Day62.算法训练

最爱大白菜x2023-12-02 9:12

718. 最长重复子数组

java 复制代码

class Solution {
    public int findLength(int[] nums1, int[] nums2) {
            int max = 0;
            int[][] dp = new int[nums1.length][nums2.length];
            for (int i = 0; i < nums1.length; i++) {
                for (int j = 0; j < nums2.length; j++) {
                    if (nums1[i] == nums2[j]) {
                        if (i == 0 || j == 0) {
                            dp[i][j] = 1;
                        } else {
                            dp[i][j] = dp[i - 1][j - 1] + 1;
                        }

                        if (dp[i][j] > max) {
                            max = dp[i][j];
                        }
                    }
                }
            }
            // for (int[] ints : dp) {
                // System.out.println(Arrays.toString(ints));
            // }
            return max;
        }
}

300. 最长递增子序列

java 复制代码

class Solution {
    public int lengthOfLIS(int[] nums) {
        int[] dp = new int[nums.length];
        Arrays.fill(dp, 1);
        int max = 1;
        for (int i = 1; i < nums.length; i++) {
            for (int j = 0; j < i; j++) {
                if (nums[i] > nums[j]) {
                    dp[i] = Integer.max(dp[i], dp[j] + 1);
                    if (dp[i] > max) {
                        max = dp[i];
                    }
                }
            }
        }
        return max;
    }
}

674. 最长连续递增序列

java 复制代码

class Solution {
    public int findLengthOfLCIS(int[] nums) {
        int[] dp = new int[nums.length];
        Arrays.fill(dp, 1);
        int max = 1;
        for (int i = 1; i < nums.length; i++) {
            if (nums[i - 1] < nums[i]) {
                dp[i] = dp[i - 1] + 1;
                if (dp[i] > max) {
                    max = dp[i];
                }
            }
        }
        // System.out.println(Arrays.toString(dp));
        return max;
    }
}

1143. 最长公共子序列

java 复制代码

class Solution {
    public int longestCommonSubsequence(String text1, String text2) {
        int[][] dp = new int[text1.length() + 1][text2.length() + 1];

        char[] chars1 = text1.toCharArray();
        char[] chars2 = text2.toCharArray();

        for (int i = 1; i < chars1.length + 1; i++) {
            for (int j = 1; j < chars2.length + 1; j++) {
                if (chars1[i - 1] == chars2[j - 1]) {
                    dp[i][j] = dp[i - 1][j - 1] + 1;
                } else {
                    dp[i][j] = Integer.max(dp[i - 1][j], dp[i][j - 1]);
                }
            }
        }
        return dp[chars1.length][chars2.length];
    }
}