A. Rudolph and Cut the Rope

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

There are n� nails driven into the wall, the i�-th nail is driven ai�� meters above the ground, one end of the bi�� meters long rope is tied to it. All nails hang at different heights one above the other. One candy is tied to all ropes at once. Candy is tied to end of a rope that is not tied to a nail.

To take the candy, you need to lower it to the ground. To do this, Rudolph can cut some ropes, one at a time. Help Rudolph find the minimum number of ropes that must be cut to get the candy.

The figure shows an example of the first test:

Input

The first line contains one integer t� (1≤t≤1041≤�≤104) --- the number of test cases.

The first line of each test case contains one integer n� (1≤n≤501≤�≤50) --- the number of nails.

The i�-th of the next n� lines contains two integers ai�� and bi�� (1≤ai,bi≤2001≤��,��≤200) --- the height of the i�-th nail and the length of the rope tied to it, all ai�� are different.

It is guaranteed that the data is not contradictory, it is possible to build a configuration described in the statement.

Output

For each test case print one integer --- the minimum number of ropes that need to be cut to make the candy fall to the ground.

Example

input

Copy

复制代码

4

3

4 3

3 1

1 2

4

9 2

5 2

7 7

3 4

5

11 7

5 10

12 9

3 2

1 5

3

5 6

4 5

7 7

output

Copy

复制代码
2
2
3
0

解题说明:水题,此题分析一下就能发现,只要绳子长度小于高度,那就必须要切断才能让糖果落地,直接判断即可。

cpp 复制代码
#include<stdio.h>
int main()
{
	int m, n, a, b, ans;
	scanf("%d", &n);
	for (int i = 0; i < n; i++)
	{
		ans = 0;
		scanf("%d", &m);
		for (int j = 0; j < m; j++)
		{
			scanf("%d %d", &a, &b);
			if (a > b)
			{
				ans++;
			}
		}
		printf("%d\n", ans);
	}
	return 0;
}
相关推荐
【 】4237 小时前
C++&STL(Standard Template Library,标准模板库)
java·开发语言·c++
Wect8 小时前
LeetCode 5. 最长回文子串:DP + 中心扩展
前端·算法·typescript
一只牛_0078 小时前
pthread亲和性继承的一个坑:main绑核让整个进程退化到单核
c++
糖果店的幽灵8 小时前
决策树详解与sklearn实战
算法·决策树·sklearn
Lewiis8 小时前
趣谈排序算法
算法·排序算法
ComputerInBook8 小时前
数字图像处理(4版)——第 8 章——图像压缩与水印(上)(Rafael C.Gonzalez&Richard E. Woods)
人工智能·算法·计算机视觉·图像压缩·图像水印
刀法如飞8 小时前
Python列表去重:从新手三连到高阶特技,20种解法全收录
python·算法·编程语言
minji...8 小时前
算法题 动态规划
算法·动态规划
张健11564096488 小时前
C++访问控制与友元
java·开发语言·c++
水蓝烟雨9 小时前
3337. 字符串转换后的长度 II
算法·leetcode