Design your implementation of the linked list. You can choose to use a singly or doubly linked list.
A node in a singly linked list should have two attributes: val and next. val is the value of the current node, and next is a pointer/reference to the next node.
If you want to use the doubly linked list, you will need one more attribute prev to indicate the previous node in the linked list. Assume all nodes in the linked list are 0-indexed.
Implement the MyLinkedList class:
MyLinkedList()Initializes theMyLinkedListobject.int get(int index)Get the value of theindexthnode in the linked list. If the index is invalid, return-1.void addAtHead(int val)Add a node of valuevalbefore the first element of the linked list. After the insertion, the new node will be the first node of the linked list.void addAtTail(int val)Append a node of valuevalas the last element of the linked list.void addAtIndex(int index, int val)Add a node of valuevalbefore theindexthnode in the linked list. Ifindexequals the length of the linked list, the node will be appended to the end of the linked list. Ifindexis greater than the length, the node will not be inserted.void deleteAtIndex(int index)Delete theindexthnode in the linked list, if the index is valid.
Example 1:
Input ["MyLinkedList", "addAtHead", "addAtTail", "addAtIndex", "get", "deleteAtIndex", "get"] [[], [1], [3], [1, 2], [1], [1], [1]] Output [null, null, null, null, 2, null, 3] Explanation MyLinkedList myLinkedList = new MyLinkedList(); myLinkedList.addAtHead(1); myLinkedList.addAtTail(3); myLinkedList.addAtIndex(1, 2); // linked list becomes 1->2->3 myLinkedList.get(1); // return 2 myLinkedList.deleteAtIndex(1); // now the linked list is 1->3 myLinkedList.get(1); // return 3
Constraints:
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0 <= index, val <= 1000 -
Please do not use the built-in LinkedList library.
-
At most
2000calls will be made toget,addAtHead,addAtTail,addAtIndexanddeleteAtIndex.class MyLinkedList {
public:
struct ListNode
{
int val;
ListNode*next;
ListNode(int val):val(val),next(nullptr){}
};
//初始化链表
MyLinkedList() {
_dummyHead=new ListNode(0);
_size=0;
}int get(int index) { if(index<0 || index>(_size-1))return -1; ListNode*curr=_dummyHead->next; while(index--)curr=curr->next; return curr->val; } void addAtHead(int val) { ListNode*curr=new ListNode(val); curr->next=_dummyHead->next; _dummyHead->next=curr; _size++; } void addAtTail(int val) { ListNode*newnode=new ListNode(val); ListNode*curr=_dummyHead; while(curr->next!=NULL)curr=curr->next; curr->next=newnode; _size++; } void addAtIndex(int index, int val) { if(index<0)index=0; if(index>_size)return; ListNode*newnode=new ListNode(val); ListNode*curr=_dummyHead; while(index--)curr=curr->next; newnode->next=curr->next; curr->next=newnode; _size++; } void deleteAtIndex(int index) { if(index>=_size || index<0)return; ListNode*curr=_dummyHead; while(index--)curr=curr->next; curr->next=curr->next->next; _size--; } void PrintLinedList(){ ListNode*curr=_dummyHead; while(curr->next!=NULL){ cout<<curr->next->val<<" "; curr=curr->next; } cout<<endl; }private:
int _size;
ListNode*_dummyHead;
};
注意:
1.其实这里使用到的各种链表的操作都不是很难,只是需要注意index下标是从0开始的。考虑各种极端一点的情况。
2.关于初始化链表和struct ListNode方面我还有一点欠缺