Postgresql获取指定时间前的时间

Best_Liu~2024-04-18 21:21

1、获取指定时间前12小时数据

sql 复制代码

SELECT
	* 
FROM
	dispatch_team_real 
WHERE
	to_timestamp( start_time, 'YYYY-MM-DD HH24:MI:SS' ) = ( to_timestamp( '2023-09-17 06:00:00', 'YYYY-MM-DD HH24:MI:SS' ) - INTERVAL '12 HOUR' ) 
	AND to_timestamp( end_time, 'YYYY-MM-DD HH24:MI:SS' ) = ( to_timestamp( '2023-09-17 18:00:00', 'YYYY-MM-DD HH24:MI:SS' ) - INTERVAL '12 HOUR' );

2、获取当前时间之前10s的数据

sql 复制代码

SELECT
	* 
FROM
	dispatch_team_real 
WHERE
	to_timestamp( start_time, 'YYYY-MM-DD HH24:MI:SS' ) = ( now() - INTERVAL '10 seconds' ) ;

3、获取当前时间前10分钟的数据

sql 复制代码

SELECT
	* 
FROM
	dispatch_team_real 
WHERE
	to_timestamp( start_time, 'YYYY-MM-DD HH24:MI:SS' ) = ( now() - INTERVAL '10 minutes' ) ;

4、获取当前时间前10天的数据

sql 复制代码

SELECT
	* 
FROM
	dispatch_team_real 
WHERE
	to_timestamp( start_time, 'YYYY-MM-DD HH24:MI:SS' ) = ( now() - INTERVAL '10 days' ) ;

5、获取当前时间前10月的数据

sql 复制代码

SELECT
	* 
FROM
	dispatch_team_real 
WHERE
	to_timestamp( start_time, 'YYYY-MM-DD HH24:MI:SS' ) = ( now() - INTERVAL '10 months' ) ;

6、获取当前时间前10年的数据

sql 复制代码

SELECT
	* 
FROM
	dispatch_team_real 
WHERE
	to_timestamp( start_time, 'YYYY-MM-DD HH24:MI:SS' ) = ( now() - INTERVAL '10 years' ) ;