hive 谓词下推实例分析(on与where的区别)

测试数据

  • t1 表
bash 复制代码
select * from t1;
+--------+----------+---------+--------+
| t1.id  | t1.name  | t1.age  | t1.dt  |
+--------+----------+---------+--------+
| 1      | aa       | 12      | 01     |
| 1      | aa       | 12      | 02     |
| 2      | aa       | 14      | 01     |
| 2      | bb       | 14      | 02     |
| 3      | cc       | 16      | 02     |
| NULL   | aa       | 12      | 01     |
+--------+----------+---------+--------+
  • t2 表
bash 复制代码
select * from t2;
+--------+----------+---------+--------+
| t2.id  | t2.name  | t2.age  | t2.dt  |
+--------+----------+---------+--------+
| 1      | 1        | aa      | 12     |
| 2      | 1        | aa      | 12     |
| 1      | NULL     | aa      | 12     |
| 1      | 2        | aa      | 14     |
| 2      | 2        | bb      | 14     |
| 2      | 3        | cc      | 16     |
+--------+----------+---------+--------+

关联查询

  • t1 left join t2
bash 复制代码
select * from t1 a left join t2 b on a.id=b.id;
+-------+---------+--------+-------+-------+---------+--------+-------+
| a.id  | a.name  | a.age  | a.dt  | b.id  | b.name  | b.age  | b.dt  |
+-------+---------+--------+-------+-------+---------+--------+-------+
| 3     | cc      | 16     | 02    | NULL  | NULL    | NULL   | NULL  |
| NULL  | aa      | 12     | 01    | NULL  | NULL    | NULL   | NULL  |
| 1     | aa      | 12     | 01    | 1     | NULL    | aa     | 12    |
| 1     | aa      | 12     | 01    | 1     | 1       | aa     | 12    |
| 1     | aa      | 12     | 01    | 1     | 2       | aa     | 14    |
| 1     | aa      | 12     | 02    | 1     | NULL    | aa     | 12    |
| 1     | aa      | 12     | 02    | 1     | 1       | aa     | 12    |
| 1     | aa      | 12     | 02    | 1     | 2       | aa     | 14    |
| 2     | aa      | 14     | 01    | 2     | 3       | cc     | 16    |
| 2     | aa      | 14     | 01    | 2     | 1       | aa     | 12    |
| 2     | aa      | 14     | 01    | 2     | 2       | bb     | 14    |
| 2     | bb      | 14     | 02    | 2     | 3       | cc     | 16    |
| 2     | bb      | 14     | 02    | 2     | 1       | aa     | 12    |
| 2     | bb      | 14     | 02    | 2     | 2       | bb     | 14    |
+-------+---------+--------+-------+-------+---------+--------+-------+
  • t1 left join t2 on a.id=b.id where a.dt ='01',保留表谓词下推,map端提前过滤
bash 复制代码
select * from t1 a left join t2 b on a.id=b.id where a.dt ='01';
+-------+---------+--------+-------+-------+---------+--------+-------+
| a.id  | a.name  | a.age  | a.dt  | b.id  | b.name  | b.age  | b.dt  |
+-------+---------+--------+-------+-------+---------+--------+-------+
| NULL  | aa      | 12     | 01    | NULL  | NULL    | NULL   | NULL  |
| 1     | aa      | 12     | 01    | 1     | NULL    | aa     | 12    |
| 1     | aa      | 12     | 01    | 1     | 1       | aa     | 12    |
| 1     | aa      | 12     | 01    | 1     | 2       | aa     | 14    |
| 2     | aa      | 14     | 01    | 2     | 3       | cc     | 16    |
| 2     | aa      | 14     | 01    | 2     | 1       | aa     | 12    |
| 2     | aa      | 14     | 01    | 2     | 2       | bb     | 14    |
+-------+---------+--------+-------+-------+---------+--------+-------+
  • t1 left join t2 on a.id=b.id and a.dt ='01',保留表非谓词下推,reduce端过滤
bash 复制代码
select * from t1 a left join t2 b on a.id=b.id and a.dt ='01';
+-------+---------+--------+-------+-------+---------+--------+-------+
| a.id  | a.name  | a.age  | a.dt  | b.id  | b.name  | b.age  | b.dt  |
+-------+---------+--------+-------+-------+---------+--------+-------+
| 1     | aa      | 12     | 02    | NULL  | NULL    | NULL   | NULL  |
| 2     | bb      | 14     | 02    | NULL  | NULL    | NULL   | NULL  |
| 3     | cc      | 16     | 02    | NULL  | NULL    | NULL   | NULL  |
| NULL  | aa      | 12     | 01    | NULL  | NULL    | NULL   | NULL  |
| 1     | aa      | 12     | 01    | 1     | 2       | aa     | 14    |
| 1     | aa      | 12     | 01    | 1     | NULL    | aa     | 12    |
| 1     | aa      | 12     | 01    | 1     | 1       | aa     | 12    |
| 2     | aa      | 14     | 01    | 2     | 2       | bb     | 14    |
| 2     | aa      | 14     | 01    | 2     | 3       | cc     | 16    |
| 2     | aa      | 14     | 01    | 2     | 1       | aa     | 12    |
+-------+---------+--------+-------+-------+---------+--------+-------+

