LeetCode //C - 211. Design Add and Search Words Data Structure

Design a data structure that supports adding new words and finding if a string matches any previously added string.

Implement the WordDictionary class:

  • WordDictionary() Initializes the object.
  • void addWord(word) Adds word to the data structure, it can be matched later.
  • bool search(word) Returns true if there is any string in the data structure that matches word or false otherwise. word may contain dots '.' where dots can be matched with any letter.
Example:

Input:

"WordDictionary","addWord","addWord","addWord","search","search","search","search"

\[\],\["bad"\],\["dad"\],\["mad"\],\["pad"\],\["bad"\],\[".ad"\],\["b..."\]

Output:

null,null,null,null,false,true,true,true

Explanation:

WordDictionary wordDictionary = new WordDictionary();

wordDictionary.addWord("bad");

wordDictionary.addWord("dad");

wordDictionary.addWord("mad");

wordDictionary.search("pad"); // return False

wordDictionary.search("bad"); // return True

wordDictionary.search(".ad"); // return True

wordDictionary.search("b..."); // return True

Constraints:
  • 1 <= word.length <= 25
  • word in addWord consists of lowercase English letters.
  • word in search consist of '.' or lowercase English letters.
  • There will be at most 2 dots in word for search queries.
  • At most 1 0 4 10^4 104 calls will be made to addWord and search.

From: LeetCode

Link: 211. Design Add and Search Words Data Structure


Solution:

Ideas:

1. TrieNode Structure:

Each node in the Trie is represented by a TrieNode structure. It has the following components:

  • An array of pointers, children, where each pointer corresponds to a letter in the English alphabet (26 lowercase letters).
  • A boolean flag, isEndOfWord, to signify whether a word ends at this node.

2. WordDictionary Structure:

The WordDictionary itself is represented by a structure, which holds a pointer to the root node of the Trie.

3. wordDictionaryCreate:

This function initializes the WordDictionary object and allocates memory for the root node of the Trie.

4. wordDictionaryAddWord:

This function is used to insert words into the Trie. For each character in the word, it traverses down the Trie, creating new nodes if needed, until the end of the word is reached, at which point it sets the isEndOfWord flag to true.

5. wordDictionarySearch and searchHelper:

  • The wordDictionarySearch function is used to search for a word in the Trie, with support for the . character, which can match any letter.
  • It calls a helper function searchHelper, which performs a recursive search to handle the . character.
  • If the searchHelper encounters a . character, it recursively checks all its children.
  • If it can traverse the entire word and reach a node where isEndOfWord is true, it returns true; otherwise, it returns false.

6. wordDictionaryFree and freeNode:

  • These functions deallocate the memory used by the WordDictionary and its nodes.
  • freeNode is a recursive function that frees all the child nodes before freeing the parent node.
Code:
c 复制代码
#define ALPHABET_SIZE 26

typedef struct TrieNode {
    struct TrieNode *children[ALPHABET_SIZE];
    bool isEndOfWord;
} TrieNode;

typedef struct {
    TrieNode *root;
} WordDictionary;

TrieNode* createNode() {
    TrieNode *newNode = (TrieNode *)calloc(1, sizeof(TrieNode));
    return newNode;
}

WordDictionary* wordDictionaryCreate() {
    WordDictionary *dict = (WordDictionary *)malloc(sizeof(WordDictionary));
    dict->root = createNode();
    return dict;
}

void wordDictionaryAddWord(WordDictionary* obj, char * word) {
    TrieNode *node = obj->root;
    for (int i = 0; word[i] != '\0'; i++) {
        int index = word[i] - 'a';
        if (!node->children[index])
            node->children[index] = createNode();
        node = node->children[index];
    }
    node->isEndOfWord = true;
}

bool searchHelper(TrieNode *node, char *word) {
    for (int i = 0; word[i] != '\0'; i++) {
        if (word[i] == '.') {
            for (int j = 0; j < ALPHABET_SIZE; j++) {
                if (node->children[j] && searchHelper(node->children[j], word + i + 1))
                    return true;
            }
            return false;
        } else {
            int index = word[i] - 'a';
            if (!node->children[index])
                return false;
            node = node->children[index];
        }
    }
    return node->isEndOfWord;
}

bool wordDictionarySearch(WordDictionary* obj, char * word) {
    return searchHelper(obj->root, word);
}

void freeNode(TrieNode *node) {
    for(int i = 0; i < ALPHABET_SIZE; i++)
        if(node->children[i])
            freeNode(node->children[i]);
    free(node);
}

void wordDictionaryFree(WordDictionary* obj) {
    if(!obj) return;
    freeNode(obj->root);
    free(obj);
}

/**
 * Your WordDictionary struct will be instantiated and called as such:
 * WordDictionary* obj = wordDictionaryCreate();
 * wordDictionaryAddWord(obj, word);
 
 * bool param_2 = wordDictionarySearch(obj, word);
 
 * wordDictionaryFree(obj);
*/
相关推荐
京东云开发者40 分钟前
从“会生成”到“能生产”:萤火虫 AIGC 平台的 AI Infra 实践
算法·aigc·产品
youshi666842 分钟前
PID——算法改进
算法
文丑颜不良啊1 小时前
LeetCode1861~1880题目解析
java·leetcode
文丑颜不良啊2 小时前
LeetCode1921~1940题目解析
java·leetcode
一只不想敲代码的程序猿2 小时前
如何更高效地拆解问题?
算法
微尘hjx3 小时前
【Deep-OC-SORT 02】多轨迹算法Deep-OC-SORT-相对 OC-SORT 的改进点
人工智能·算法·yolo·目标跟踪·视觉检测·ultralytics·deep-oc-sort
梦帮科技3 小时前
意识启发式量子隧穿退火算法用于全局优化 (CITA) 完整技术指南
网络·人工智能·算法·量子计算·模拟退火算法
一去不复返的通信er4 小时前
排序 + 双指针:力扣15三数之和
算法·leetcode
文丑颜不良啊4 小时前
LeetCode1901~1920题目解析
java·leetcode
Pniubi5 小时前
力扣3无重复字符的最长字串(滑动窗口)
算法·leetcode·职场和发展