第3章 网页数据的解析提取

His Last Bow2023-12-05 15:34

目录

1. XPath 的使用

  • XPath（XML Path Language）
    • XML 路径语言
    • 用于在 XML 文档中查找信息
      • html 文档也适用

1.1 XPath 常用规则

表达式 描述
nodename 选取此节点的所有子节点
/ 从当前节点选取直接子节点
// 从当前节点选取子孙节点
. 选取当前节点
... 选取当前节点的父节点
@ 选取属性
  • 示例
python 复制代码 
//title[@lang="eng"]

1.2 安装

python 复制代码 
pip3 install lxml

1.3 实例引入

python 复制代码 
from lxml import etree

text = """
<div>
    <ul>
        <li class="item-0"><a href="link1.html">first item</a></li>
        <li class="item-1"><a href="link2.html">second item</a></li>
        <li class="item-inactive"><a href="link3.html">third item</a></li>
        <li class="item-1"><a href="link4.html">fourth item</a></li>
        <li class="item-0"><a href="link5.html">fifth item</a>
    </ul>
</div>
"""

html = etree.HTML(text)
result = etree.tostring(html)
print(result.decode('utf-8'))

  • etree 模块可以自动修正 HTML 文本

  • 直接读取文本

    • test.html

      html 复制代码 
      <div>
    <ul>
        <li class="item-0"><a href="link1.html">first item</a></li>
        <li class="item-1"><a href="link2.html">second item</a></li>
        <li class="item-inactive"><a href="link3.html">third item</a></li>
        <li class="item-1"><a href="link4.html">fourth item</a></li>
        <li class="item-0"><a href="link5.html">fifth item</a>
    </ul>
</div>

    • test.py

      python 复制代码 
      from lxml import etree

html = etree.parse("./test.html", etree.HTMLParser())
result = etree.tostring(html)
print(result.decode('utf-8'))

1.4 所有节点

  • 获取所有节点（//*）
python 复制代码 
from lxml import etree

html = etree.parse("./test.html", etree.HTMLParser())
result = html.xpath("//*")
print(result)
  • 获取所有 li 节点（//li）
python 复制代码 
from lxml import etree

html = etree.parse("./test.html", etree.HTMLParser())
result = html.xpath("//li")
print(result)
  • 使用 // + name 来获取所有名称为 name 的节点

1.5 子节点

  • 获取 li 节点的直接子节点 a
python 复制代码 
from lxml import etree

html = etree.parse("./test.html", etree.HTMLParser())
result = html.xpath("//li/a")
print(result)
  • 获取 ul 节点的子孙节点 a
python 复制代码 
from lxml import etree

html = etree.parse("./test.html", etree.HTMLParser())
result = html.xpath("//ul//a")
print(result)

1.6 父节点

  • 获取 href 属性为 link4.html 的 a 节点，然后获取其父节点，再获取父节点的 class 属性
python 复制代码 
from lxml import etree

html = etree.parse("./test.html", etree.HTMLParser())
result = html.xpath("//a[@href=\"link4.html\"]/../@class")
print(result)
  • 通过 parent:: 获取父节点
python 复制代码 
from lxml import etree

html = etree.parse("./test.html", etree.HTMLParser())
result = html.xpath("//a[@href=\"link4.html\"]/parent::*/@class")
print(result)

1.7 属性匹配

  • 使用 @ 过滤
python 复制代码 
from lxml import etree

html = etree.parse("./test.html", etree.HTMLParser())
result = html.xpath("//li[@class=\"item-0\"]")
print(result)

1.8 文本获取

  • 获取 class 属性为 item-0 的 li 节点，并获取其直接子节点的文本
python 复制代码 
from lxml import etree

html = etree.parse("./test.html", etree.HTMLParser())
result = html.xpath("//li[@class=\"item-0\"]/text()")
print(result)

  • 获取 class 属性为 item-0 的 li 节点，并获取其内部的文本

    • 先选取 a 节点再获取文本

      python 复制代码 
      from lxml import etree

html = etree.parse("./test.html", etree.HTMLParser())
result = html.xpath("//li[@class=\"item-0\"]/a/text()")
print(result)

