A. Rudolph and Cut the Rope

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

There are n� nails driven into the wall, the i�-th nail is driven ai�� meters above the ground, one end of the bi�� meters long rope is tied to it. All nails hang at different heights one above the other. One candy is tied to all ropes at once. Candy is tied to end of a rope that is not tied to a nail.

To take the candy, you need to lower it to the ground. To do this, Rudolph can cut some ropes, one at a time. Help Rudolph find the minimum number of ropes that must be cut to get the candy.

The figure shows an example of the first test:

Input

The first line contains one integer t� (1≤t≤1041≤�≤104) --- the number of test cases.

The first line of each test case contains one integer n� (1≤n≤501≤�≤50) --- the number of nails.

The i�-th of the next n� lines contains two integers ai�� and bi�� (1≤ai,bi≤2001≤��,��≤200) --- the height of the i�-th nail and the length of the rope tied to it, all ai�� are different.

It is guaranteed that the data is not contradictory, it is possible to build a configuration described in the statement.

Output

For each test case print one integer --- the minimum number of ropes that need to be cut to make the candy fall to the ground.

Example

input

Copy

复制代码

4

3

4 3

3 1

1 2

4

9 2

5 2

7 7

3 4

5

11 7

5 10

12 9

3 2

1 5

3

5 6

4 5

7 7

output

Copy

复制代码
2
2
3
0

解题说明:水题,此题分析一下就能发现,只要绳子长度小于高度,那就必须要切断才能让糖果落地,直接判断即可。

cpp 复制代码
#include<stdio.h>
int main()
{
	int m, n, a, b, ans;
	scanf("%d", &n);
	for (int i = 0; i < n; i++)
	{
		ans = 0;
		scanf("%d", &m);
		for (int j = 0; j < m; j++)
		{
			scanf("%d %d", &a, &b);
			if (a > b)
			{
				ans++;
			}
		}
		printf("%d\n", ans);
	}
	return 0;
}
相关推荐
NAGNIP1 小时前
一文搞懂机器学习中的特征降维!
算法·面试
NAGNIP1 小时前
一文搞懂机器学习中的特征构造!
算法·面试
Learn Beyond Limits2 小时前
解构语义:从词向量到神经分类|Decoding Semantics: Word Vectors and Neural Classification
人工智能·算法·机器学习·ai·分类·数据挖掘·nlp
你怎么知道我是队长2 小时前
C语言---typedef
c语言·c++·算法
带土13 小时前
5. enum(枚举)关键字在C/C++中的作用
c语言·c++
驴友花雕3 小时前
【花雕学编程】Arduino BLDC 之群体机器人协同探索
c++·单片机·嵌入式硬件·arduino bldc·群体机器人协同探索
驴友花雕3 小时前
【花雕学编程】Arduino BLDC 之仿人机器人膝关节稳定系统
c++·单片机·嵌入式硬件·arduino bldc·仿人机器人膝关节稳定系统
Qhumaing4 小时前
C++学习:【PTA】数据结构 7-1 实验7-1(最小生成树-Prim算法)
c++·学习·算法
Z1Jxxx5 小时前
01序列01序列
开发语言·c++·算法