KADB行列转换

create table row2col(name varchar(20),subject varchar(20),grade varchar(10));

insert into row2col SELECT 'Tim' name, '数学' subject, 'A' grade

UNION

SELECT 'Tim' name, '英语' subject, 'B' grade

UNION

SELECT 'Tim' name, '语文' subject, null grade

UNION

SELECT 'Tom' name, '数学' subject, 'B' grade

UNION

SELECT 'Tom' name, '英语' subject, 'D' grade

UNION

SELECT 'Tom' name, '语文' subject, 'B' grade;

行转列:

select t.name,t.grades[1] 数学,t.grades[2] 英语,t.grades[3] 语文 from(

SELECT

t.name,

array_agg(t.grade order by t.subject) grades

FROM row2col t group by t.name)t;

name | 数学 | 英语 | 语文

------+------+------+------

Tim | A | B |

Tom | B | D | B

列转行:

select name,unnest(array['数学','英语','语文']),unnest(array[数学,英语,语文]) from (select t.name,t.grades[1] 数学,t.grades[2] 英语,t.grades[3] 语文 from(

SELECT

t.name,

array_agg(t.grade order by t.subject) grades

FROM row2col t group by t.name)t

)a;

name | unnest | unnest

------+--------+--------

Tim | 数学 | A

Tim | 英语 | B

Tim | 语文 |

Tom | 数学 | B

Tom | 英语 | D

Tom | 语文 | B

2、递归的实现方式

CREATE TABLE employees (

employee_id serial PRIMARY KEY,

full_name VARCHAR NOT NULL,

manager_id INT

);

INSERT INTO employees (

employee_id,

full_name,

manager_id

)

VALUES

(1, 'Michael North', NULL),

(2, 'Megan Berry', 1),

(3, 'Sarah Berry', 1),

(4, 'Zoe Black', 1),

(5, 'Tim James', 1),

(6, 'Bella Tucker', 2),

(7, 'Ryan Metcalfe', 2),

(8, 'Max Mills', 2),

(9, 'Benjamin Glover', 2),

(10, 'Carolyn Henderson', 3),

(11, 'Nicola Kelly', 3),

(12, 'Alexandra Climo', 3),

(13, 'Dominic King', 3),

(14, 'Leonard Gray', 4),

(15, 'Eric Rampling', 4),

(16, 'Piers Paige', 7),

(17, 'Ryan Henderson', 7),

(18, 'Frank Tucker', 8),

(19, 'Nathan Ferguson', 8),

(20, 'Kevin Rampling', 8);

返回id为2的经理的所有下属

WITH RECURSIVE subordinates AS (

SELECT

employee_id,

manager_id,

full_name

FROM

employees

WHERE

employee_id = 2

UNION

SELECT

e.employee_id,

e.manager_id,

e.full_name

FROM

employees e

INNER JOIN subordinates s ON s.employee_id = e.manager_id

) SELECT

*

FROM

subordinates;

employee_id | manager_id | full_name

-------------+------------+-----------------

2 | 1 | Megan Berry

9 | 2 | Benjamin Glover

8 | 2 | Max Mills

7 | 2 | Ryan Metcalfe

6 | 2 | Bella Tucker

19 | 8 | Nathan Ferguson

18 | 8 | Frank Tucker

20 | 8 | Kevin Rampling

16 | 7 | Piers Paige

17 | 7 | Ryan Henderson

相关推荐
yaoh.wang3 天前
力扣(LeetCode) 70: 爬楼梯 - 解法思路
python·算法·leetcode·面试·职场和发展·动态规划·递归
DanyHope4 天前
LeetCode 206. 反转链表:迭代 + 递归双解法全解析
算法·leetcode·链表·递归·迭代
oscar9997 天前
CSP-J教程——第一阶段第十一课:函数与递归初步
递归·函数·csp-j
长安er7 天前
LeetCode 46/51 排列型回溯题笔记-全排列 / N 皇后
笔记·算法·leetcode·回溯·递归·n皇后
鹿角片ljp10 天前
力扣104.求二叉树最大深度:递归和迭代
算法·leetcode·二叉树·递归
长安er10 天前
LeetCode 235 & 236 最近公共祖先(LCA)解题总结
算法·leetcode·二叉树·递归·lca
长安er12 天前
LeetCode 100/101/110/199 对称/平衡二叉树与右视图
算法·leetcode·二叉树·dfs·bfs·递归
quan263119 天前
20251204,职级权限,开发实践分享
java·递归·java权限·职级架构
达不溜先生 ୧⍢⃝୨23 天前
循环赛日程表问题
c语言·算法·递归·分治·循环赛日程表·动态二维数组
啊吧怪不啊吧1 个月前
自己调用自己的算法——递归算法
大数据·算法·leetcode·逻辑回归·递归