    • 使用 //

      python 复制代码 
      from lxml import etree

html = etree.parse("./test.html", etree.HTMLParser())
result = html.xpath("//li[@class=\"item-0\"]//text()")
print(result)

  • 获取子孙节点下的所有文本：//

  • 获取特定子孙节点下的所有文本：/特定节点/

1.9 属性获取

python 复制代码 
from lxml import etree

html = etree.parse("./test.html", etree.HTMLParser())
result = html.xpath("//li/a/@href")
print(result)

1.10 属性多值匹配

  • li 属性有两个值
    • li
    • li-first
  • 使用之前的属性匹配将无法获取
python 复制代码 
from lxml import etree

text = """
<li class="li li-first"><a href="link.html">first item</a></li>
"""
html = etree.HTML(text)
result = html.xpath("//li[@class=\"li\"]/a/text()")
print(result)
  • 使用 contains 进行属性的多值匹配
python 复制代码 
from lxml import etree

text = """
<li class="li li-first"><a href="link.html">first item</a></li>
"""
html = etree.HTML(text)
result = html.xpath("//li[contains(@class, \"li\")]/a/text()")
print(result)

1.11 多属性匹配

python 复制代码 
from lxml import etree

text = """
<li class="li li-first" name="item"><a href="link.html">first item</a></li>
"""
html = etree.HTML(text)
result = html.xpath(
    "//li[contains(@class, \"li\") and @name=\"item\"]/a/text()")
print(result)
  • 运算符
运算符 描述
or 或
and 与
mod 求余
| 求两个节点集
+ 加
- 减
* 乘
div 除
= 等于
!= 不等于
< 小于
<= 小于等于
> 大于
>= 大于等于

1.12 按序选择

python 复制代码 
from lxml import etree

html = etree.parse("./test.html", etree.HTMLParser())

# 选取第一个节点
result = html.xpath("//li[1]/a/text()")
print(result)

# 选取最后一个节点
result = html.xpath("//li[last()]/a/text()")
print(result)

# 获取限定位置的节点
result = html.xpath("//li[position() < 3]/a/text()")
print(result)

# 获取倒数第三个节点
result = html.xpath("//li[last() - 2]/a/text()")
print(result)

1.13 节点轴选择

python 复制代码 
from lxml import etree

html = etree.parse("./test.html", etree.HTMLParser())

# ancestor轴: 获取所有祖先节点
result = html.xpath("//li[1]/ancestor::*")
print(result)
result = html.xpath("//li[1]/ancestor::div")
print(result)

# attribute轴: 获取所有属性值
result = html.xpath("//li[1]/attribute::*")
print(result)

# child轴: 获取所有直接子节点
result = html.xpath("//li[1]/child::a[@href=\"link1.html\"]")
print(result)

# descendant轴: 获取所有子孙节点
result = html.xpath("//li[1]/descendant::span")
print(result)

# following轴: 获取当前节点之后的所有节点
result = html.xpath("//li[1]/following::*[2]")
print(result)

# following-sibling轴: 获取当前节点之后的所有同级节点
result = html.xpath("//li[1]/following-sibling::*")
print(result)

2. Beautiful Soup 的使用

  • 借助网页的结构和属性等特性来解析网页

2.1 解析器

  • Beautiful Soup 在解析时是依赖解析器的
  • Beautiful Soup 支持的解析器
解析器 使用方法 优势 劣势
Python 标准库 BeautifulSoup(markup, "html.parser") Python 的内置标准库、执行速度适中、文档容错能力强 Python 2.7.3 或 Python 3.2.2 前的版本中文容错能力差
LXML HTML 解析器 BeautifulSoup(markup, "lxml") 速度快、文档容错能力强 需要安装 C 语言库
LXML XML 解析器 BeautifulSoup(markup, "xml") 速度快、唯一支持 XML 的解析器 需要安装 C 语言库
html5lib BeautifulSoup(markup, "html5lib") 提供最好的容错性、以浏览器的方式解析文档、生成HTML5格式的文档 速度慢、不依赖外部扩展

