LeetCode每日一题——275. H-Index II

文章目录

一、题目

Given an array of integers citations where citations[i] is the number of citations a researcher received for their ith paper and citations is sorted in ascending order, return the researcher's h-index.

According to the definition of h-index on Wikipedia: The h-index is defined as the maximum value of h such that the given researcher has published at least h papers that have each been cited at least h times.

You must write an algorithm that runs in logarithmic time.

Example 1:

Input: citations = [0,1,3,5,6]

Output: 3

Explanation: [0,1,3,5,6] means the researcher has 5 papers in total and each of them had received 0, 1, 3, 5, 6 citations respectively.

Since the researcher has 3 papers with at least 3 citations each and the remaining two with no more than 3 citations each, their h-index is 3.

Example 2:

Input: citations = [1,2,100]

Output: 2

Constraints:

n == citations.length

1 <= n <= 105

0 <= citations[i] <= 1000

citations is sorted in ascending order.

二、题解

cpp 复制代码
class Solution {
public:
    int hIndex(vector<int>& citations) {
        int n = citations.size();
        int left = 0, right = n - 1;
        while(left <= right){
            int mid = (left + right) >> 1;
            int ret = n - mid;
            if(citations[mid] >= ret) right = mid - 1;
            else if(citations[mid] < ret) left = mid + 1;
        }
        return n - left;
    }
};
相关推荐
玉树临风ives几秒前
atcoder ABC 453 题解
数据结构·c++·算法·图论·atcoder
小则又沐风a1 分钟前
STL库: string类
开发语言·c++
田梓燊6 分钟前
leetcode 48
算法·leetcode·职场和发展
mmz120710 分钟前
深度优先搜索DFS2(c++)
c++·算法·深度优先
6Hzlia10 分钟前
【Hot 100 刷题计划】 LeetCode 169. 多数元素 | C++ 哈希表基础解法
c++·leetcode·散列表
米粒112 分钟前
力扣算法刷题 Day 38 (打家劫舍专题)
算法·leetcode·职场和发展
暴力求解13 分钟前
C++ ---string类(三)
开发语言·c++
琪伦的工具库15 分钟前
批量PDF合并工具使用说明:批量合并与直接合并两种模式,拖拽排序/页面范围/遍历子目录/重名自动处理
数据结构·pdf·排序算法
Robot_Nav17 分钟前
RC-ESDF与Lazy Theta* 算法结合进行离线全局路径的生成
算法·全局规划·esdf
papership19 分钟前
【入门级-算法-7、搜索算法:深度优先搜索】
算法·深度优先