目录
[1.CASE WHEN](#1.CASE WHEN)
[2.UNION ALL合并结果集](#2.UNION ALL合并结果集)
[四、行转列练习:CASE WHEN/DECODE/PIVOT/lag/LEAD](#四、行转列练习:CASE WHEN/DECODE/PIVOT/lag/LEAD)
[1.CASE WHEN](#1.CASE WHEN)
一、原始数据
sql
CREATE TABLE T_SCORE (SNO NUMBER,CLA VARCHAR2(20),SCORE NUMBER);
INSERT INTO T_SCORE VALUES (101,'语文',88);
INSERT INTO T_SCORE VALUES (101,'数学',89);
INSERT INTO T_SCORE VALUES (101,'英语',90);
INSERT INTO T_SCORE VALUES (102,'语文',91);
INSERT INTO T_SCORE VALUES (102,'数学',77);
INSERT INTO T_SCORE VALUES (102,'英语',56);
INSERT INTO T_SCORE VALUES (103,'语文',77);
INSERT INTO T_SCORE VALUES (103,'数学',88);
INSERT INTO T_SCORE VALUES (103,'英语',99);
INSERT INTO T_SCORE VALUES (104,'语文',77);
INSERT INTO T_SCORE VALUES (104,'数学',66);
INSERT INTO T_SCORE VALUES (104,'英语',55);
INSERT INTO T_SCORE VALUES (105,'语文',44);
INSERT INTO T_SCORE VALUES (105,'数学',67);
INSERT INTO T_SCORE VALUES (105,'英语',78);
INSERT INTO T_SCORE VALUES (106,'语文',89);
INSERT INTO T_SCORE VALUES (106,'数学',98);
INSERT INTO T_SCORE VALUES (106,'英语',78);
INSERT INTO T_SCORE VALUES (107,'语文',67);
INSERT INTO T_SCORE VALUES (107,'数学',56);
INSERT INTO T_SCORE VALUES (107,'英语',54);
INSERT INTO T_SCORE VALUES (108,'语文',76);
INSERT INTO T_SCORE VALUES (108,'数学',78);
INSERT INTO T_SCORE VALUES (108,'英语',12);
COMMIT;
SELECT * FROM T_SCORE;
二、行转列的多种实现方式
原格式:

行转列后的格式:

1.CASE WHEN
sql
select SNO
, CASE WHEN CLA = '语文' THEN SCORE end as 语文
, CASE WHEN CLA = '数学' THEN SCORE end as 数学
, CASE WHEN CLA = '英语' THEN SCORE end as 英语
from T_SCORE;

下面两种聚合函数都可以:
sql
select SNO
, max(CASE WHEN CLA = '语文' THEN SCORE end) as 语文
, max(CASE WHEN CLA = '数学' THEN SCORE end) as 数学
, max(CASE WHEN CLA = '英语' THEN SCORE end) as 英语
from T_SCORE
group by SNO
order by SNO;
select SNO
, sum(CASE WHEN CLA = '语文' THEN SCORE end) as 语文
, sum(CASE WHEN CLA = '数学' THEN SCORE end) as 数学
, sum(CASE WHEN CLA = '英语' THEN SCORE end) as 英语
from T_SCORE
group by SNO
order by SNO;
二者区别:
聚合函数 | 逻辑 | 处理重复记录 | 适用场景 |
---|---|---|---|
MAX |
返回分组内的最大值。若每组只有一个值,则直接返回该值。 | 保留最大值(如补考成绩)。 | 行转列(提取唯一值)。 |
SUM |
返回分组内所有值的总和。若每组只有一个值,则返回该值本身。 | 累加所有值(可能导致成绩异常)。 | 统计总分或合计。 |
2.DECODE
sql
select SNO
, decode(CLA, '语文', SCORE) as 语文
, decode(CLA, '数学', SCORE) as 数学
, decode(CLA, '英语', SCORE) as 英语
from T_SCORE;

sql
select SNO
, max(decode(CLA, '语文', SCORE)) as 语文
, max(decode(CLA, '数学', SCORE)) as 数学
, max(decode(CLA, '英语', SCORE)) as 英语
from T_SCORE
group by SNO
order by SNO;
select SNO
, sum(decode(CLA, '语文', SCORE)) as 语文
, sum(decode(CLA, '数学', SCORE)) as 数学
, sum(decode(CLA, '英语', SCORE)) as 英语
from T_SCORE
group by SNO
order by SNO;

