A. Rudolph and Cut the Rope

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

There are n� nails driven into the wall, the i�-th nail is driven ai�� meters above the ground, one end of the bi�� meters long rope is tied to it. All nails hang at different heights one above the other. One candy is tied to all ropes at once. Candy is tied to end of a rope that is not tied to a nail.

To take the candy, you need to lower it to the ground. To do this, Rudolph can cut some ropes, one at a time. Help Rudolph find the minimum number of ropes that must be cut to get the candy.

The figure shows an example of the first test:

Input

The first line contains one integer t� (1≤t≤1041≤�≤104) --- the number of test cases.

The first line of each test case contains one integer n� (1≤n≤501≤�≤50) --- the number of nails.

The i�-th of the next n� lines contains two integers ai�� and bi�� (1≤ai,bi≤2001≤��,��≤200) --- the height of the i�-th nail and the length of the rope tied to it, all ai�� are different.

It is guaranteed that the data is not contradictory, it is possible to build a configuration described in the statement.

Output

For each test case print one integer --- the minimum number of ropes that need to be cut to make the candy fall to the ground.

Example

input

Copy

复制代码

4

3

4 3

3 1

1 2

4

9 2

5 2

7 7

3 4

5

11 7

5 10

12 9

3 2

1 5

3

5 6

4 5

7 7

output

Copy

复制代码
2
2
3
0

解题说明:水题,此题分析一下就能发现,只要绳子长度小于高度,那就必须要切断才能让糖果落地,直接判断即可。

cpp 复制代码
#include<stdio.h>
int main()
{
	int m, n, a, b, ans;
	scanf("%d", &n);
	for (int i = 0; i < n; i++)
	{
		ans = 0;
		scanf("%d", &m);
		for (int j = 0; j < m; j++)
		{
			scanf("%d %d", &a, &b);
			if (a > b)
			{
				ans++;
			}
		}
		printf("%d\n", ans);
	}
	return 0;
}
相关推荐
罗西的思考2 小时前
机器人 / 强化学习】HIL-SERL:人类在环驱动的具身智能进化框架
人工智能·算法·机器学习
CSharp精选营4 小时前
关系型 vs 非关系型:从原理到选型,一文搞定数据库核心分类
数据结构·nosql·关系型数据库·非关系型数据库·技术选型
美团技术团队5 小时前
LongCat 开源 VitaBench 2.0:长期动态智能体基准新标杆
人工智能·算法
用户8055336980312 小时前
不止三件套:QObject 属性系统全关键字与运行时反射!
c++·qt
To_OC1 天前
LC 207 课程表:刚学图论那会儿,我连这是拓扑排序都没看出来
javascript·算法·leetcode
To_OC1 天前
LC 208 实现 Trie 前缀树:曾被名字劝退,写完发现是送分题
javascript·算法·leetcode
BadBadBad__AK1 天前
线段树维护区间 k 次方和
c++·数学·算法·stl
卷无止境1 天前
Eigen 库如何借助 OpenMP 加速计算
c++·后端
_清歌2 天前
DSpark 深度解读:DeepSeek-V4 如何用「半自回归」把推理速度提升 85%
算法