LeetCode 1212 查询球队积分(PostgreSQL)

数据准备

sql 复制代码
Create table If Not Exists Teams (team_id int, team_name varchar(30))
Create table If Not Exists Matches (match_id int, host_team int, guest_team int, host_goals int, guest_goals int)
Truncate table Teams
insert into Teams (team_id, team_name) values ('10', 'Leetcode FC')
insert into Teams (team_id, team_name) values ('20', 'NewYork FC')
insert into Teams (team_id, team_name) values ('30', 'Atlanta FC')
insert into Teams (team_id, team_name) values ('40', 'Chicago FC')
insert into Teams (team_id, team_name) values ('50', 'Toronto FC')
Truncate table Matches
insert into Matches (match_id, host_team, guest_team, host_goals, guest_goals) values ('1', '10', '20', '3', '0')
insert into Matches (match_id, host_team, guest_team, host_goals, guest_goals) values ('2', '30', '10', '2', '2')
insert into Matches (match_id, host_team, guest_team, host_goals, guest_goals) values ('3', '10', '50', '5', '1')
insert into Matches (match_id, host_team, guest_team, host_goals, guest_goals) values ('4', '20', '30', '1', '0')
insert into Matches (match_id, host_team, guest_team, host_goals, guest_goals) values ('5', '50', '30', '1', '0')

需求

如果球队赢了比赛(即比对手进更多的球),就得 3 分。

如果双方打成平手(即,与对方得分相同),则得 1 分。

如果球队输掉了比赛(例如,比对手少进球),就 不得分 。

写出一条SQL语句以查询每个队的 team_id,team_name 和 num_points。

输入


输出

1.查詢三種情況下的host_team,及其得分

sql 复制代码
select host_team ,
case 
	when host_goals > guest_goals then 3 
	when host_goals < guest_goals then 0
	else 1
end as team_goals
from matches;

2.查詢平局的guest_team及其得分

sql 复制代码
select guest_team , 1 as team_goals
from matches
where host_goals = guest_goals;

3.拼接兩種條件下的結果,創建臨時表,統計每個球隊總得分

sql 复制代码
with t1 as (
	select host_team ,
	case 
		when host_goals > guest_goals then 3 
		when host_goals < guest_goals then 0
		else 1
	end as team_goals
	from matches
	union all
	select guest_team , 1 as team_goals
	from matches
	where host_goals = guest_goals
),t2 as (
select host_team,sum(team_goals) goals_sum
from t1
group by host_team
)
select team_id,team_name,coalesce(goals_sum,0) as num_points
from teams left join t2
on teams.team_id =t2.host_team
order by num_points desc,team_id
;
相关推荐
夜天炫安全19 小时前
数据结构中所需的C语言基础
c语言·数据结构·算法
小陳参上20 小时前
用Python创建一个Discord聊天机器人
jvm·数据库·python
2301_7890156220 小时前
DS进阶:AVL树
开发语言·数据结构·c++·算法
changhong198621 小时前
如何在 Spring Boot 中配置数据库?
数据库·spring boot·后端
qyzm1 天前
天梯赛练习(3月13日)
开发语言·数据结构·python·算法·贪心算法
执笔画情ora1 天前
Postgresql数据库管理-pg_xact
数据库·postgresql·oracle
逆境不可逃1 天前
LeetCode 热题 100 之 64. 最小路径和 5. 最长回文子串 1143. 最长公共子序列 72. 编辑距离
算法·leetcode·动态规划
南棱笑笑生1 天前
20260310在瑞芯微原厂RK3576的Android14查看系统休眠时间
服务器·网络·数据库·rockchip
CoderCodingNo1 天前
【GESP】C++五级练习题 luogu-P1182 数列分段 Section II
开发语言·c++·算法
放下华子我只抽RuiKe51 天前
机器学习全景指南-直觉篇——基于距离的 K-近邻 (KNN) 算法
人工智能·gpt·算法·机器学习·语言模型·chatgpt·ai编程