10.22.2024刷华为OD C题型（三）--for循环例子

脚踝动了手术，现在宾馆恢复，伤筋动骨一百天还真不是说笑的，继续努力吧。

文章目录

靠谱的车
灰度图恢复
[灰度图恢复 -- for循环使用例子](#灰度图恢复 -- for循环使用例子)

靠谱的车

https://www.nowcoder.com/discuss/564514429228834816

这个题目思路不难，就是要自己学会看代码，gpt也不可能一次就吐出代码，还是要学会改

另外动态规划可以缩短时间，但你不给我答案我还真不会做，或者得慢慢来，很逆天。

python 复制代码

def replace_4_with_5(num):
  result = 0
  multiplier = 1
  while num > 0:
    digit = num % 10
    if digit == 4:
      digit = 5
    result += digit * multiplier
    multiplier *= 10
    num //= 10
  return result


def calculate_actual_mileage(meter_reading):
  # meter_reading
  start = 0
  count = 0
  while True:
    start += 1
    count += 1
    # 如果start含有4，则该位数进1，
    start = replace_4_with_5(start)
    if start == meter_reading:
        break
  return count

if __name__ == "__main__":
  meter_reading = int(input("请输入计费表读数："))
  actual_mileage = calculate_actual_mileage(meter_reading)
  print("实际里程数为：", actual_mileage)

灰度图恢复

https://www.nowcoder.com/discuss/565217974919901184

灰度图恢复 -- for循环使用例子

https://www.nowcoder.com/discuss/565217974919901184

python 复制代码

for循环两两引用的方法

if __name__ == "__main__":
    # 获取用户输入
    # user_input = input("请输入一串用空格隔开的数字：")

    # 将输入字符串按空格分割成列表
    # number_strings = user_input.split()

    # 将字符串列表转换为整数列表
    # numbers = [int(num) for num in number_strings]

    # 如果需要浮点数，可以使用以下代码：
    # numbers = [float(num) for num in number_strings]
    numbers = [10, 10, 56, 34, 99, 1, 87, 8, 99, 3, 255, 6, 99, 5, 255, 4, 99, 7, 255, 2, 99, 9, 255, 21]
    # 输出结果
    print("你输入的数字是：", numbers)

    number1 = numbers[2:]
    for i in range(len(number1)):
        value = number1[i]
        number = number1[i+1]
        
        print(value,number)


    print(len(numbers) - 2)

python 复制代码

if __name__ == "__main__":
    # 获取用户输入
    numbers = input("请输入一串用空格隔开的数字：")
    special_number = input("具体像素位置：")
    # 将输入字符串按空格分割成列表
    number_strings = numbers.split()
    special_number = special_number.split()
    # 将字符串列表转换为整数列表
    numbers = [int(num) for num in number_strings]
    special_number = [int(num) for num in special_number]
    a = special_number[0]
    b = special_number[1]
    # 如果需要浮点数，可以使用以下代码：
    # numbers = [float(num) for num in number_strings]
    # numbers = [10, 10, 56, 34, 99, 1, 87, 8, 99, 3, 255, 6, 99, 5, 255, 4, 99, 7, 255, 2, 99, 9, 255, 21]
    # 输出结果
    print("你输入的数字是：", numbers)
    row = numbers[0]
    col = numbers[1]
    number1 = numbers[2:]
    grayscale = []
    for i in range(int(len(number1) / 2)):
        # print(i) 0 ~ 21
        value = number1[2 * i]
        number = number1[2 * i+1]
        for j in range(number):
            grayscale.append(value)

    print(len(grayscale))


    print(grayscale[col * a + b])