A. Rudolph and Cut the Rope

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

There are n� nails driven into the wall, the i�-th nail is driven ai�� meters above the ground, one end of the bi�� meters long rope is tied to it. All nails hang at different heights one above the other. One candy is tied to all ropes at once. Candy is tied to end of a rope that is not tied to a nail.

To take the candy, you need to lower it to the ground. To do this, Rudolph can cut some ropes, one at a time. Help Rudolph find the minimum number of ropes that must be cut to get the candy.

The figure shows an example of the first test:

Input

The first line contains one integer t� (1≤t≤1041≤�≤104) --- the number of test cases.

The first line of each test case contains one integer n� (1≤n≤501≤�≤50) --- the number of nails.

The i�-th of the next n� lines contains two integers ai�� and bi�� (1≤ai,bi≤2001≤��,��≤200) --- the height of the i�-th nail and the length of the rope tied to it, all ai�� are different.

It is guaranteed that the data is not contradictory, it is possible to build a configuration described in the statement.

Output

For each test case print one integer --- the minimum number of ropes that need to be cut to make the candy fall to the ground.

Example

input

Copy

复制代码

4

3

4 3

3 1

1 2

4

9 2

5 2

7 7

3 4

5

11 7

5 10

12 9

3 2

1 5

3

5 6

4 5

7 7

output

Copy

复制代码
2
2
3
0

解题说明:水题,此题分析一下就能发现,只要绳子长度小于高度,那就必须要切断才能让糖果落地,直接判断即可。

cpp 复制代码
#include<stdio.h>
int main()
{
	int m, n, a, b, ans;
	scanf("%d", &n);
	for (int i = 0; i < n; i++)
	{
		ans = 0;
		scanf("%d", &m);
		for (int j = 0; j < m; j++)
		{
			scanf("%d %d", &a, &b);
			if (a > b)
			{
				ans++;
			}
		}
		printf("%d\n", ans);
	}
	return 0;
}
相关推荐
浅念-2 小时前
递归解题指南:LeetCode经典题全解析
数据结构·算法·leetcode·职场和发展·排序算法·深度优先·递归
Kiling_07043 小时前
Java集合进阶:Set与Collections详解
算法·哈希算法
智者知已应修善业3 小时前
【51单片机89C51及74LS273、74LS244组成】2022-5-28
c++·经验分享·笔记·算法·51单片机
洛水水3 小时前
【力扣100题】33.验证二叉搜索树
算法·leetcode·职场和发展
SimpleLearingAI3 小时前
聚类算法详解
算法·数据挖掘·聚类
刀法如飞4 小时前
Go 字符串查找的 20 种实现方式,用不同思路解决问题
算法·面试·程序员
Byron Loong6 小时前
【c++】为什么有了dll和.h,还需要包含lib
java·开发语言·c++
Dlrb12116 小时前
C语言-指针数组与数组指针
c语言·数据结构·算法·指针·数组指针·指针数组·二级指针
WL_Aurora6 小时前
Python 算法基础篇之集合
python·算法
坚果派·白晓明6 小时前
【鸿蒙PC三方库移植适配框架解读系列】第一篇:Lycium C/C++ 三方库适配 — 概述与环境配置
c语言·开发语言·c++·harmonyos·开源鸿蒙·三方库·c/c++三方库