LeetCode 1212 查询球队积分(PostgreSQL)

数据准备

sql 复制代码
Create table If Not Exists Teams (team_id int, team_name varchar(30))
Create table If Not Exists Matches (match_id int, host_team int, guest_team int, host_goals int, guest_goals int)
Truncate table Teams
insert into Teams (team_id, team_name) values ('10', 'Leetcode FC')
insert into Teams (team_id, team_name) values ('20', 'NewYork FC')
insert into Teams (team_id, team_name) values ('30', 'Atlanta FC')
insert into Teams (team_id, team_name) values ('40', 'Chicago FC')
insert into Teams (team_id, team_name) values ('50', 'Toronto FC')
Truncate table Matches
insert into Matches (match_id, host_team, guest_team, host_goals, guest_goals) values ('1', '10', '20', '3', '0')
insert into Matches (match_id, host_team, guest_team, host_goals, guest_goals) values ('2', '30', '10', '2', '2')
insert into Matches (match_id, host_team, guest_team, host_goals, guest_goals) values ('3', '10', '50', '5', '1')
insert into Matches (match_id, host_team, guest_team, host_goals, guest_goals) values ('4', '20', '30', '1', '0')
insert into Matches (match_id, host_team, guest_team, host_goals, guest_goals) values ('5', '50', '30', '1', '0')

需求

如果球队赢了比赛(即比对手进更多的球),就得 3 分。

如果双方打成平手(即,与对方得分相同),则得 1 分。

如果球队输掉了比赛(例如,比对手少进球),就 不得分 。

写出一条SQL语句以查询每个队的 team_id,team_name 和 num_points。

输入


输出

1.查詢三種情況下的host_team,及其得分

sql 复制代码
select host_team ,
case 
	when host_goals > guest_goals then 3 
	when host_goals < guest_goals then 0
	else 1
end as team_goals
from matches;

2.查詢平局的guest_team及其得分

sql 复制代码
select guest_team , 1 as team_goals
from matches
where host_goals = guest_goals;

3.拼接兩種條件下的結果,創建臨時表,統計每個球隊總得分

sql 复制代码
with t1 as (
	select host_team ,
	case 
		when host_goals > guest_goals then 3 
		when host_goals < guest_goals then 0
		else 1
	end as team_goals
	from matches
	union all
	select guest_team , 1 as team_goals
	from matches
	where host_goals = guest_goals
),t2 as (
select host_team,sum(team_goals) goals_sum
from t1
group by host_team
)
select team_id,team_name,coalesce(goals_sum,0) as num_points
from teams left join t2
on teams.team_id =t2.host_team
order by num_points desc,team_id
;
相关推荐
TDengine (老段)5 小时前
TDengine 时间函数 WEEK 用户手册
大数据·数据库·物联网·时序数据库·iot·tdengine·涛思数据
小白程序员成长日记5 小时前
2025.11.29 力扣每日一题
数据结构·算法·leetcode
还是鼠鼠5 小时前
Redisson实现的分布式锁能解决主从一致性的问题吗?
java·数据库·redis·分布式·缓存·面试·redisson
DingYuan1016 小时前
MySql分类
数据库·mysql
在黎明的反思6 小时前
进程通信之消息队列(IPC)
算法
杨云龙UP6 小时前
SQL Server 备份异地同步 + 清理脚本
运维·服务器·数据库·sql·mysql·sqlserver
O***Z6166 小时前
Redis——Windows安装
数据库·windows·redis
老鱼说AI6 小时前
算法基础教学第一步:数据结构
数据结构·python·算法
0***h9426 小时前
MySQL 启动失败 (code=exited, status=1FAILURE) 异常解决方案
数据库·mysql