2.2 安装

python 复制代码 
pip3 install beautifulsoup4
pip3 install lxml

2.3 基本使用

python 复制代码 
from bs4 import BeautifulSoup

html = """
<html>
    <head>
        <title>Test</title>
    </head>
    <body>
        <p class="title" name="name"><b>Test</b></p>
        <p class="story">A B C
        <a href="http://example.com/A" class="abc" id="link1"><!--A--></a>,
        <a href="http://example.com/B" class="abc" id="link2">B</a> and
        <a href="http://example.com/C" class="abc" id="link3">C </a>;
        </p>
        <p class="story">···</p>
"""

soup = BeautifulSoup(html, "lxml")

# 以标准的缩进格式输出
print(soup.prettify())
print(soup.title.string)
  • Beautiful Soup 在初始化时会自动修正格式

2.4 节点选择器

python 复制代码 
from bs4 import BeautifulSoup

html = """
<html>
    <head><title>Test</title></head>
    <body>
        <p class="title" name="name"><b>Test</b></p>
        <p class="story">A B C
        <a href="http://example.com/A" class="abc" id="link1"><!--A--></a>,
        <a href="http://example.com/B" class="abc" id="link2">B</a> and
        <a href="http://example.com/C" class="abc" id="link3">C </a>;
        </p>
        <p class="story">···</p>
"""

soup = BeautifulSoup(html, "lxml")

print(soup.title)
print(type(soup.title))
print(soup.title.string)
print(soup.head)
print(soup.p)
  • 此种选择方式只能选择到第一个匹配的节点，后面的其他节点都会忽略

2.5 提取信息

获取节点名称（name）

python 复制代码 
print(soup.title.name)

获取属性（attrs）

python 复制代码 
print(soup.p.attrs)
print(soup.p.attrs["name"])

获取内容（string）

python 复制代码 
print(soup.p.string)

嵌套选择

python 复制代码 
print(soup.head.title)
print(soup.head.title.string)

2.6 关联选择

子节点和子孙节点

  • 直接子节点

    • contents

      python 复制代码 
      from bs4 import BeautifulSoup

html = """
<html>
    <head><title>Test</title></head>
    <body>
        <p class="story">A B C
        <a href="http://example.com/A" class="abc" id="link1"><span>A</span></a>,
        <a href="http://example.com/B" class="abc" id="link2">B</a> and
        <a href="http://example.com/C" class="abc" id="link3">C </a>;
        </p>
        <p class="story">···</p>
"""

soup = BeautifulSoup(html, "lxml")

print(soup.p.contents)

    • children

      python 复制代码 
      from bs4 import BeautifulSoup

soup = BeautifulSoup(html, "lxml")

print(soup.p.children)
for i, child in enumerate(soup.p.children):
    print(i, child)

  • 子孙节点（descendants）

python 复制代码 
from bs4 import BeautifulSoup

soup = BeautifulSoup(html, "lxml")

print(soup.p.descendants)
for i, child in enumerate(soup.p.descendants):
    print(i, child)

父节点和祖先节点

  • 父节点（parent）
python 复制代码 
from bs4 import BeautifulSoup

html = """
<html>
    <body>
    	<p class="story">
        <a href="http://example.com/A" class="abc" id="link1"><span>A</span></a>,
        <a href="http://example.com/B" class="abc" id="link2">B</a> and
        <a href="http://example.com/C" class="abc" id="link3">C </a>;
        </p>
"""

soup = BeautifulSoup(html, "lxml")

print(soup.a.parent)
  • 祖先节点（parents）
python 复制代码 
from bs4 import BeautifulSoup

html = """
<html>
    <body>
    	<p class="story">
        <a href="http://example.com/A" class="abc" id="link1"><span>A</span></a>,
        <a href="http://example.com/B" class="abc" id="link2">B</a> and
        <a href="http://example.com/C" class="abc" id="link3">C </a>;
        </p>
"""

soup = BeautifulSoup(html, "lxml")

print(type(soup.a.parents))
print(list(enumerate(soup.a.parents)))

兄弟节点

python 复制代码 
from bs4 import BeautifulSoup

html = """
<html>
    <body>
    	<p class="story">
        Test
        <a href="http://example.com/A" class="abc" id="link1"><span>A</span></a>
        ABC
        <a href="http://example.com/B" class="abc" id="link2">B</a>
        abc
        <a href="http://example.com/C" class="abc" id="link3">C </a>
        123
        </p>
"""

soup = BeautifulSoup(html, "lxml")

print("next sibling", soup.a.next_sibling)
print("prev sibling", soup.a.previous_sibling)
print("next siblings", list(enumerate(soup.a.next_siblings)))
print("prev siblings", list(enumerate(soup.a.previous_siblings)))

