LeetCode第79题 - 单词搜索

题目

解答

java 复制代码
class Solution {
    public boolean exist(char[][] board, String word) {
        int rowLength = board.length;
        int colomnLength = board[0].length;

        boolean[][] boardUsed = new boolean[rowLength][colomnLength];

        for (int i = 0; i < rowLength; ++i) {
            Arrays.fill(boardUsed[i], false);
        }

        char firstChar = word.charAt(0);
        for (int row = 0; row < rowLength; ++row) {
            for (int colomn = 0; colomn < colomnLength; ++colomn) {
                if (board[row][colomn] == firstChar) {
                    for (int i = 0; i < rowLength; ++i) {
                        Arrays.fill(boardUsed[i], false);
                    }

                    boardUsed[row][colomn] = true;
                    if (exist(board, word, 1, boardUsed, row, colomn)) {
                        return true;
                    }
                }
            }
        }
        return false;
    }

    public boolean exist(char[][] board, String word, int index, boolean[][] boardUsed, int rowIndex, int colomnIndex) {

        if (index >= word.length()) {
            return true;
        }

        int rowLength = board.length;
        int colomnLength = board[0].length;

        int nextIndex = index + 1;
        char c = word.charAt(index);
        boardUsed[rowIndex][colomnIndex] = true;
        int nextRow = 0;
        int nextColomn = 0;
        // 上一行
        {
            nextRow = rowIndex - 1;
            nextColomn = colomnIndex;
            if (nextRow >= 0 && !boardUsed[nextRow][nextColomn] && board[nextRow][nextColomn] == c) {
                if (exist(board, word, nextIndex, boardUsed, nextRow, nextColomn)) {
                    return true;
                } else {
                    boardUsed[nextRow][nextColomn] = false;
                }
            }
        }
        // 下一行
        {
            nextRow = rowIndex + 1;
            nextColomn = colomnIndex;

            if (nextRow < rowLength && !boardUsed[nextRow][nextColomn] && board[nextRow][nextColomn] == c) {

                if (exist(board, word, nextIndex, boardUsed, nextRow, nextColomn)) {
                    return true;
                } else {
                    boardUsed[nextRow][nextColomn] = false;
                }
            }
        }
        // 左边
        {
            nextRow = rowIndex;
            nextColomn = colomnIndex - 1;
            if (nextColomn >= 0 && !boardUsed[nextRow][nextColomn] && board[nextRow][nextColomn] == c) {
                if (exist(board, word, nextIndex, boardUsed, nextRow, nextColomn)) {
                    return true;
                } else {
                    boardUsed[nextRow][nextColomn] = false;
                }
            }
        }
        // 右边
        {
            nextRow = rowIndex;
            nextColomn = colomnIndex + 1;

            if (nextColomn < colomnLength && !boardUsed[nextRow][nextColomn] && board[nextRow][nextColomn] == c) {
                if (exist(board, word, nextIndex, boardUsed, nextRow, nextColomn)) {
                    return true;
                } else {
                    boardUsed[nextRow][nextColomn] = false;
                }
            }
        }

        return false;
    }
}

总结

回溯法。

相关推荐
Liu628884 小时前
C++中的工厂模式高级应用
开发语言·c++·算法
AI科技星5 小时前
全尺度角速度统一:基于 v ≡ c 的纯推导与验证
c语言·开发语言·人工智能·opencv·算法·机器学习·数据挖掘
参.商.5 小时前
【Day41】143. 重排链表
leetcode·golang
条tiao条5 小时前
KMP 算法详解:告别暴力匹配,让字符串匹配 “永不回头”
开发语言·算法
干啥啥不行,秃头第一名5 小时前
C++20概念(Concepts)入门指南
开发语言·c++·算法
zzh940776 小时前
Gemini 3.1 Pro 硬核推理优化剖析:思维织锦、动态计算与国内实测
算法
2301_807367196 小时前
C++中的解释器模式变体
开发语言·c++·算法
愣头不青6 小时前
617.合并二叉树
java·算法
MIUMIUKK7 小时前
双指针三大例题
算法
灵感__idea7 小时前
Hello 算法:复杂问题的应对策略
前端·javascript·算法