LeetCode93. Restore IP Addresses

文章目录

一、题目

A valid IP address consists of exactly four integers separated by single dots. Each integer is between 0 and 255 (inclusive) and cannot have leading zeros.

For example, "0.1.2.201" and "192.168.1.1" are valid IP addresses, but "0.011.255.245", "192.168.1.312" and "192.168@1.1" are invalid IP addresses.

Given a string s containing only digits, return all possible valid IP addresses that can be formed by inserting dots into s. You are not allowed to reorder or remove any digits in s. You may return the valid IP addresses in any order.

Example 1:

Input: s = "25525511135"

Output: "255.255.11.135","255.255.111.35"

Example 2:

Input: s = "0000"

Output: "0.0.0.0"

Example 3:

Input: s = "101023"

Output: "1.0.10.23","1.0.102.3","10.1.0.23","10.10.2.3","101.0.2.3"

Constraints:

1 <= s.length <= 20

s consists of digits only.

二、题解

注意c++中字符串的insert方法和erase方法

cpp 复制代码
class Solution {
public:
    vector<string> res;
    bool isValid(string& s,int start,int end){
        if(start > end) return false;
        if(s[start] == '0' && start != end) return false;
        int num = 0;
        for(int i = start;i <= end;i++){
            if(s[i] < '0' || s[i] > '9') return false;
            num = num * 10 + s[i] - '0';
            if(num > 255) return false;
        }
        return true;
    }
    void backtracking(string s,int startIndex,int pointSum){
        if(pointSum == 3){
            if(isValid(s,startIndex,s.size()-1)){
                res.push_back(s);
                return;
            }
        }
        for(int i = startIndex;i < s.size();i++){
            //合法的情况下
            if(isValid(s,startIndex,i)){
                s.insert(s.begin() + i + 1,'.');
                pointSum++;
                backtracking(s,i + 2,pointSum);
                s.erase(s.begin() + i + 1);
                pointSum--;
            }
            else break;
        }
    }
    vector<string> restoreIpAddresses(string s) {
        backtracking(s,0,0);
        return res;
    }
};
相关推荐
程序猿阿森17 分钟前
深入解析 NLI:RAG 与大模型防幻觉的“最后一道防线”
前端·人工智能·算法
General_G1 小时前
创建型模式—原型(Prototype)模式
c++·设计模式·原型模式
syagain_zsx1 小时前
protobuf 实战:从 .proto 到 C++ 序列化的完整链路
c++·学习·程序人生·谷歌·protobuf
而后笑面对1 小时前
浅尝贝叶斯估计
人工智能·算法·机器学习
welfare9622 小时前
新号别搞:C++_list
开发语言·c++
xiaoye-duck2 小时前
《C++ 项目:手写大模型接入 SDK》云端 API 调用基础与 Apifox 调试实战
网络·c++·语言模型
坤坤子吖2 小时前
Linux 线程同步与互斥——条件变量与线程同步
linux·开发语言·c++·笔记·学习
杜 硕2 小时前
从零开始的C++生活——第二讲——03
c++·生活
u0111026752 小时前
图片生成任务的日志记录与敏感信息取舍
前端·图像处理·算法·ai作画
花间相见3 小时前
【计算基础|MySQL08】索引(上):为什么是 B+ 树
数据结构·mysql·算法·架构