3.PIVOT(Oracle独有)
语法:
sql
PIVOT (SUM(聚合值) FOR 待转换的列名 IN (待转换的列名里面的值 转换后列的别名))
sql
select *
from T_SCORE
PIVOT (sum(SCORE) for CLA in ( '语文' Chinese,'数学' Math,'英语' English))
order by SNO;

4.使用LEAD开窗函数
因为要对中文进行排序,所以先使用ASCII码
sql
SELECT CLA, ASCII(CLA)
FROM T_SCORE
GROUP BY CLA
ORDER BY CLA;

sql
SELECT *
FROM (SELECT sno
, LEAD(score, 0) OVER (PARTITION BY sno ORDER BY CLA ) 数学
, LEAD(score, 1) OVER (PARTITION BY sno ORDER BY CLA ) 英语
, LEAD(score, 2) OVER (PARTITION BY sno ORDER BY CLA ) 语文
FROM T_SCORE)
WHERE 语文 IS NOT NULL;

三、列转行的多种实现方式
sql
DROP TABLE b_score;
CREATE TABLE b_score AS
SELECT *
FROM (SELECT *
FROM t_score
PIVOT (
SUM(score) -- 聚合函数(使用 SUM 或 MAX 均可)
FOR cla IN (
'语文' AS 语文, -- 指定课程名称及对应的列别名
'数学' AS 数学,
'英语' AS 英语
)
))
ORDER BY sno; -- 按学生编号排序
COMMIT;
SELECT *
FROM b_score;
原格式:

行转列后的格式:

1.UNPIVOT(Oracle独有)
语法:
sql
UNPIVOT (存储指标值的列名 FOR 合并后的列名 IN (待合并的列名))
sql
SELECT *
FROM b_score
UNPIVOT (score FOR cla IN (语文,数学,英语));

2.UNION ALL合并结果集
sql
SELECT sno,'语文' cla,语文 score FROM b_score
UNION ALL
SELECT sno,'数学' cla,数学 score FROM b_score
UNION ALL
SELECT sno,'英语' cla,英语 score FROM b_score
order by SNO;

四、行转列练习:CASE WHEN/DECODE/PIVOT/lag/LEAD
输出每个部门的总人数,展示样式:
D10 D20 D30
3 5 6
1.CASE WHEN
sql
select COUNT(case when DEPTNO = 10 then 1 end) as D10
, COUNT(case when DEPTNO = 20 then 1 end) as D20
, COUNT(case when DEPTNO = 30 then 1 end) as D30
from EMP;
2.DECODE
sql
select COUNT(DECODE(DEPTNO, 10, 1)) as D10
, COUNT(DECODE(DEPTNO, 20, 1)) as D20
, COUNT(DECODE(DEPTNO, 30, 1)) as D30
from EMP;
3.PIVOT
sql
SELECT DEPTNO
, COUNT(EMPNO) CM
FROM EMP
GROUP BY DEPTNO;

sql
select *
from (SELECT DEPTNO
, COUNT(EMPNO) CM
FROM EMP
GROUP BY DEPTNO)
pivot (sum(cm) for DEPTNO in (10 D10,20 D20,30 D30));

4.LEAD
sql
select DEPTNO, count(empno) ct
from EMP
group by DEPTNO;

sql
SELECT *
FROM (select lead(ct, 0) over ( order by DEPTNO) as D10
, lead(ct, 1) over ( order by DEPTNO) as D20
, lead(ct, 2) over ( order by DEPTNO) as D30
from (select DEPTNO, count(empno) ct
from EMP
group by DEPTNO)) a
WHERE D30 IS NOT NULL;
