LeetCode93. Restore IP Addresses

文章目录

一、题目

A valid IP address consists of exactly four integers separated by single dots. Each integer is between 0 and 255 (inclusive) and cannot have leading zeros.

For example, "0.1.2.201" and "192.168.1.1" are valid IP addresses, but "0.011.255.245", "192.168.1.312" and "192.168@1.1" are invalid IP addresses.

Given a string s containing only digits, return all possible valid IP addresses that can be formed by inserting dots into s. You are not allowed to reorder or remove any digits in s. You may return the valid IP addresses in any order.

Example 1:

Input: s = "25525511135"

Output: "255.255.11.135","255.255.111.35"

Example 2:

Input: s = "0000"

Output: "0.0.0.0"

Example 3:

Input: s = "101023"

Output: "1.0.10.23","1.0.102.3","10.1.0.23","10.10.2.3","101.0.2.3"

Constraints:

1 <= s.length <= 20

s consists of digits only.

二、题解

注意c++中字符串的insert方法和erase方法

cpp 复制代码
class Solution {
public:
    vector<string> res;
    bool isValid(string& s,int start,int end){
        if(start > end) return false;
        if(s[start] == '0' && start != end) return false;
        int num = 0;
        for(int i = start;i <= end;i++){
            if(s[i] < '0' || s[i] > '9') return false;
            num = num * 10 + s[i] - '0';
            if(num > 255) return false;
        }
        return true;
    }
    void backtracking(string s,int startIndex,int pointSum){
        if(pointSum == 3){
            if(isValid(s,startIndex,s.size()-1)){
                res.push_back(s);
                return;
            }
        }
        for(int i = startIndex;i < s.size();i++){
            //合法的情况下
            if(isValid(s,startIndex,i)){
                s.insert(s.begin() + i + 1,'.');
                pointSum++;
                backtracking(s,i + 2,pointSum);
                s.erase(s.begin() + i + 1);
                pointSum--;
            }
            else break;
        }
    }
    vector<string> restoreIpAddresses(string s) {
        backtracking(s,0,0);
        return res;
    }
};
相关推荐
Cx330_FCQ2 小时前
Tmux使用
服务器·git·算法
拳里剑气3 小时前
C++算法:多源BFS
c++·算法·宽度优先·多源bfs
ysa0510304 小时前
【板子】短序列dp(换成维护更小常数维度的dp)
c++·笔记·算法·板子
shwill1234 小时前
PID 算法(三)--- 增量 PID ↔ 单神经元 PID 等价映射
linux·算法
wabs6665 小时前
关于图论【卡码网110.字符串迁移的思考】
数据结构·算法·图论
hanlin035 小时前
刷题笔记:力扣第242、349题(哈希表)
笔记·算法·leetcode
aramae6 小时前
C++ IO流完全指南:从C标准库到C++流式编程
服务器·c语言·开发语言·c++·后端
_wyt0016 小时前
c++里的族谱:树
c++·
浮沉9876 小时前
二分查找算法例题(二)
算法
only-qi7 小时前
大模型Agent面试攻略:落地工程痛点、评估体系与Agentic RAG核心精讲
人工智能·算法·面试·职场和发展·langchain·rag