提取信息

python 复制代码 
from bs4 import BeautifulSoup

html = """
<html>
    <body>
        <p class="story">
        Test
        <a href="http://example.com/A" class="abc" id="link1"><span>A</span></a><a href="http://example.com/B" class="abc" id="link2">B</a><a href="http://example.com/C" class="abc" id="link3">C </a>
        </p>
"""

soup = BeautifulSoup(html, "lxml")

print(soup.a.next_sibling)
print(soup.a.next_sibling.string)
print(soup.a.parents)
print(list(soup.a.parents)[0])
print(list(soup.a.parents)[0].attrs["class"])

2.7 方法选择器

find_all

python 复制代码 
findall(name, attrs, recursive, text, **kwargs)

name

python 复制代码 
from bs4 import BeautifulSoup

html = """
<div class="panel">
    <div class="panel-heading">
        <h4>
            Hello
        </h4>
    </div>
    <div class="panel-body">
        <ul class="list" id="list-1">
            <li class="element">A</li>
            <li class="element">B</li>
            <li class="element">C</li>
        </ul>
        <ul class="list list-small" id="list-2">
            <li class="element">a</li>
            <li class="element">b</li>
            <li class="element">c</li>
        </ul>
    </div>
</div>
"""

soup = BeautifulSoup(html, "lxml")

print(soup.find_all(name="ul"))
print(type(soup.find_all(name="ul")[0]))
for ul in soup.find_all(name="ul"):
    print(ul.find_all(name="li"))
    for li in ul.find_all(name="li"):
        print(li.string)

attrs

python 复制代码 
from bs4 import BeautifulSoup

html = """
<div class="panel">
    <div class="panel-heading">
        <h4>
            Hello
        </h4>
    </div>
    <div class="panel-body">
        <ul class="list" id="list-1">
            <li class="element">A</li>
            <li class="element">B</li>
            <li class="element">C</li>
        </ul>
        <ul class="list list-small" id="list-2">
            <li class="element">a</li>
            <li class="element">b</li>
            <li class="element">c</li>
        </ul>
    </div>
</div>
"""

soup = BeautifulSoup(html, "lxml")

print(soup.find_all(attrs={"id": "list-1"}))
print(soup.find_all(attrs={"class": "element"}))
# 等效于
print(soup.find_all(id="list-1"))
print(soup.find_all(class_="element"))

text

  • 该参数应为正则表达式对象
  • 返回结果是由所有与该正则表达式相匹配的节点文本组成的列表
python 复制代码 
import re
from bs4 import BeautifulSoup

html = """
<div class="panel">
    <div class="panel-body">
        <a>link1</a>
        <a>link2</a>
    </div>
</div>
"""

soup = BeautifulSoup(html, "lxml")

print(soup.find_all(text=re.compile("link")))

find

  • 只能获取第一个匹配的节点元素
python 复制代码 
from bs4 import BeautifulSoup

html = """
<div class="panel">
    <div class="panel-heading">
        <h4>
            Hello
        </h4>
    </div>
    <div class="panel-body">
        <ul class="list" id="list-1">
            <li class="element">A</li>
            <li class="element">B</li>
            <li class="element">C</li>
        </ul>
        <ul class="list list-small" id="list-2">
            <li class="element">a</li>
            <li class="element">b</li>
            <li class="element">c</li>
        </ul>
    </div>
</div>
"""

soup = BeautifulSoup(html, "lxml")

print(soup.find(name="ul"))
print(type(soup.find(name="ul")))
print(soup.find(class_="list"))

