LeetCode93. Restore IP Addresses

文章目录

一、题目

A valid IP address consists of exactly four integers separated by single dots. Each integer is between 0 and 255 (inclusive) and cannot have leading zeros.

For example, "0.1.2.201" and "192.168.1.1" are valid IP addresses, but "0.011.255.245", "192.168.1.312" and "[email protected]" are invalid IP addresses.

Given a string s containing only digits, return all possible valid IP addresses that can be formed by inserting dots into s. You are not allowed to reorder or remove any digits in s. You may return the valid IP addresses in any order.

Example 1:

Input: s = "25525511135"

Output: ["255.255.11.135","255.255.111.35"]

Example 2:

Input: s = "0000"

Output: ["0.0.0.0"]

Example 3:

Input: s = "101023"

Output: ["1.0.10.23","1.0.102.3","10.1.0.23","10.10.2.3","101.0.2.3"]

Constraints:

1 <= s.length <= 20

s consists of digits only.

二、题解

注意c++中字符串的insert方法和erase方法

cpp 复制代码
class Solution {
public:
    vector<string> res;
    bool isValid(string& s,int start,int end){
        if(start > end) return false;
        if(s[start] == '0' && start != end) return false;
        int num = 0;
        for(int i = start;i <= end;i++){
            if(s[i] < '0' || s[i] > '9') return false;
            num = num * 10 + s[i] - '0';
            if(num > 255) return false;
        }
        return true;
    }
    void backtracking(string s,int startIndex,int pointSum){
        if(pointSum == 3){
            if(isValid(s,startIndex,s.size()-1)){
                res.push_back(s);
                return;
            }
        }
        for(int i = startIndex;i < s.size();i++){
            //合法的情况下
            if(isValid(s,startIndex,i)){
                s.insert(s.begin() + i + 1,'.');
                pointSum++;
                backtracking(s,i + 2,pointSum);
                s.erase(s.begin() + i + 1);
                pointSum--;
            }
            else break;
        }
    }
    vector<string> restoreIpAddresses(string s) {
        backtracking(s,0,0);
        return res;
    }
};
相关推荐
px不是xp2 分钟前
山东大学算法设计与分析复习笔记
笔记·算法·贪心算法·动态规划·图搜索算法
-qOVOp-25 分钟前
408第一季 - 数据结构 - 栈与队列的应用
数据结构
终焉代码25 分钟前
STL解析——list的使用
开发语言·c++
DevangLic40 分钟前
【 *p取出内容 &a得到地址】
c++
枫景Maple1 小时前
LeetCode 2297. 跳跃游戏 VIII(中等)
算法·leetcode
鑫鑫向栄1 小时前
[蓝桥杯]修改数组
数据结构·c++·算法·蓝桥杯·动态规划
鑫鑫向栄1 小时前
[蓝桥杯]带分数
数据结构·c++·算法·职场和发展·蓝桥杯
m0_552200822 小时前
《UE5_C++多人TPS完整教程》学习笔记37 ——《P38 变量复制(Variable Replication)》
c++·游戏·ue5
小wanga2 小时前
【递归、搜索与回溯】专题三 穷举vs暴搜vs回溯vs剪枝
c++·算法·机器学习·剪枝