信息奥赛一本通—编程启蒙（3371：【例64.2】 生日相同）

代码如下：

#include<bits/stdc++.h>
using namespace std;
int main() {
	int n;
	cin >> n;
	string name[200];
	int month[200];
	int day[200];
	for (int i = 0; i < n; i++) {
		cin >> name[i] >> month[i] >> day[i];
	}
	bool found = false;
	for (int m = 1; m <= 12; m++) {
		for (int d = 1; d <= 31; d++) {
			vector<string> same;
			for (int i = 0; i < n; i++) {
				if (month[i] == m && day[i] == d) {
					same.push_back(name[i]);
				}
			}
			if (same.size() >= 2) {
				found = true;
				for (int i = 0; i < same.size(); i++) {
					for (int j = i + 1; j < same.size(); j++) {
						if (same[i].size() > same[j].size()) {
							swap(same[i], same[j]);
						} else if (same[i].size() == same[j].size() && same[i] > same[j]) {
							swap(same[i], same[j]);
						}
					}
				}
				cout << m << " " << d << " ";
				for (int i = 0; i < same.size(); i++) {
					cout << same[i] << " ";
				}
				cout << endl;
			}
		}
	}
	if (!found) {
		cout << "None" << endl;
	}

	return 0;
}

网站链接：https://bas.ssoier.cn/problem_show.php?pid=3371

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