A. Rudolph and Cut the Rope

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

There are n� nails driven into the wall, the i�-th nail is driven ai�� meters above the ground, one end of the bi�� meters long rope is tied to it. All nails hang at different heights one above the other. One candy is tied to all ropes at once. Candy is tied to end of a rope that is not tied to a nail.

To take the candy, you need to lower it to the ground. To do this, Rudolph can cut some ropes, one at a time. Help Rudolph find the minimum number of ropes that must be cut to get the candy.

The figure shows an example of the first test:

Input

The first line contains one integer t� (1≤t≤1041≤�≤104) --- the number of test cases.

The first line of each test case contains one integer n� (1≤n≤501≤�≤50) --- the number of nails.

The i�-th of the next n� lines contains two integers ai�� and bi�� (1≤ai,bi≤2001≤��,��≤200) --- the height of the i�-th nail and the length of the rope tied to it, all ai�� are different.

It is guaranteed that the data is not contradictory, it is possible to build a configuration described in the statement.

Output

For each test case print one integer --- the minimum number of ropes that need to be cut to make the candy fall to the ground.

Example

input

Copy

复制代码

4

3

4 3

3 1

1 2

4

9 2

5 2

7 7

3 4

5

11 7

5 10

12 9

3 2

1 5

3

5 6

4 5

7 7

output

Copy

复制代码
2
2
3
0

解题说明:水题,此题分析一下就能发现,只要绳子长度小于高度,那就必须要切断才能让糖果落地,直接判断即可。

cpp 复制代码
#include<stdio.h>
int main()
{
	int m, n, a, b, ans;
	scanf("%d", &n);
	for (int i = 0; i < n; i++)
	{
		ans = 0;
		scanf("%d", &m);
		for (int j = 0; j < m; j++)
		{
			scanf("%d %d", &a, &b);
			if (a > b)
			{
				ans++;
			}
		}
		printf("%d\n", ans);
	}
	return 0;
}
相关推荐
t***54418 小时前
Clang 编译器在 Orwell Dev-C++ 中的局限性
开发语言·c++
Sam_Deep_Thinking19 小时前
学数据结构到底有什么用
数据结构
kobesdu19 小时前
人形机器人SLAM:技术挑战、算法综述与开源方案
算法·机器人·人形机器人
yolo_guo20 小时前
redis++使用: hmset 与 hmget
c++·redis
handler0120 小时前
拒绝权限报错!三分钟掌握 Linux 权限管理
linux·c语言·c++·笔记·学习
椰羊~王小美21 小时前
随机数概念及算法
算法
阿Y加油吧21 小时前
算法实战笔记:LeetCode 169 多数元素 & 75 颜色分类
笔记·算法·leetcode
t***54421 小时前
如何在Dev-C++中选择Clang编译器
开发语言·c++
不要秃头的小孩21 小时前
力扣刷题——509. 斐波那契数
python·算法·leetcode·动态规划