A. Rudolph and Cut the Rope

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

There are n� nails driven into the wall, the i�-th nail is driven ai�� meters above the ground, one end of the bi�� meters long rope is tied to it. All nails hang at different heights one above the other. One candy is tied to all ropes at once. Candy is tied to end of a rope that is not tied to a nail.

To take the candy, you need to lower it to the ground. To do this, Rudolph can cut some ropes, one at a time. Help Rudolph find the minimum number of ropes that must be cut to get the candy.

The figure shows an example of the first test:

Input

The first line contains one integer t� (1≤t≤1041≤�≤104) --- the number of test cases.

The first line of each test case contains one integer n� (1≤n≤501≤�≤50) --- the number of nails.

The i�-th of the next n� lines contains two integers ai�� and bi�� (1≤ai,bi≤2001≤��,��≤200) --- the height of the i�-th nail and the length of the rope tied to it, all ai�� are different.

It is guaranteed that the data is not contradictory, it is possible to build a configuration described in the statement.

Output

For each test case print one integer --- the minimum number of ropes that need to be cut to make the candy fall to the ground.

Example

input

Copy

复制代码

4

3

4 3

3 1

1 2

4

9 2

5 2

7 7

3 4

5

11 7

5 10

12 9

3 2

1 5

3

5 6

4 5

7 7

output

Copy

复制代码
2
2
3
0

解题说明:水题,此题分析一下就能发现,只要绳子长度小于高度,那就必须要切断才能让糖果落地,直接判断即可。

cpp 复制代码
#include<stdio.h>
int main()
{
	int m, n, a, b, ans;
	scanf("%d", &n);
	for (int i = 0; i < n; i++)
	{
		ans = 0;
		scanf("%d", &m);
		for (int j = 0; j < m; j++)
		{
			scanf("%d %d", &a, &b);
			if (a > b)
			{
				ans++;
			}
		}
		printf("%d\n", ans);
	}
	return 0;
}
相关推荐
机器人梦想家4 分钟前
具身机器人视觉服务的异步回调与并发控制
数据库·算法·机器人
_wxd6661 小时前
STL-stack与queue与priority_queue(容器适配器)
c++
我命由我123451 小时前
人脸识别 - 人脸识别选帧
java·人工智能·python·算法·安全·java-ee·人脸识别
时针滴滴答啊1 小时前
最大子数组和
算法·leetcode·职场和发展
zh路西法2 小时前
【玩转VLA具身智能机械臂】(二):MoveIt2 运动规划——架构、配置与 C++ 上手
c++·机械臂·路径规划·vla·planner·moveit2
五月底_2 小时前
LIS算法
python·算法·最长子序列
学学酱快乐2 小时前
2026年PMP考试生命周期选择决策树精讲:从需求判断到混合型统一框架的应试全攻略
算法·决策树·机器学习·pmp新版考试大纲·pmp新题型·pmp培训哪家好·pmp培训机构推荐
爱和冰阔落2 小时前
【Linux】Ctrl+C 到底做了什么?从键盘、kill 到 alarm,一次讲清信号的产生
linux·运维·c++·安卓
傅科摆 _ py2 小时前
动态规划复习
算法·动态规划
水饺编程3 小时前
第5章,[Win32 章节] :贝塞尔样条曲线(一)
c语言·c++·windows·visual studio