【LeetCode热题100】--121.买卖股票的最佳时机

121.买卖股票的最佳时机

class Solution {
    public int maxProfit(int[] prices) {
        int minprice = Integer.MAX_VALUE;
        int maxprofit = 0;
        for(int i =0;i<prices.length;i++){
            if(prices[i] < minprice){
                minprice = prices[i]; //找到最小值
            }else if(prices[i] - minprice > maxprofit){ //记录之后与最小值之间得差值
                maxprofit = prices[i] - minprice;  
            }
        }
        return maxprofit;

    }
}