find_parents

  • 获取所有的祖先节点

find_parent

  • 获取直接父节点

find_next_siblings

  • 获取后面的所有兄弟节点

find_next_sibling

  • 获取后面的第一个兄弟节点

find_previous_siblings

  • 获取前面的所有兄弟节点

find_previous_sibling

  • 获取前面第一个兄弟节点

find_all_next

  • 获取节点后面所有符合条件的节点

find_next

  • 获取节点后面第一个符合条件的节点

find_all_previous

  • 获取节点前面所有符合条件的节点

find_previous

  • 获取节点前面第一个符合条件的节点

2.8 CSS 选择器

实例

  • select(节点1，节点2，节点3 ···)
    • 获取所有 节点1 下的所有 节点2 下的所有 节点3 ···
  • 节点可以换为
    • .class名
    • #id名
python 复制代码 
from bs4 import BeautifulSoup

html = """
<div class="panel">
    <div class="panel-heading">
        <h4>Hello</h4>
    </div>
    <div class="panel-body">
        <ul class="list" id="list-1">
            <li class="element">A</li>
            <li class="element">B</li>
            <li class="element">C</li>
        </ul>
        <ul class="list list-small" id="list-2">
            <li class="element">a</li>
            <li class="element">b</li>
            <li class="element">c</li>
        </ul>
    </div>
</div>
"""

soup = BeautifulSoup(html, "lxml")

print(soup.select(".panel .panel-body .list"))
print(soup.select("ul li"))
print(soup.select("#list-2 .element"))
print(type(soup.select("ul")[0]))

嵌套选择

python 复制代码 
soup = BeautifulSoup(html, "lxml")

for ul in soup.select("ul"):
    print(ul.select("li"))

获取属性

  • 方括号获取
  • .attrs[]
python 复制代码 
soup = BeautifulSoup(html, "lxml")

for ul in soup.select("ul"):
    print(ul["id"])
    # 等效于
    print(ul.attrs["id"])

获取文本

  • .get_text()
  • .string
python 复制代码 
soup = BeautifulSoup(html, "lxml")

for li in soup.select("li"):
    print(f"text: {li.get_text()}")
    # 等效于
    print(f"string: {li.string}")

3. pyquery 的使用

3.1 安装

python 复制代码 
pip3 install pyquery

3.2 初始化

字符串初始化

python 复制代码 
from pyquery import PyQuery

html = """
<div>
    <ul>
        <li class="item-0">first item</li>
        <li class="item-1"><a href="link2.html">second item</a></li>
        <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
        <li class="item-1 active"><a href="link4.html">fourth item</a></li>
        <li class="item-0"><a href="link5.html">fifth item</a></li>
    </ul>
</div>
"""

doc = PyQuery(html)
print(doc("li"))

URL初始化

python 复制代码 
from pyquery import PyQuery

doc = PyQuery(url="https://www.bilibili.com/")
# 等效于
doc = PyQuery(requests.get(url).text)
print(doc("title"))

文件初始化

python 复制代码 
from pyquery import PyQuery

doc = PyQuery(filename="test.html")
print(doc("li"))

3.3 基本CSS选择器

python 复制代码 
from pyquery import PyQuery

html = """
<div id="container">
    <ul class="list">
        <li class="item-0">first item</li>
        <li class="item-1"><a href="link2.html">second item</a></li>
        <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
        <li class="item-1 active"><a href="link4.html">fourth item</a></li>
        <li class="item-0"><a href="link5.html">fifth item</a></li>
    </ul>
</div>
"""

doc = PyQuery(html)

print(doc("#container .list li"))
print(type(doc("#container .list li")))

for item in doc("#container .list li").items():
    print(item.text())

3.4 查找节点

直接子节点

python 复制代码 
from pyquery import PyQuery

doc = PyQuery(html)
items = doc(".list")
lis = items.children()

print(type(lis))
print(lis)

子孙节点

python 复制代码 
from pyquery import PyQuery

doc = PyQuery(html)

items = doc(".list")
print(type(items))
print(items)

lis = items.find("li")
print(type(lis))
print(lis)

直接父节点

python 复制代码 
from pyquery import PyQuery

html = """
<div class="wrap">
    <div id="container">
        <ul class="list">
            <li class="item-0">first item</li>
            <li class="item-1"><a href="link2.html">second item</a></li>
            <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
            <li class="item-1 active"><a href="link4.html">fourth item</a></li>
            <li class="item-0"><a href="link5.html">fifth item</a></li>
        </ul>
    </div>
</div>
"""

doc = PyQuery(html)
items = doc(".list")
container = items.parent()

print(type(container))
print(container)

