LeetCode //C - 211. Design Add and Search Words Data Structure

Design a data structure that supports adding new words and finding if a string matches any previously added string.

Implement the WordDictionary class:

  • WordDictionary() Initializes the object.
  • void addWord(word) Adds word to the data structure, it can be matched later.
  • bool search(word) Returns true if there is any string in the data structure that matches word or false otherwise. word may contain dots '.' where dots can be matched with any letter.
Example:

Input:

"WordDictionary","addWord","addWord","addWord","search","search","search","search"

\[\],\["bad"\],\["dad"\],\["mad"\],\["pad"\],\["bad"\],\[".ad"\],\["b..."\]

Output:

null,null,null,null,false,true,true,true

Explanation:

WordDictionary wordDictionary = new WordDictionary();

wordDictionary.addWord("bad");

wordDictionary.addWord("dad");

wordDictionary.addWord("mad");

wordDictionary.search("pad"); // return False

wordDictionary.search("bad"); // return True

wordDictionary.search(".ad"); // return True

wordDictionary.search("b..."); // return True

Constraints:
  • 1 <= word.length <= 25
  • word in addWord consists of lowercase English letters.
  • word in search consist of '.' or lowercase English letters.
  • There will be at most 2 dots in word for search queries.
  • At most 1 0 4 10^4 104 calls will be made to addWord and search.

From: LeetCode

Link: 211. Design Add and Search Words Data Structure


Solution:

Ideas:

1. TrieNode Structure:

Each node in the Trie is represented by a TrieNode structure. It has the following components:

  • An array of pointers, children, where each pointer corresponds to a letter in the English alphabet (26 lowercase letters).
  • A boolean flag, isEndOfWord, to signify whether a word ends at this node.

2. WordDictionary Structure:

The WordDictionary itself is represented by a structure, which holds a pointer to the root node of the Trie.

3. wordDictionaryCreate:

This function initializes the WordDictionary object and allocates memory for the root node of the Trie.

4. wordDictionaryAddWord:

This function is used to insert words into the Trie. For each character in the word, it traverses down the Trie, creating new nodes if needed, until the end of the word is reached, at which point it sets the isEndOfWord flag to true.

5. wordDictionarySearch and searchHelper:

  • The wordDictionarySearch function is used to search for a word in the Trie, with support for the . character, which can match any letter.
  • It calls a helper function searchHelper, which performs a recursive search to handle the . character.
  • If the searchHelper encounters a . character, it recursively checks all its children.
  • If it can traverse the entire word and reach a node where isEndOfWord is true, it returns true; otherwise, it returns false.

6. wordDictionaryFree and freeNode:

  • These functions deallocate the memory used by the WordDictionary and its nodes.
  • freeNode is a recursive function that frees all the child nodes before freeing the parent node.
Code:
c 复制代码
#define ALPHABET_SIZE 26

typedef struct TrieNode {
    struct TrieNode *children[ALPHABET_SIZE];
    bool isEndOfWord;
} TrieNode;

typedef struct {
    TrieNode *root;
} WordDictionary;

TrieNode* createNode() {
    TrieNode *newNode = (TrieNode *)calloc(1, sizeof(TrieNode));
    return newNode;
}

WordDictionary* wordDictionaryCreate() {
    WordDictionary *dict = (WordDictionary *)malloc(sizeof(WordDictionary));
    dict->root = createNode();
    return dict;
}

void wordDictionaryAddWord(WordDictionary* obj, char * word) {
    TrieNode *node = obj->root;
    for (int i = 0; word[i] != '\0'; i++) {
        int index = word[i] - 'a';
        if (!node->children[index])
            node->children[index] = createNode();
        node = node->children[index];
    }
    node->isEndOfWord = true;
}

bool searchHelper(TrieNode *node, char *word) {
    for (int i = 0; word[i] != '\0'; i++) {
        if (word[i] == '.') {
            for (int j = 0; j < ALPHABET_SIZE; j++) {
                if (node->children[j] && searchHelper(node->children[j], word + i + 1))
                    return true;
            }
            return false;
        } else {
            int index = word[i] - 'a';
            if (!node->children[index])
                return false;
            node = node->children[index];
        }
    }
    return node->isEndOfWord;
}

bool wordDictionarySearch(WordDictionary* obj, char * word) {
    return searchHelper(obj->root, word);
}

void freeNode(TrieNode *node) {
    for(int i = 0; i < ALPHABET_SIZE; i++)
        if(node->children[i])
            freeNode(node->children[i]);
    free(node);
}

void wordDictionaryFree(WordDictionary* obj) {
    if(!obj) return;
    freeNode(obj->root);
    free(obj);
}

/**
 * Your WordDictionary struct will be instantiated and called as such:
 * WordDictionary* obj = wordDictionaryCreate();
 * wordDictionaryAddWord(obj, word);
 
 * bool param_2 = wordDictionarySearch(obj, word);
 
 * wordDictionaryFree(obj);
*/
相关推荐
罗西的思考13 小时前
机器人 / 强化学习】HIL-SERL:人类在环驱动的具身智能进化框架
人工智能·算法·机器学习
美团技术团队16 小时前
LongCat 开源 VitaBench 2.0:长期动态智能体基准新标杆
人工智能·算法
To_OC1 天前
LC 207 课程表:刚学图论那会儿,我连这是拓扑排序都没看出来
javascript·算法·leetcode
To_OC1 天前
LC 208 实现 Trie 前缀树:曾被名字劝退,写完发现是送分题
javascript·算法·leetcode
BadBadBad__AK1 天前
线段树维护区间 k 次方和
c++·数学·算法·stl
_清歌2 天前
DSpark 深度解读:DeepSeek-V4 如何用「半自回归」把推理速度提升 85%
算法
统计实现局2 天前
SVD 的三步走:双对角化、Givens 收敛、排序
算法
躬行见万象2 天前
《VLA 系列》UniLab 强化训练 | G1 机器人 |复现
算法
统计实现局2 天前
对称不定分解(Bunch-Kaufman):为什么 Cholesky 不够用
算法