DjangoRF-14-创建request子应用

任小永的博客2024-08-06 16:06

注意，本应该是requests模块，为了区分，避免错误，用request

1、进入apps,创建request django-admin startapp request

2、因为只发送请求，没有数据库相关，不需要model。

3、进行序列化

from rest_framework import serializers

这里没u有进行引入ModeSer

class SingleRequestSerializer(serializers.Serializer):

method_choices = [

('get', 'get'),

('post', 'post'),

('delete', 'delete'),

('put', 'put'),

('patch', 'patch'),

]

url = serializers.CharField(help_text='url', label='url')

method = serializers.ChoiceField(choices=method_choices, help_text='请求方法', label='请求方法')

request = serializers.JSONField(help_text='请求参数', required=False, label='请求参数', default={})

复制代码

def validate_request(self, value):
    """解决json数据为空的问题"""
    if value.get('json') == {}:
        value.pop('json')
    return value

4views代码

from django.shortcuts import render

Create your views here.

import base64

import requests

from rest_framework.decorators import api_view

from rest_framework.response import Response

from .serializers import SingleRequestSerializer

@api_view(http_method_names=['POST'])

def request_view(request, format=None):

1. 接受请求数据并校验

serializer = SingleRequestSerializer(data=request.data)

serializer.is_valid(raise_exception=True)

2. 发送请求

data = serializer.validated_data

res = requests.request(method=data['method'], url=data['url'], **data['request'])

3. 组织响应数据并返回

res_data = {

'status_code': res.status_code,

'headers': dict(res.headers),

'cookies': dict(res.cookies)

}

content_type = res_data['headers'].get('Content-Type')

if content_type:

根据不同类型构造数据

if 'html' in content_type:

res_data['text'] = res.text

elif 'json' in content_type:

res_data['json'] = res.json()

else:

res_data['content'] = base64.b64encode(res.content).decode()

else:

res_data['content'] = base64.b64encode(res.content).decode()

复制代码

return Response(res_data, status=200)

5、urls的代码

from django.urls import path

from .views import request_view

urlpatterns = [

path('', request_view, name='request')

]

6.进行调试