说明:保留表应用谓词下推,提前过滤,会把不符合条件的数据提前过滤掉;保留表不应用谓词下推,不提前过滤,只能在join发生时,不符合条件的数据不参与关联计算;

  • t1 left join t2 on a.id=b.id and b.dt ='12',空表谓词下推,map端过滤
bash 复制代码
select * from t1 a left join t2 b on a.id=b.id and b.dt ='12';
+-------+---------+--------+-------+-------+---------+--------+-------+
| a.id  | a.name  | a.age  | a.dt  | b.id  | b.name  | b.age  | b.dt  |
+-------+---------+--------+-------+-------+---------+--------+-------+
| 2     | aa      | 14     | 01    | 2     | 1       | aa     | 12    |
| 2     | bb      | 14     | 02    | 2     | 1       | aa     | 12    |
| 3     | cc      | 16     | 02    | NULL  | NULL    | NULL   | NULL  |
| NULL  | aa      | 12     | 01    | NULL  | NULL    | NULL   | NULL  |
| 1     | aa      | 12     | 01    | 1     | NULL    | aa     | 12    |
| 1     | aa      | 12     | 01    | 1     | 1       | aa     | 12    |
| 1     | aa      | 12     | 02    | 1     | NULL    | aa     | 12    |
| 1     | aa      | 12     | 02    | 1     | 1       | aa     | 12    |
+-------+---------+--------+-------+-------+---------+--------+-------+
  • t1 left join t2 on a.id=b.id where b.dt ='12',空表非谓词下推,reduce端过滤
bash 复制代码
select * from t1 a left join t2 b on a.id=b.id where b.dt ='12';
+-------+---------+--------+-------+-------+---------+--------+-------+
| a.id  | a.name  | a.age  | a.dt  | b.id  | b.name  | b.age  | b.dt  |
+-------+---------+--------+-------+-------+---------+--------+-------+
| 2     | aa      | 14     | 01    | 2     | 1       | aa     | 12    |
| 2     | bb      | 14     | 02    | 2     | 1       | aa     | 12    |
| 1     | aa      | 12     | 01    | 1     | NULL    | aa     | 12    |
| 1     | aa      | 12     | 01    | 1     | 1       | aa     | 12    |
| 1     | aa      | 12     | 02    | 1     | NULL    | aa     | 12    |
| 1     | aa      | 12     | 02    | 1     | 1       | aa     | 12    |
+-------+---------+--------+-------+-------+---------+--------+-------+

说明:空表应用谓词下推,提前过滤,会把不符合条件的数据提前过滤掉;空表不应用谓词下推,不提前过滤,只能在join完成时,过滤不符合条件的数据;

总结 : 是否应用谓词下推,最后产生的结果往往不同,这里需要特别注意。

参考:
一文弄懂Hive中谓词下推(on与where的区别)

相关推荐
郑州光合科技余经理12 分钟前
PHP构建:支撑欧美澳市场的同城生活服务平台开发
java·开发语言·数据库·uni-app·php·排序算法·生活
超级大只老咪7 小时前
数组相邻元素比较的循环条件(Java竞赛考点)
java
小浣熊熊熊熊熊熊熊丶7 小时前
《Effective Java》第25条:限制源文件为单个顶级类
java·开发语言·effective java
howard20058 小时前
Hive实战任务 - 9.1 实现词频统计
hive·词频统计
毕设源码-钟学长8 小时前
【开题答辩全过程】以 公交管理系统为例,包含答辩的问题和答案
java·eclipse
啃火龙果的兔子8 小时前
JDK 安装配置
java·开发语言
星哥说事8 小时前
应用程序监控:Java 与 Web 应用的实践
java·开发语言
派大鑫wink8 小时前
【JAVA学习日志】SpringBoot 参数配置:从基础到实战,解锁灵活配置新姿势
java·spring boot·后端
xUxIAOrUIII8 小时前
【Spring Boot】控制器Controller方法
java·spring boot·后端
Dolphin_Home8 小时前
从理论到实战:图结构在仓库关联业务中的落地(小白→中级,附完整代码)
java·spring boot·后端·spring cloud·database·广度优先·图搜索算法