祖先节点

python 复制代码 
from pyquery import PyQuery

html = """
<div class="wrap">
    <div id="container">
        <ul class="list">
            <li class="item-0">first item</li>
            <li class="item-1"><a href="link2.html">second item</a></li>
            <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
            <li class="item-1 active"><a href="link4.html">fourth item</a></li>
            <li class="item-0"><a href="link5.html">fifth item</a></li>
        </ul>
    </div>
</div>
"""

doc = PyQuery(html)
items = doc(".list")
parents = items.parents()

print(type(parents))
print(parents)

兄弟节点（有问题）

  • 输出优先级
python 复制代码 
from pyquery import PyQuery

html = """
<div class="wrap">
    <div id="container">
        <ul class="list">
            <li class="item-0">first item</li>
            <li class="item-1"><a href="link2.html">second item</a></li>
            <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
            <li class="item-1 active"><a href="link4.html">fourth item</a></li>
            <li class="item-0"><a href="link5.html">fifth item</a></li>
        </ul>
    </div>
</div>
"""

doc = PyQuery(html)
lis = doc(".list .item-0.active")

for item in lis.siblings().items():
    print(item.text())

3.5 遍历节点

获取单个节点

python 复制代码 
from pyquery import PyQuery

html = """
<div class="wrap">
    <div id="container">
        <ul class="list">
            <li class="item-0">first item</li>
            <li class="item-1"><a href="link2.html">second item</a></li>
            <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
            <li class="item-1 active"><a href="link4.html">fourth item</a></li>
            <li class="item-0"><a href="link5.html">fifth item</a></li>
        </ul>
    </div>
</div>
"""

doc = PyQuery(html)
li = doc(".item-0.active")

print(li)
print(str(li))

获取多个节点

python 复制代码 
from pyquery import PyQuery

html = """
<div class="wrap">
    <div id="container">
        <ul class="list">
            <li class="item-0">first item</li>
            <li class="item-1"><a href="link2.html">second item</a></li>
            <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
            <li class="item-1 active"><a href="link4.html">fourth item</a></li>
            <li class="item-0"><a href="link5.html">fifth item</a></li>
        </ul>
    </div>
</div>
"""

doc = PyQuery(html)
lis = doc("li").items()

print(type(lis))

for li in lis:
    print(li, type(li))

获取信息

  • 信息
    • 属性
    • 文本

获取属性（attr()）

python 复制代码 
from pyquery import PyQuery

html = """
<div class="wrap">
    <div id="container">
        <ul class="list">
            <li class="item-0">first item</li>
            <li class="item-1"><a href="link2.html">second item</a></li>
            <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
            <li class="item-1 active"><a href="link4.html">fourth item</a></li>
            <li class="item-0"><a href="link5.html">fifth item</a></li>
        </ul>
    </div>
</div>
"""

doc = PyQuery(html)
a = doc(".item-0.active a")

print(a, type(a))
print(a.attr("href"))
# 等效于
print(a.attr.href)

a = doc("a")

print(a, type(a))
print(a.attr("href"))
for item in a.items():
    print(item.attr("href"))

获取文本

获取内部文本（.text()）
  • 贪婪
  • 如果拥有多个文本内容均会输出，且以空格分隔
python 复制代码 
from pyquery import PyQuery

html = """
<div class="wrap">
    <div id="container">
        <ul class="list">
            <li class="item-0">first item</li>
            <li class="item-1"><a href="link2.html">second item</a></li>
            <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
            <li class="item-1 active"><a href="link4.html">fourth item</a></li>
            <li class="item-0"><a href="link5.html">fifth item</a></li>
        </ul>
    </div>
</div>
"""

doc = PyQuery(html)
a = doc(".item-0.active a")

print(a)
print(a.text())
获取内部的HTML文本（.html()）
  • 非贪婪
  • 只会输出第一个匹配的文本
python 复制代码 
from pyquery import PyQuery

html = """
<div class="wrap">
    <div id="container">
        <ul class="list">
            <li class="item-0">first item</li>
            <li class="item-1"><a href="link2.html">second item</a></li>
            <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
            <li class="item-1 active"><a href="link4.html">fourth item</a></li>
            <li class="item-0"><a href="link5.html">fifth item</a></li>
        </ul>
    </div>
</div>
"""

