python作业一 - 技术栈

python 复制代码

#A.方法一
num = int(input("请输入要打印的层数:"))
for n in range(1, num+1):
    s = ""
    for i in range(1, n+1):
        s += f"{i}" + " "

    print(s)
#方法二：
i=int(input("i:"))
for i in range(1,i+1):
    s=""
    for j in range(1,i+1):
        s+=f"{j}\t"
    print(s)

#B.方法一：
num = int(input("请输入要打印的层数:"))
for i in range(num+1, 0, -1):
    s=" "
    for j in range(1, i, 1):
        s+=f"{j}" + " "
    print(s) 

#方法二：
n = int(input("n:"))
for i in range(n):
    for j in range(1,n-i+1):
        print(f"{j}\t",end='')
    print()

#C.方法一：
num = int(input("请输入要打印的层数:"))
for i in range(1, num + 1):
    s = ""
    for k in range(num - i):
        s += " " * 2
    for j in range(0, i):
        s += f"{(i - j)}" + " "
    print(s)
#方法二：
n = int(input("n:"))
for i in range(1,n+1):

    for _ in range(n-i):
        print("\t",end='')

    for j in range(i,0,-1):
        print(f"{j}\t",end='')
    print()

#D.方法一：
num = int(input("请输入要打印的层数:"))
for i in range(num + 1, 0, -1):
    s = ""
    for k in range(num + 1 - i):
        s += " " * 2
    for j in range(i - 1, 0, -1):
        s += f"{(i - j)}" + " "
    print(s)
#方法二：
n = int(input("n:"))
for i in range(1,n+1):

    for _ in range(i-1):
        print("\t",end='')

    for j in range(1,n+2-i):
        print(f"{j}\t",end='')
    print()

python 复制代码

n = input("Enter an integer：")
n = n[3::-1]
print(f"The reversed number is {n}")

python 复制代码

n = int(input("Enter an integer:"))
m = n % 5 == 0 and n % 6 == 0
print(f"Is {n} divisible by 5 and 6?", m)
m = n % 5 == 0 or n % 6 == 0
print(f"Is {n} divisible by 5 or 6?", m)
m = not (n % 5 == 0 and n % 6 == 0)
print(f"Is {n} divisible by 5 and 6,but not both", m)