下面是一个简单的井字棋(Tic-Tac-Toe)游戏的C语言实现。这个游戏是在命令行界面上运行的,支持两名玩家轮流输入他们的步骤。
c
#include <stdio.h>
#include <stdbool.h>
#define SIZE 3
void drawBoard(char board[SIZE][SIZE]) {
for (int i = 0; i < SIZE; ++i) {
for (int j = 0; j < SIZE; ++j) {
printf(" %c ", board[i][j]);
if (j < SIZE - 1) printf("|");
}
printf("\n");
if (i < SIZE - 1) printf("---|---|---\n");
}
}
bool checkWin(char board[SIZE][SIZE], char player) {
// Check rows, columns and diagonals for a win
for (int i = 0; i < SIZE; ++i) {
if ((board[i][0] == player && board[i][1] == player && board[i][2] == player) ||
(board[0][i] == player && board[1][i] == player && board[2][i] == player)) {
return true;
}
}
if ((board[0][0] == player && board[1][1] == player && board[2][2] == player) ||
(board[0][2] == player && board[1][1] == player && board[2][0] == player)) {
return true;
}
return false;
}
bool isBoardFull(char board[SIZE][SIZE]) {
for (int i = 0; i < SIZE; ++i)
for (int j = 0; j < SIZE; ++j)
if (board[i][j] == ' ') return false;
return true;
}
int main() {
char board[SIZE][SIZE];
for (int i = 0; i < SIZE; ++i)
for (int j = 0; j < SIZE; ++j)
board[i][j] = ' ';
bool playerOneTurn = true;
int row, col;
while (true) {
drawBoard(board);
if (playerOneTurn) printf("Player X's turn.\n");
else printf("Player O's turn.\n");
printf("Enter row and column: ");
scanf("%d %d", &row, &col);
if (row >= 0 && row < SIZE && col >= 0 && col < SIZE && board[row][col] == ' ') {
board[row][col] = playerOneTurn ? 'X' : 'O';
if (checkWin(board, playerOneTurn ? 'X' : 'O')) {
drawBoard(board);
printf(playerOneTurn ? "Player X wins!\n" : "Player O wins!\n");
break;
}
if (isBoardFull(board)) {
drawBoard(board);
printf("It's a draw!\n");
break;
}
playerOneTurn = !playerOneTurn;
} else {
printf("Invalid move. Try again.\n");
}
}
return 0;
}
程序说明:
drawBoard
函数:用于打印当前的游戏板状态。checkWin
函数:检查当前是否有玩家获胜。它会检查所有可能的胜利条件:行、列以及两条对角线。isBoardFull
函数:判断游戏板是否已满,如果满了且没有玩家获胜,则游戏为平局。- 主函数 (
main
):初始化游戏板,循环处理玩家的输入,并根据玩家的输入更新游戏板。每轮都会检查是否有玩家获胜或游戏是否结束于平局。
这个程序提供了一个基础版本的井字棋游戏。你可以在此基础上添加更多功能,比如更友好的用户界面、与电脑进行对战等。