doc = PyQuery(html)
li = doc(".item-0.active")

print(li)
print(li.html())
.html()的相关误区
python 复制代码 
from pyquery import PyQuery

html = """
<div class="wrap">
    <div id="container">
        <ul class="list">
            <li class="item-0">first item</li>
            <li class="item-1"><a href="link2.html">second item</a></li>
            <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
            <li class="item-1 active"><a href="link4.html">fourth item</a></li>
            <li class="item-0"><a href="link5.html">fifth item</a></li>
        </ul>
    </div>
</div>
"""

doc = PyQuery(html)
li = doc(".item-0.active")
a = doc(".item-0.active a")

# 输出内容相同，但内容并不相等
print(li.html())
print(a)

# 类型为str
print(type(li.html()))

# 类型为pyquery.pyquery.PyQuery
print(type(a))

3.6 节点操作

addClass和removeClass

  • 动态改变节点的Class属性
python 复制代码 
from pyquery import PyQuery

html = """
<div class="wrap">
    <div id="container">
        <ul class="list">
            <li class="item-0">first item</li>
            <li class="item-1"><a href="link2.html">second item</a></li>
            <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
            <li class="item-1 active"><a href="link4.html">fourth item</a></li>
            <li class="item-0"><a href="link5.html">fifth item</a></li>
        </ul>
    </div>
</div>
"""

doc = PyQuery(html)
li = doc(".item-0.active")
print(li)

li.remove_class("active")
print(li)

li.add_class("active")
print(li)

attr、text和html

python 复制代码 
from pyquery import PyQuery

html = """
<ul class="warp">
    <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
</ul>
"""

doc = PyQuery(html)

li = doc(".item-0.active")
print(li)

li.attr("name", "link")
print(li)

li.text("changed item")
print(li)

li.html("<span>changed item</span>")
print(li)

remove

python 复制代码 
from pyquery import PyQuery

html = """
<ul class="warp">
    ABC
    <p>abc<p>
</ul>
"""

doc = PyQuery(html)

li = doc(".item-0.active")
warp = doc(".warp")
warp.find("p").remove()
print(warp.text())

3.7 伪类选择器

python 复制代码 
from pyquery import PyQuery

html = """
<div class="wrap">
    <div id="container">
        <ul class="list">
            <li class="item-0">first item</li>
            <li class="item-1"><a href="link2.html">second item</a></li>
            <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
            <li class="item-1 active"><a href="link4.html">fourth item</a></li>
            <li class="item-0"><a href="link5.html">fifth item</a></li>
        </ul>
    </div>
</div>
"""

doc = PyQuery(html)

# 第一个li节点
li = doc("li:first-child")
print(li)

# 最后一个li节点
li = doc("li:last-child")
print(li)


# 第二个li节点
li = doc("li:nth-child(2)")
print(li)

# 下标大于2的节点
li = doc("li:gt(2)")
print(li)

# 以2为倍数位置的节点
li = doc("li:nth-child(2n)")
print(li)

# 包含second文本的节点
li = doc("li:contains(second)")
print(li)

4. parsel的使用

  • 可以接卸HTML和XML
  • 支持使用XPath和CSS选择器对内容进行提取和修改
  • 融合了正则表达式的提取功能

4.1 安装

python 复制代码 
pip3 install parsel

4.2 初始化

python 复制代码 
from parsel import Selector

html = """
<div>
    <ul>
        <li class="item-0">first item</li>
        <li class="item-1"><a href="link2.html">second item</a></li>
        <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
        <li class="item-1 active"><a href="link4.html">fourth item</a></li>
        <li class="item-0"><a href="link5.html">fifth item</a></li>
    </ul>
</div>
"""

selector = Selector(text=html)

items1 = selector.css(".item-0")
print(len(items1), type(items1), items1)

items2 = selector.xpath("//li[contains(@class, 'item-0')]")
print(len(items2), type(items2), items2)
  • .css()方法提取的结果是xpath属性而不是css属性
    • CSS选择器被转化成XPath
      • 由底层cssselect库实现
    • 真正用于节点提取的是XPath

