LeetCode //C - 48. Rotate Image

48. Rotate Image

You are given an n x n 2D matri x representing an image, rotate the image by 90 degrees (clockwise).

You have to rotate the image in-place , which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.

Example 1:

Input: matrix = \[1,2,3,4,5,6,7,8,9]
Output: \[7,4,1,8,5,2,9,6,3]

Example 2:

Input: matrix = \[5,1,9,11,2,4,8,10,13,3,6,7,15,14,12,16]
Output: \[15,13,2,5,14,3,4,1,12,6,8,9,16,7,10,11]

Constraints:

• n == matrix.length == matrixi.length
• 1 <= n <= 20
• -1000 <= matrixij <= 1000

From: LeetCode

Link: 48. Rotate Image

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Solution:

Ideas：

To rotate a matrix by 90 degrees clockwise in place, we can follow a two-step process:

1. Transpose the Matrix: The transpose of a matrix is obtained by swapping rows and columns. This means

   matrixij will become matrixji.

2. Reverse the Rows: Reverse each row of the transposed matrix.

Following these steps will give us the rotated matrix.

Code:

void rotate(int** matrix, int matrixSize, int* matrixColSize) {
    // Transpose the matrix
    for (int i = 0; i < matrixSize; i++) {
        for (int j = i; j < matrixSize; j++) {
            int temp = matrix[i][j];
            matrix[i][j] = matrix[j][i];
            matrix[j][i] = temp;
        }
    }

    // Reverse each row
    for (int i = 0; i < matrixSize; i++) {
        for (int j = 0, k = matrixSize - 1; j < k; j++, k--) {
            int temp = matrix[i][j];
            matrix[i][j] = matrix[i][k];
            matrix[i][k] = temp;
        }
    }
}