A. Rudolph and Cut the Rope

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

There are n� nails driven into the wall, the i�-th nail is driven ai�� meters above the ground, one end of the bi�� meters long rope is tied to it. All nails hang at different heights one above the other. One candy is tied to all ropes at once. Candy is tied to end of a rope that is not tied to a nail.

To take the candy, you need to lower it to the ground. To do this, Rudolph can cut some ropes, one at a time. Help Rudolph find the minimum number of ropes that must be cut to get the candy.

The figure shows an example of the first test:

Input

The first line contains one integer t� (1≤t≤1041≤�≤104) --- the number of test cases.

The first line of each test case contains one integer n� (1≤n≤501≤�≤50) --- the number of nails.

The i�-th of the next n� lines contains two integers ai�� and bi�� (1≤ai,bi≤2001≤��,��≤200) --- the height of the i�-th nail and the length of the rope tied to it, all ai�� are different.

It is guaranteed that the data is not contradictory, it is possible to build a configuration described in the statement.

Output

For each test case print one integer --- the minimum number of ropes that need to be cut to make the candy fall to the ground.

Example

input

Copy

复制代码

4

3

4 3

3 1

1 2

4

9 2

5 2

7 7

3 4

5

11 7

5 10

12 9

3 2

1 5

3

5 6

4 5

7 7

output

Copy

复制代码
2
2
3
0

解题说明:水题,此题分析一下就能发现,只要绳子长度小于高度,那就必须要切断才能让糖果落地,直接判断即可。

cpp 复制代码
#include<stdio.h>
int main()
{
	int m, n, a, b, ans;
	scanf("%d", &n);
	for (int i = 0; i < n; i++)
	{
		ans = 0;
		scanf("%d", &m);
		for (int j = 0; j < m; j++)
		{
			scanf("%d %d", &a, &b);
			if (a > b)
			{
				ans++;
			}
		}
		printf("%d\n", ans);
	}
	return 0;
}
相关推荐
m沐沐5 小时前
【深度学习】YOLOv2目标检测算法——改进点、网络结构与聚类先验框解析
人工智能·pytorch·深度学习·算法·yolo·目标检测·transformer
不会就选b5 小时前
算法日常・每日刷题--<链表>3
数据结构·算法·链表
geovindu5 小时前
go: Iterative Algorithms
开发语言·后端·算法·golang·迭代算法
稚南城才子,乌衣巷风流7 小时前
块状链表:数据结构详解与实现
数据结构·链表
Zachery Pole7 小时前
CCF-CSP备战NO.7【队列】
算法
闪电悠米7 小时前
力扣hot100-48.旋转图像-转置翻转详解
算法·leetcode·职场和发展
满天星83035778 小时前
【算法】最长递增子序列(三种解法)
算法
hold?fish:palm8 小时前
kv存储主从复制的设计与实现
c++·redis·后端
啦啦啦啦啦zzzz8 小时前
算法:贪心算法
c++·算法·leetcode·贪心算法
charlie1145141918 小时前
现代C++工程实践 WeakPtr 实战(三):WeakPtrFactory 与「最后成员」惯用法
开发语言·c++·开源项目·现代c++