LeetCode //C - 211. Design Add and Search Words Data Structure

Design a data structure that supports adding new words and finding if a string matches any previously added string.

Implement the WordDictionary class:

  • WordDictionary() Initializes the object.
  • void addWord(word) Adds word to the data structure, it can be matched later.
  • bool search(word) Returns true if there is any string in the data structure that matches word or false otherwise. word may contain dots '.' where dots can be matched with any letter.
Example:

Input:

"WordDictionary","addWord","addWord","addWord","search","search","search","search"

\[\],\["bad"\],\["dad"\],\["mad"\],\["pad"\],\["bad"\],\[".ad"\],\["b..."\]

Output:

null,null,null,null,false,true,true,true

Explanation:

WordDictionary wordDictionary = new WordDictionary();

wordDictionary.addWord("bad");

wordDictionary.addWord("dad");

wordDictionary.addWord("mad");

wordDictionary.search("pad"); // return False

wordDictionary.search("bad"); // return True

wordDictionary.search(".ad"); // return True

wordDictionary.search("b..."); // return True

Constraints:
  • 1 <= word.length <= 25
  • word in addWord consists of lowercase English letters.
  • word in search consist of '.' or lowercase English letters.
  • There will be at most 2 dots in word for search queries.
  • At most 1 0 4 10^4 104 calls will be made to addWord and search.

From: LeetCode

Link: 211. Design Add and Search Words Data Structure


Solution:

Ideas:

1. TrieNode Structure:

Each node in the Trie is represented by a TrieNode structure. It has the following components:

  • An array of pointers, children, where each pointer corresponds to a letter in the English alphabet (26 lowercase letters).
  • A boolean flag, isEndOfWord, to signify whether a word ends at this node.

2. WordDictionary Structure:

The WordDictionary itself is represented by a structure, which holds a pointer to the root node of the Trie.

3. wordDictionaryCreate:

This function initializes the WordDictionary object and allocates memory for the root node of the Trie.

4. wordDictionaryAddWord:

This function is used to insert words into the Trie. For each character in the word, it traverses down the Trie, creating new nodes if needed, until the end of the word is reached, at which point it sets the isEndOfWord flag to true.

5. wordDictionarySearch and searchHelper:

  • The wordDictionarySearch function is used to search for a word in the Trie, with support for the . character, which can match any letter.
  • It calls a helper function searchHelper, which performs a recursive search to handle the . character.
  • If the searchHelper encounters a . character, it recursively checks all its children.
  • If it can traverse the entire word and reach a node where isEndOfWord is true, it returns true; otherwise, it returns false.

6. wordDictionaryFree and freeNode:

  • These functions deallocate the memory used by the WordDictionary and its nodes.
  • freeNode is a recursive function that frees all the child nodes before freeing the parent node.
Code:
c 复制代码
#define ALPHABET_SIZE 26

typedef struct TrieNode {
    struct TrieNode *children[ALPHABET_SIZE];
    bool isEndOfWord;
} TrieNode;

typedef struct {
    TrieNode *root;
} WordDictionary;

TrieNode* createNode() {
    TrieNode *newNode = (TrieNode *)calloc(1, sizeof(TrieNode));
    return newNode;
}

WordDictionary* wordDictionaryCreate() {
    WordDictionary *dict = (WordDictionary *)malloc(sizeof(WordDictionary));
    dict->root = createNode();
    return dict;
}

void wordDictionaryAddWord(WordDictionary* obj, char * word) {
    TrieNode *node = obj->root;
    for (int i = 0; word[i] != '\0'; i++) {
        int index = word[i] - 'a';
        if (!node->children[index])
            node->children[index] = createNode();
        node = node->children[index];
    }
    node->isEndOfWord = true;
}

bool searchHelper(TrieNode *node, char *word) {
    for (int i = 0; word[i] != '\0'; i++) {
        if (word[i] == '.') {
            for (int j = 0; j < ALPHABET_SIZE; j++) {
                if (node->children[j] && searchHelper(node->children[j], word + i + 1))
                    return true;
            }
            return false;
        } else {
            int index = word[i] - 'a';
            if (!node->children[index])
                return false;
            node = node->children[index];
        }
    }
    return node->isEndOfWord;
}

bool wordDictionarySearch(WordDictionary* obj, char * word) {
    return searchHelper(obj->root, word);
}

void freeNode(TrieNode *node) {
    for(int i = 0; i < ALPHABET_SIZE; i++)
        if(node->children[i])
            freeNode(node->children[i]);
    free(node);
}

void wordDictionaryFree(WordDictionary* obj) {
    if(!obj) return;
    freeNode(obj->root);
    free(obj);
}

/**
 * Your WordDictionary struct will be instantiated and called as such:
 * WordDictionary* obj = wordDictionaryCreate();
 * wordDictionaryAddWord(obj, word);
 
 * bool param_2 = wordDictionarySearch(obj, word);
 
 * wordDictionaryFree(obj);
*/
相关推荐
天空'之城1 小时前
C 语言工业级通用组件手写 06:固定块内存池
c语言·嵌入式开发·内存池·底层优化
香辣牛肉饭1 小时前
【算法】动态规划 最长公共子序列(LCS)
经验分享·笔记·算法·动态规划
.徐十三.2 小时前
一篇文章看到最短路径——Dijkstra算法
算法
十月的皮皮2 小时前
stm20260720-从新手 C 到量产 STM32 工程:程序设计推导指南
c语言·开发语言·stm32·stm32cubemx·hal库
Echo缘3 小时前
嵌入式系统C语言资源分类与内存分布分析
c语言·开发语言
科学实验家3 小时前
二叉树的几道题
算法
abcy0712134 小时前
flink state实例
大数据·算法·flink
qizayaoshuap4 小时前
# [特殊字符] 密码生成器 — 鸿蒙ArkTS安全算法与密码强度评估系统
java·算法·安全·华为·harmonyos
良木林4 小时前
滑动窗口 - LeetCode hot 100
javascript·算法·leetcode·双指针·滑动窗口