37. 解数独

编写一个程序,通过填充空格来解决数独问题。

数独的解法需遵循如下规则:

  1. 数字 1-9 在每一行只能出现一次。
  2. 数字 1-9 在每一列只能出现一次。
  3. 数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。(请参考示例图)

数独部分空格内已填入了数字,空白格用 '.' 表示。

示例 1:

复制代码
输入:board = [["5","3",".",".","7",".",".",".","."],["6",".",".","1","9","5",".",".","."],[".","9","8",".",".",".",".","6","."],["8",".",".",".","6",".",".",".","3"],["4",".",".","8",".","3",".",".","1"],["7",".",".",".","2",".",".",".","6"],[".","6",".",".",".",".","2","8","."],[".",".",".","4","1","9",".",".","5"],[".",".",".",".","8",".",".","7","9"]]
输出:[["5","3","4","6","7","8","9","1","2"],["6","7","2","1","9","5","3","4","8"],["1","9","8","3","4","2","5","6","7"],["8","5","9","7","6","1","4","2","3"],["4","2","6","8","5","3","7","9","1"],["7","1","3","9","2","4","8","5","6"],["9","6","1","5","3","7","2","8","4"],["2","8","7","4","1","9","6","3","5"],["3","4","5","2","8","6","1","7","9"]]
解释:输入的数独如上图所示,唯一有效的解决方案如下所示:

提示:

  • board.length == 9
  • board[i].length == 9
  • board[i][j] 是一位数字或者 '.'
  • 题目数据 保证 输入数独仅有一个解
java 复制代码
    public boolean solveSudoku(char[][] board) {
        for (int i = 0; i < 9; i++) {
            for (int j = 0; j < 9; j++) {
                如果为空格就依次把1-9填入
                if (board[i][j] == '.') {
                    for (char k = '1'; k <= '9'; k++) {
                        // 判断填入的数字是否合法
                        if (isValid(i, j, k, board)) {
                            board[i][j] = k;
                            // 递归
                            boolean result = solveSudoku(board);
                            if(result == true)  
                                return true;
                            board[i][j]='.';  //不合法就回溯,回溯前先重新赋值为空
                        }
                    }
                    // 填写完成后返回
                    return false;
                }
            }
        }
        return true;
    }

    /**
     * 判断放入棋盘的数字是否合法
     */
    public boolean isValid(int row, int col, char val, char[][] board) {
        // 验证一行
        for (int i = 0; i < 9; i++) { // 判断行里是否重复
            if (board[row][i] == val) {
                return false;
            }
        }

        // 验证一列
        for (int j = 0; j < 9; j++) { // 判断行里是否重复
            if (board[j][col] == val) {
                return false;
            }
        }

        //    验证3*3
        int startRow = (row / 3) * 3;
        int startCol = (col / 3) * 3;
        for (int i = startRow; i < startRow + 3; i++) { // 判断9方格里是否重复
            for (int j = startCol; j < startCol + 3; j++) {
                if (board[i][j] == val ) {
                    return false;
                }
            }
        }
        return true;
    }
相关推荐
我可能是个假开发3 小时前
FTP Unicode 文件名导致 `550` 的问题分析与解决方案
java·开发语言·spring
WL学习笔记4 小时前
日期类(C++)
开发语言·c++·日期类实现
谢亮_vipxieliang5 小时前
Go map与结构体的正确使用
开发语言·golang·哈希算法
H.莓飛5 小时前
【C++】命名空间、缺省参数、函数重载与引用
linux·开发语言·c++·visual studio
xxwl5855 小时前
数据结构知识点和代码实现总结(C语言实现)
c语言·开发语言·数据结构
lerhxx6 小时前
AI 应用如何高效优雅地恢复中断?—— "连接解耦 + 状态持久化"
前端·javascript
mantou1328 小时前
我给 AI Agent 做了个「油猴」:让 Claude Code / Codex 直接用你已登录的浏览器
前端·javascript·后端
默_笙8 小时前
🍕 一个主编、三个工种、两本手册:搭一支 AI 调研队
前端·javascript
code2cat8 小时前
Java进阶篇之AtomicMarkableReference:引用还在,标记已经改变
java·开发语言·cas·并发编程·逻辑删除
CappuccinoRose9 小时前
FormData数据处理
开发语言·前端·javascript·表单数据