LeetCode每日一题——275. H-Index II

文章目录

一、题目

Given an array of integers citations where citations[i] is the number of citations a researcher received for their ith paper and citations is sorted in ascending order, return the researcher's h-index.

According to the definition of h-index on Wikipedia: The h-index is defined as the maximum value of h such that the given researcher has published at least h papers that have each been cited at least h times.

You must write an algorithm that runs in logarithmic time.

Example 1:

Input: citations = [0,1,3,5,6]

Output: 3

Explanation: [0,1,3,5,6] means the researcher has 5 papers in total and each of them had received 0, 1, 3, 5, 6 citations respectively.

Since the researcher has 3 papers with at least 3 citations each and the remaining two with no more than 3 citations each, their h-index is 3.

Example 2:

Input: citations = [1,2,100]

Output: 2

Constraints:

n == citations.length

1 <= n <= 105

0 <= citations[i] <= 1000

citations is sorted in ascending order.

二、题解

cpp 复制代码
class Solution {
public:
    int hIndex(vector<int>& citations) {
        int n = citations.size();
        int left = 0, right = n - 1;
        while(left <= right){
            int mid = (left + right) >> 1;
            int ret = n - mid;
            if(citations[mid] >= ret) right = mid - 1;
            else if(citations[mid] < ret) left = mid + 1;
        }
        return n - left;
    }
};
相关推荐
沐苏瑶5 小时前
Java 搜索型数据结构全解:二叉搜索树、Map/Set 体系与哈希表
java·数据结构·算法
ccLianLian5 小时前
深度学习·DDPM
数据结构
ZoeJoy86 小时前
算法筑基(二):搜索算法——从线性查找到图搜索,精准定位数据
算法·哈希算法·图搜索算法
Alicx.6 小时前
dfs由易到难
算法·蓝桥杯·宽度优先
桦06 小时前
【C++复习】:继承
开发语言·c++
_日拱一卒6 小时前
LeetCode:找到字符串中的所有字母异位词
算法·leetcode
鱼难终7 小时前
类和对象(下)
c++
云泽8087 小时前
深入 AVL 树:原理剖析、旋转算法与性能评估
数据结构·c++·算法
Wilber的技术分享8 小时前
【LeetCode高频手撕题 2】面试中常见的手撕算法题(小红书)
笔记·算法·leetcode·面试
邪神与厨二病8 小时前
Problem L. ZZUPC
c++·数学·算法·前缀和