桥和割点,以及图的遍历树

目录

什么是桥

寻找桥的算法

代码实现

什么是割点

​寻找割点的算法

代码实现


什么是桥

寻找桥的算法

代码实现

java 复制代码
import java.util.ArrayList;

public class FindBridges {

    private Graph G;
    private boolean[] visited;

    private int ord[];
    private int low[];
    private int cnt;

    private ArrayList<Edge> res;

    public FindBridges(Graph G){

        this.G = G;
        visited = new boolean[G.V()];

        res = new ArrayList<>();
        ord = new int[G.V()];
        low = new int[G.V()];
        cnt = 0;

        for(int v = 0; v < G.V(); v ++)
            if(!visited[v])
                dfs(v, v);
    }

    private void dfs(int v, int parent){

        visited[v] = true;
        ord[v] = cnt;
        low[v] = ord[v];
        cnt ++;

        for(int w: G.adj(v))
            if(!visited[w]){
                dfs(w, v);
                low[v] = Math.min(low[v], low[w]);
                if(low[w] > ord[v])
                    res.add(new Edge(v, w));
            }
            else if(w != parent)
                low[v] = Math.min(low[v], low[w]);
    }

    public ArrayList<Edge> result(){
        return res;
    }

    public static void main(String[] args){

        Graph g = new Graph("g.txt");
        FindBridges fb = new FindBridges(g);
        System.out.println("Bridges in g : " + fb.result());

        Graph g2 = new Graph("g2.txt");
        FindBridges fb2 = new FindBridges(g2);
        System.out.println("Bridges in g2 : " + fb2.result());

        Graph g3 = new Graph("g3.txt");
        FindBridges fb3 = new FindBridges(g3);
        System.out.println("Bridges in g3 : " + fb3.result());

        Graph tree = new Graph("tree.txt");
        FindBridges fb_tree = new FindBridges(tree);
        System.out.println("Bridges in tree : " + fb_tree.result());
    }
}

什么是割点

寻找割点的算法

孩子的数量是根据树来说的,而不是看根节点有多少个邻边,遍历树不同孩子数量也不同。

代码实现

java 复制代码
import java.util.HashSet;

public class FindCutPoints {

    private Graph G;
    private boolean[] visited;

    private int[] ord;
    private int[] low;
    private int cnt;

    private HashSet<Integer> res;

    public FindCutPoints(Graph G){

        this.G = G;
        visited = new boolean[G.V()];

        res = new HashSet<>();
        ord = new int[G.V()];
        low = new int[G.V()];
        cnt = 0;

        for(int v = 0; v < G.V(); v ++)
            if(!visited[v])
                dfs(v, v);
    }

    private void dfs(int v, int parent){

        visited[v] = true;
        ord[v] = cnt;
        low[v] = ord[v];
        cnt ++;

        int child = 0;

        for(int w: G.adj(v))
            if(!visited[w]){
                dfs(w, v);
                low[v] = Math.min(low[v], low[w]);

                if(v != parent && low[w] >= ord[v])
                    res.add(v);

                child ++;
                if(v == parent && child > 1)
                    res.add(v);
            }
            else if(w != parent)
                low[v] = Math.min(low[v], ord[w]);
    }

    public HashSet<Integer> result(){
        return res;
    }

    public static void main(String[] args){

        Graph g = new Graph("g.txt");
        FindCutPoints fc = new FindCutPoints(g);
        System.out.println("Cut Points in g : " + fc.result());

        Graph g2 = new Graph("g2.txt");
        FindCutPoints fc2 = new FindCutPoints(g2);
        System.out.println("Cut Points in g2 : " + fc2.result());

        Graph g3 = new Graph("g3.txt");
        FindCutPoints fc3 = new FindCutPoints(g3);
        System.out.println("Cut Points in g3 : " + fc3.result());

        Graph tree = new Graph("tree.txt");
        FindCutPoints fc4 = new FindCutPoints(tree);
        System.out.println("Cut Points in tree : " + fc4.result());

    }
}
相关推荐
地平线开发者5 小时前
J6B vio scenario sample
算法
Flittly13 小时前
【AgentScope Java新手村系列】(16)从RAG到多路检索
java·spring boot·spring
小兔崽子去哪了13 小时前
Java 生成二维码解决方案
java·后端
BothSavage17 小时前
Trae远程开发中DeepSeek自定义模型4054错误的排查与修复
算法
小林ixn17 小时前
从暴力到KMP:一道题彻底搞懂字符串匹配的前世今生
算法
人活一口气17 小时前
从JVM调优到MCP协议:Java全栈技术体系深度总结与企业级架构实践
java·spring boot
烬羽19 小时前
字符串算法入门:从反转字符串到回文判断,面试不再慌
算法·面试
NE_STOP19 小时前
Vibe Coding -- 完整项目案例实操
java
荣码19 小时前
GraphRAG:普通RAG只能回答"点"的问题,我踩了4个坑才搞懂
java·python