4.3 提取文本

提取单个文本（get()）

  • 只能获取第一个匹配的对象
python 复制代码 
from parsel import Selector

html = """
<div>
    <ul>
        <li class="item-0">first item</li>
        <li class="item-1"><a href="link2.html">second item</a></li>
        <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
        <li class="item-1 active"><a href="link4.html">fourth item</a></li>
        <li class="item-0"><a href="link5.html">fifth item</a></li>
    </ul>
</div>
"""

selector = Selector(text=html)

items = selector.css(".item-0")
print(f"type of items: {type(items)}")
for item in items:
    print(f"type of item: {type(item)}")
    text = item.xpath(".//text()").get()
    print(text)

提取多个文本（getall()）

python 复制代码 
from parsel import Selector

html = """
<div>
    <ul>
        <li class="item-0">first item</li>
        <li class="item-1"><a href="link2.html">second item</a></li>
        <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
        <li class="item-1 active"><a href="link4.html">fourth item</a></li>
        <li class="item-0"><a href="link5.html">fifth item</a></li>
    </ul>
</div>
"""

selector = Selector(text=html)

result = selector.xpath("//li[contains(@class, \"item-0\")]//text()").getall()
print(result)

result = selector.css(".item-0 *::text").getall()
print(result)

4.4 提取属性

python 复制代码 
from parsel import Selector

html = """
<div>
    <ul>
        <li class="item-0">first item</li>
        <li class="item-1"><a href="link2.html">second item</a></li>
        <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
        <li class="item-1 active"><a href="link4.html">fourth item</a></li>
        <li class="item-0"><a href="link5.html">fifth item</a></li>
    </ul>
</div>
"""

selector = Selector(text=html)

result = selector.css(".item-0.active a::attr(href)").get()
print(result)

result = selector.xpath("//li[contains(@class, \"item-0\") and contains(@class, \"active\")]/a/@href").get()
print(result)

4.5 正则提取

python 复制代码 
from parsel import Selector

html = """
<div>
    <ul>
        <li class="item-0">first item</li>
        <li class="item-1"><a href="link2.html">second item</a></li>
        <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>
        <li class="item-1 active"><a href="link4.html">fourth item</a></li>
        <li class="item-0"><a href="link5.html">fifth item</a></li>
    </ul>
</div>
"""

selector = Selector(text=html)

result = selector.css(".item-0").re("link(.*?)\"")
print(result)

result = selector.css(".item-0 *::text").re(".*item")
print(result)

# 获取第一个符合
result = selector.css(".item-0").re_first(">(.*?item)")
print(result)
相关推荐
Logintern0914 分钟前
使用VS Code进行Python编程的一些快捷方式
开发语言·python
Multiple-ji25 分钟前
想学python进来看看把
开发语言·python
liuyuzhongcc1 小时前
List 接口中的 sort 和 forEach 方法
java·数据结构·python·list
鸟哥大大1 小时前
【Python】pypinyin-汉字拼音转换工具
python·自然语言处理
jiugie1 小时前
MongoDB学习
数据库·python·mongodb
阿尔法波2 小时前
python与pycharm如何设置文件夹为源代码根目录
开发语言·python·pycharm
xing25162 小时前
pytest下allure
开发语言·python·pytest
眸笑丶2 小时前
使用 Python 调用 Ollama API 并调用 deepseek-r1:8b 模型
开发语言·python
dexianshen2 小时前
配置mysql8.0使用PXC实现高可用
python
中国loong2 小时前
pandas连接mysql数据库
python
热门推荐
01DeepSeek各版本说明与优缺点分析02如何在WPS和Word/Excel中直接使用DeepSeek功能03DeepSeek本地部署详细指南04太炸裂了！清华大学deepseek从入门到精通使用手册又出第三版了，《普通人如何抓住DeepSeek红利》（无套路，直接下载）05本地部署DeepSeek教程（Mac版本）06DeepSeek r1本地安装全指南07DeepSeek R1本地化部署 Ollama + Chatbox 打造最强 AI 工具08本地化部署AI知识库：基于Ollama+DeepSeek+AnythingLLM保姆级教程09在Windows下安装Ollama并体验DeepSeek r1大模型10DeepSeek RAGFlow构建本地知识库系统