高数常用等价无穷小和泰勒公式动态图像

文章目录

下面的代码都是Maple,没有找到Maple就选择了Matlab代码

sinx~x

matlab 复制代码
f := x;
g := sin(x);
plots[animatecurve]([f, g], x = -1 .. 1, color = [red, blue], legend = ["x", "sinx"], frames = 50);

arcsinx~x

matlab 复制代码
f := x;
g := arcsin(x);
plots[animatecurve]([f, g], x = -1 .. 1, color = [red, blue], legend = ["x", arcsinx], frames = 50);

tanx~x

matlab 复制代码
f := x;
g := tan(x);
plots[animatecurve]([f, g], x = -1 .. 1, color = [red, blue], legend = ["x", tanx], frames = 50);

e^x-1~x

matlab 复制代码
f := x;
g := exp(x) - 1;
plots[animatecurve]([f, g], x = -1 .. 1, color = [red, blue], legend = ["x", exp(x) - 1], frames = 50);

ln(x+1)~x

matlab 复制代码
f := x;
g := ln(x + 1);
plots[animatecurve]([f, g], x = -0.5 .. 0.5, color = [red, blue], legend = ["x", ln(x + 1)], frames = 50);

1-cosx~1/2*x^2

matlab 复制代码
f := 1 - cos(x);
g := 1/2*x^2;
plots[animatecurve]([f, g], x = -1 .. 1, color = [red, blue], legend = [1 - cosx, 1/2*x^2], frames = 50);

sinx泰勒展开

matlab 复制代码
f := x - 1/6*x^3;
g := sin(x);
plots[animatecurve]([f, g], x = -1.5 .. 1.5, color = [red, blue], legend = [x - 1/6*x^3, "sinx"], frames = 50);

arcsinx泰勒展开

matlab 复制代码
f := x + 1/6*x^3;
g := arcsin(x);
plots[animatecurve]([f, g], x = -1 .. 1, color = [red, blue], legend = [x - 1/6*x^3, "arcsinx"], frames = 50);

tanx泰勒展开

matlab 复制代码
f := x + 1/3*x^3;
g := tan(x);
plots[animatecurve]([f, g], x = -1 .. 1, color = [red, blue], legend = [x - 1/6*x^3, "tanx"], frames = 50);

arctanx泰勒展开

matlab 复制代码
f := x - 1/3*x^3;
g := arctan(x);
plots[animatecurve]([f, g], x = -1 .. 1, color = [red, blue], legend = [x - 1/3*x^3, "arctanx"], frames = 50);

cosx泰勒展开

matlab 复制代码
f := cos(x);
g := 1 - 1/2*x^2 + 1/24*x^4;
plots[animatecurve]([f, g], x = -2 .. 2, color = [red, blue], legend = [cosx, 1 - 1/2*x^2 + 1/24*x^4], frames = 50);

ln(x+1)泰勒展开

matlab 复制代码
f := ln(1 + x);
g := x - 1/2*x^2 + 1/3*x^3 - 1/4*x^4;
plots[animatecurve]([f, g], x = -1 .. 1, color = [red, blue], legend = [ln(1 + x), x - 1/2*x^2 + 1/3*x^3 - 1/4*x^4], frames = 50);

e^x泰勒展开

matlab 复制代码
f := exp(x);
g := 1 + x + x^2/2! + x^3/3!;
plots[animatecurve]([f, g], x = -1 .. 1, color = [red, blue], legend = [exp(x), 1 + x + x^2/2! + x^3/3!], frames = 50);

1/(1-x)泰勒展开

matlab 复制代码
f := 1/(1 - x);
g := x^3 + x^2 + x + 1;
plots[animatecurve]([f, g], x = -0.5 .. 0.5, color = [red, blue], legend = [1/(1 - x), x^3 + x^2 + x + 1], frames = 50);
相关推荐
hetao17338375 小时前
2026-10-22~23 hetao1733837 的刷题记录
c++·算法
java_nnnn5 小时前
LeetCode刷题滑动窗口(串联所有单词的子串+最小覆盖的子串)Java
算法·leetcode·职场和发展
Navigator_Z6 小时前
LeetCode //C - 1301. Number of Paths with Max Score
c语言·算法·leetcode
卡卡~~6 小时前
“101计划”核心课程实践教材《数据实验结构指导-C++语言版》题目集
开发语言·c++·学习·算法
企业数字化笔记7 小时前
AI视频增强后画质怎么验收?插值基线、伪细节与帧间闪烁的检查方法
人工智能·算法·音视频
学逆向的7 小时前
C 内存属性
c语言·开发语言·算法·网络安全
lengxuenong8 小时前
树状数组 · 信息学学习手册1-求和3个模板
c++·学习·算法·青少年编程
ComputerInBook8 小时前
泛函分析概观
人工智能·算法·机器学习·泛函分析
Nuanyt8 小时前
LeetCode Hot100 刷题笔记 · 普通数组专题
java·笔记·算法·leetcode