We need to use a radius 1 standard, then all the houses can be warmed.

Example 3:

Input: houses = 1,5, heaters = 2

Output: 3

Constraints:

1 <= houses.length, heaters.length <= 3 * 104

1 <= housesi, heatersi <= 109

二、题解

双指针,i和j分别从houses和heaters的索引从左向右移动。

cpp 复制代码
class Solution {
public:
    int findRadius(vector<int>& houses, vector<int>& heaters) {
        sort(houses.begin(),houses.end());
        sort(heaters.begin(),heaters.end());
        int res = 0;
        for(int i = 0,j = 0;i < houses.size();i++){
            while(!best(houses,heaters,i,j)) j++;
            res = max(res,abs(houses[i]-heaters[j]));
        }
        return res;
    }
    bool best(vector<int>& houses,vector<int>& heaters,int i,int j){
        if(j == heaters.size() - 1) return true;
        else if(abs(houses[i]-heaters[j]) < abs(houses[i]-heaters[j + 1])) return true;
        else return false;
    }
};
相关推荐
hanlin0312 小时前
刷题笔记:力扣第32题-最长有效括号
笔记·算法·leetcode
一拳一个呆瓜13 小时前
【STL】文件系统导航
c++·stl
All for pursuit.13 小时前
【动态规划-21】312.戳气球
数据结构·c++·算法·leetcode·动态规划
栈帧之外13 小时前
【C++】STL之set
开发语言·c++
zhanghaha131414 小时前
C++构造函数的一些其他应用(逐词逐句保姆讲解)
c++
jimy115 小时前
c++的 Type Traits (二、更详细版本)
开发语言·c++
碧海银沙音频科技研究院15 小时前
基于炬芯ATS3089X自研AEC声学回声消除算法
算法
通问AI15 小时前
在两台 Mac Studio 上跑 800B 模型:MLX + RDMA over Thunderbolt 实测与四道门选型法
算法
ZywOo62315 小时前
《算法竞赛进阶指南》0x03 前缀和与差分
算法
Scintilla_y16 小时前
DAY2 滑动窗口
算法·leetcode·散列表