R语言【taxa】——roots(),stems(),subtaxa(),supertaxa():获取根节点、茎节点、子类群和父类群

roots(x, subset = NULL)

在 taxonomy 中查找根节点类群的索引值。

复制代码
> x <- taxonomy(c('Carnivora', 'Felidae', 'Panthera', 'Panthera leo',
+                 'Panthera tigris', 'Ursidae', 'Ursus', 'Ursus arctos'),
+               supertaxa = c(NA, 1, 2, 3, 3, 1, 6, 7))

> roots(x)
[1] 1

> roots(x, subset = 2:8)
[1] 2 6

stems(x, value = NULL, ...)

返回每个类群的茎节点的索引值。

复制代码
> x <- taxonomy(c('Carnivora', 'Felidae', 'Panthera', 'Panthera leo',
+                 'Panthera tigris'),
+               supertaxa = c(NA, 1, 2, 3, 3))
> x <- c(x, x)

> stems(x)
[[1]]
[1] 1 2

[[2]]
[1] 6 7

> stems(x, value = tax_name(x))
[[1]]
[1] "Carnivora" "Felidae"  

[[2]]
[1] "Carnivora" "Felidae"  

> x
<taxonomy[10]>
1: Carnivora
└─2: Felidae
  └─3: Panthera
    ├─4: Panthera leo
    └─5: Panthera tigris
6: Carnivora
└─7: Felidae
  └─8: Panthera
    ├─9: Panthera leo
    └─10: Panthera tigris

subtaxa(x, subset = NULL, max_depth = NULL, include = FALSE, value = NULL, ...)

返回所有子类群的索引值。

Generate example data

x <- taxonomy(c('Carnivora', 'Felidae', 'Panthera', 'Panthera leo',
'Panthera tigris', 'Ursidae', 'Ursus', 'Ursus arctos'),
supertaxa = c(NA, 1, 2, 3, 3, 1, 6, 7))

The indexes of all subtaxa (with subtaxa of subtaxa, etc) for each taxon

subtaxa(x)

The indexes of immediate subtaxa (without subtaxa of subtaxa, etc) for each taxon

subtaxa(x, max_depth = 1)

Return something other than index

subtaxa(x, value = tax_name(x))

Include each taxon with its subtaxa

subtaxa(x, value = tax_name(x), include = TRUE)

Only return data for some taxa (faster than subsetting the whole result)

subtaxa(x, subset = 3)


supertaxa( x, subset = NULL, max_depth = NULL, include = FALSE, value = NULL, use_na = FALSE, ... )

返回所有父类群的索引值。

Generate example data

x <- taxonomy(c('Carnivora', 'Felidae', 'Panthera', 'Panthera leo',
'Panthera tigris', 'Ursidae', 'Ursus', 'Ursus arctos'),
supertaxa = c(NA, 1, 2, 3, 3, 1, 6, 7))

The indexes of all supertaxa (with supertaxa of supertaxa, etc) for each taxon

supertaxa(x)

Return something other than index

supertaxa(x, value = tax_name(x))

Include each taxon with its supertaxa

supertaxa(x, value = tax_name(x), include = TRUE)

Only return data for some taxa (faster than subsetting the whole result)

supertaxa(x, subset = 3)

相关推荐
初学者,亦行者1 分钟前
Rayon并行迭代器:原理、实践与性能优化
java·开发语言·spring·rust
我想进大厂14 分钟前
Python---数据容器(Set 集合)
开发语言·python
wu_jing_sheng01 小时前
销售数据分析
开发语言·python
haofafa1 小时前
STL之动态数组
开发语言·c++
earthzhang20212 小时前
【2051】【例3.1】偶数
开发语言·数据结构·算法·青少年编程·图论
专注VB编程开发20年2 小时前
.NET Reflector反编绎,如何移除DLL中的一个公开属性
开发语言·c++·c#
vxiam14xxx2 小时前
【Java Swing 项目】java 聊天系统
java·开发语言·python
znhy@1233 小时前
十三、JS进阶(二)
开发语言·前端·javascript
@木辛梓3 小时前
Linux 线程
linux·开发语言·c++
孤独的追光者4 小时前
使用Qt Designer开发上位机
开发语言·python·qt