LeetCode //C - 301. Remove Invalid Parentheses

301. Remove Invalid Parentheses

Given a string s that contains parentheses and letters, remove the minimum number of invalid parentheses to make the input string valid.

Return a list of unique strings that are valid with the minimum number of removals. You may return the answer in any order.

Example 1:

Input: s = "()())()"
Output: ["(())()","()()()"]

Example 2:

Input: s = "(a)())()"
Output: ["(a())()","(a)()()"]

Example 3:

Input: s = ")("
Output: [""]

Constraints:
  • 1 <= s.length <= 25
  • s consists of lowercase English letters and parentheses '(' and ')'.
  • There will be at most 20 parentheses in s.

From: LeetCode

Link: 301. Remove Invalid Parentheses


Solution:

Ideas:

1. Dynamic Queue and Result Resizing:

  • Queue Resizing: The BFS queue is initialized with a default size and dynamically resized if more space is needed.
  • Result Resizing: The result array is similarly resized to accommodate more valid strings as they are discovered.

2. Proper Memory Management:

  • Freeing Strings: Each dynamically allocated string in the queue and results is properly freed once it is no longer needed.
  • Clearing Visited Set: The visited set is cleared after BFS to avoid memory leaks.

3. Queue Management:

  • BFS Logic: The BFS queue is processed level by level, ensuring that all possibilities are explored and that only the minimum removal solutions are considered.
  • Memory Safety: All reallocations ensure that sufficient space is available, preventing buffer overflows and related errors.

4. Edge Cases:

  • Empty Strings: An explicit check is added for empty or null input strings, returning an empty string as the valid output.
Code:
c 复制代码
#define INITIAL_QUEUE_SIZE 1000
#define INITIAL_RESULT_SIZE 1000

// Define a structure for a hash table to store unique strings
typedef struct {
    char *str;          // Pointer to the stored string
    UT_hash_handle hh;  // Hash handle for uthash
} VisitedSet;

// Function to check if a given string has valid parentheses
bool isValid(char *s) {
    int balance = 0;
    for (int i = 0; s[i]; ++i) {
        if (s[i] == '(') balance++;
        if (s[i] == ')') balance--;
        if (balance < 0) return false; // More closing than opening
    }
    return balance == 0;
}

// Function to add a string to the visited set
bool addToVisited(VisitedSet **visited, const char *str) {
    VisitedSet *entry;
    HASH_FIND_STR(*visited, str, entry); // Check if already present
    if (!entry) {
        entry = (VisitedSet *)malloc(sizeof(VisitedSet));
        entry->str = strdup(str);
        HASH_ADD_KEYPTR(hh, *visited, entry->str, strlen(entry->str), entry);
        return true;
    }
    return false;
}

// Function to clear the visited set
void clearVisitedSet(VisitedSet *visited) {
    VisitedSet *current_entry, *tmp;
    HASH_ITER(hh, visited, current_entry, tmp) {
        HASH_DEL(visited, current_entry);
        free(current_entry->str);
        free(current_entry);
    }
}

// Function to remove invalid parentheses
char **removeInvalidParentheses(char *s, int *returnSize) {
    char **result = malloc(INITIAL_RESULT_SIZE * sizeof(char *));
    int resultCapacity = INITIAL_RESULT_SIZE;
    *returnSize = 0;

    if (!s || !*s) {
        // If string is empty or NULL, return empty string as the only valid result
        result[0] = strdup("");
        *returnSize = 1;
        return result;
    }

    VisitedSet *visited = NULL;
    char **queue = malloc(INITIAL_QUEUE_SIZE * sizeof(char *));
    int front = 0, rear = 0, queueCapacity = INITIAL_QUEUE_SIZE;
    bool found = false;

    // Initialize BFS
    queue[rear++] = strdup(s);
    addToVisited(&visited, s);

    while (front < rear) {
        int levelSize = rear - front;
        for (int i = 0; i < levelSize; ++i) {
            char *current = queue[front++];

            // Check if current string is valid
            if (isValid(current)) {
                if (!found) {
                    found = true;
                    // Reset result since this is the first valid solution
                    *returnSize = 0;
                }
                // Add valid string to result
                if (*returnSize >= resultCapacity) {
                    resultCapacity *= 2;
                    result = realloc(result, resultCapacity * sizeof(char *));
                }
                result[(*returnSize)++] = strdup(current);
            }

            // If found, skip generating further states
            if (found) {
                free(current);
                continue;
            }

            // Generate new states by removing one parenthesis at a time
            int len = strlen(current);
            for (int j = 0; j < len; ++j) {
                if (current[j] != '(' && current[j] != ')') continue;

                char *next = strdup(current);
                memmove(&next[j], &next[j + 1], len - j);

                if (addToVisited(&visited, next)) {
                    // Resize queue if needed
                    if (rear >= queueCapacity) {
                        queueCapacity *= 2;
                        queue = realloc(queue, queueCapacity * sizeof(char *));
                    }
                    queue[rear++] = next;
                } else {
                    free(next);
                }
            }

            free(current);
        }

        // If a valid expression was found, stop further exploration
        if (found) break;
    }

    clearVisitedSet(visited);
    free(queue);

    // If no valid expression found, return empty string
    if (*returnSize == 0) {
        result[0] = strdup("");
        *returnSize = 1;
    }

    return result;
}

// Helper function to free the result array
void freeResults(char **results, int returnSize) {
    for (int i = 0; i < returnSize; ++i) {
        free(results[i]);
    }
    free(results);
}
相关推荐
დ旧言~14 分钟前
【高阶数据结构】图论
算法·深度优先·广度优先·宽度优先·推荐算法
时光の尘14 分钟前
C语言菜鸟入门·关键字·float以及double的用法
运维·服务器·c语言·开发语言·stm32·单片机·c
张彦峰ZYF19 分钟前
投资策略规划最优决策分析
分布式·算法·金融
-一杯为品-23 分钟前
【51单片机】程序实验5&6.独立按键-矩阵按键
c语言·笔记·学习·51单片机·硬件工程
The_Ticker34 分钟前
CFD平台如何接入实时行情源
java·大数据·数据库·人工智能·算法·区块链·软件工程
Lenyiin1 小时前
02.06、回文链表
数据结构·leetcode·链表
爪哇学长1 小时前
双指针算法详解:原理、应用场景及代码示例
java·数据结构·算法
爱摸鱼的孔乙己1 小时前
【数据结构】链表(leetcode)
c语言·数据结构·c++·链表·csdn
Dola_Pan1 小时前
C语言:数组转换指针的时机
c语言·开发语言·算法
繁依Fanyi1 小时前
简易安卓句分器实现
java·服务器·开发语言·算法·eclipse